# i nclude<stdio.h> :IDD(<^9
# i nclude<stdio.h> 2@ vSe
# i nclude<math.h> +HNY!fv9
#define PI 3.1415926 f^il|Obzl
void ydgl(); ]YQ[ )
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; ''S*B|:
int f; J
>Zd0Dn
main() v;"[1w}
{ printf("Determaination the prime circle of cam\n"); {s!DRc]ln
printf("----------------------------\n"); bFk >IifN
printf( "input ro=");scanf("%f",&ro); g#qt<d}j
printf("input h=");scanf("%f",&h); O,6Upk
printf("input e=");scanf("%f",&e); "M5P-l$p}
printf("input dt0=");scanf("%f",&dt0); Ub=g<MYHV
am=0;p=PI/180; b[,J-/;JNL
printf("The initial data:ro=%f\n",ro); :RR<-N5+
printf("h=%f e=%f dt0=%f\n",h,e,dt0); _#xS1sD
do [<P(S~J
{ro=ro+5; S'qEBz
for(f=0;f<=dt0;f=f+2) T{v(B["!$
{d=PI*f/dt0; |r5 n p
ydgl(); uTGd{w@]0|
} }yZ9pTB.?E
}
%[0V>
while(am>30*p); @ qWgokf
printf("The intermediate results: am=%f\n",am/p); FI++A`
printf("ro=%f\n",ro); 3a #2 }
do +@[T0cXp
{ro=ro-1; ?#"rI6
if(ro<e) VAf"B5R
break; j+AAhn
tZmo= 3+:
for(f=0;f<=dt0;f=f+2) "mc/fp
{d=PI*f/dt0; y?j#;n 0
ydgl(); J'9hzag
} ~ *RG|4#
} j*@^O`^v
while((am>30*p)||(am<=29.5*p)); $j*%}x~[
printf("The final results:max alfa=%f\n",am/p); xayo{l=uGv
printf(" min ro=%f\n",ro); XB*)d
9'8
getch(); Cmg(#$X
} 8px@sXI*`
void ydgl() dC8$Ql^<
{ d0=dt0*p; QPf*!E
s=0.5*h*(1-cos(d)); ||3%REliC
ds=0.5*h*PI*sin(d)/d0; )8]O|Z-CU
r=sqrt(ro*ro-e*e); f*KNt_|:
if((s+r)==0) K|nh`r
return; I$!rNfrs
al=atan((ds-e)/(s+r)); `Yn:fL7S
if(al>am) KdIX`
am=al; _7r<RZ
}