# i nclude<stdio.h> Ea*Jl<
# i nclude<stdio.h> V<!E9/4rS
# i nclude<math.h> ~FV
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#define PI 3.1415926 0TI+6u
void ydgl(); P1
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float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; VFMg$qv|_
int f; ou@ P#:<B
main() o5FBqt
{ printf("Determaination the prime circle of cam\n"); 8BZDaiE"
printf("----------------------------\n"); LJMw-#61sj
printf( "input ro=");scanf("%f",&ro); xe6 2gaT
printf("input h=");scanf("%f",&h); GxGZxf*(
printf("input e=");scanf("%f",&e); ukSi9| 1-,
printf("input dt0=");scanf("%f",&dt0); )LwB
am=0;p=PI/180; xCV3HnZ
printf("The initial data:ro=%f\n",ro); f13%[RA9N
printf("h=%f e=%f dt0=%f\n",h,e,dt0); i=<N4Vx
do h&vq}
{ro=ro+5; l~M86 h
for(f=0;f<=dt0;f=f+2) ,wlh0;,
{d=PI*f/dt0; pr[[)[]/
ydgl(); Ui46p
} F3b[L^Km]
} )*iSN*T8q
while(am>30*p); NTVdSK7z~H
printf("The intermediate results: am=%f\n",am/p); h30~2]hH
printf("ro=%f\n",ro); '7{0k{
do >i4UU0m
{ro=ro-1; -_ [Z5%B
if(ro<e) $vdGkz@6
break; HzT"{N9
QO)Q%K,
for(f=0;f<=dt0;f=f+2) fO.gfHI
{d=PI*f/dt0; lfKrd3KS_
ydgl(); 6;GL>))'
} !_cT_
WHty
} cV5Lp4wY?
while((am>30*p)||(am<=29.5*p)); t\]CdH`+
printf("The final results:max alfa=%f\n",am/p); o=2y`Eq
printf(" min ro=%f\n",ro); xgt dmv%
getch(); Tp`by
1s
} %
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void ydgl() %9=^#e+pE
{ d0=dt0*p; ;#!`cgAh
s=0.5*h*(1-cos(d)); G)?O!(_
ds=0.5*h*PI*sin(d)/d0; F#Oqa^$(
r=sqrt(ro*ro-e*e); !+T+BFw.
if((s+r)==0) k"V3FXC)
return; b'^-$
al=atan((ds-e)/(s+r)); JF_\A)<ki
if(al>am) fdN-Zq@'
am=al; t.>vLzrU
}