# i nclude<stdio.h> *b<
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# i nclude<stdio.h> *)+K+J
# i nclude<math.h> eiiI Wr_7
#define PI 3.1415926 8SJi~gV
void ydgl(); zOV.cI6fZz
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; }ioHSkCD
int f; h[%t7qo=
main() :E$<!q
{ printf("Determaination the prime circle of cam\n"); $-tgd<2h
printf("----------------------------\n"); u0Nag=cU
printf( "input ro=");scanf("%f",&ro); Iuh1tcc
printf("input h=");scanf("%f",&h); 4 w$f-
printf("input e=");scanf("%f",&e); UK{6Rh ;
printf("input dt0=");scanf("%f",&dt0); dZSv=UY)
am=0;p=PI/180; R~=_,JUW
printf("The initial data:ro=%f\n",ro); 0N" VOEvG
printf("h=%f e=%f dt0=%f\n",h,e,dt0); nPAVrDg
O
do 9_~[
{ro=ro+5; >= G{.H
for(f=0;f<=dt0;f=f+2) -d|Q|zF^x
{d=PI*f/dt0; X4- _l$j
ydgl(); d[cqs9=\
} v>e%5[F
} O.ce"5Y^
while(am>30*p); C(RZ09,.S
printf("The intermediate results: am=%f\n",am/p); @raw8w\Zj+
printf("ro=%f\n",ro); {C% #r@6
do =th(Hdk17
{ro=ro-1; J\WUBt-M
if(ro<e) A,P_|
break; 6}Iu~|5
I UMt^z
for(f=0;f<=dt0;f=f+2) (JgW")M`cY
{d=PI*f/dt0; 4| 6<nk_
ydgl(); zc}qAy'<
} F|rJ{=x
} @xO?SjH
while((am>30*p)||(am<=29.5*p)); U\crp
T`
printf("The final results:max alfa=%f\n",am/p); >u6*P{;\
printf(" min ro=%f\n",ro); p "J^
getch(); RB\0o,mw4
} J ejDF*Q
void ydgl() H[cHF
{ d0=dt0*p; M;14s*g
s=0.5*h*(1-cos(d)); mKsTA;
ds=0.5*h*PI*sin(d)/d0; a!_vd B
r=sqrt(ro*ro-e*e); "*ot:;I
if((s+r)==0) *%{
return; HQpw2bdy
al=atan((ds-e)/(s+r)); )yHJc$OlMx
if(al>am) V_>)m3zsL
am=al; stb)Tl^
}