# i nclude<stdio.h> n?y 'c^
# i nclude<stdio.h> T$: >*
# i nclude<math.h> Wr] O
#define PI 3.1415926 5 ."5IjZu
void ydgl(); ?F!EB4E\y}
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; P#AAOSlLV
int f; \BN|?r$a
main() ~Y\QGuT
{ printf("Determaination the prime circle of cam\n"); k%{ l4
printf("----------------------------\n"); w@87]/ 4Rq
printf( "input ro=");scanf("%f",&ro); m, \i
printf("input h=");scanf("%f",&h); /uK)rG
F
printf("input e=");scanf("%f",&e); zl0;84:H
printf("input dt0=");scanf("%f",&dt0); ;l$9gD>R
am=0;p=PI/180; *6NO-T; -
printf("The initial data:ro=%f\n",ro); VT'0DQ!NIq
printf("h=%f e=%f dt0=%f\n",h,e,dt0); 4O$ m R
do Z+Kv+GmqH
{ro=ro+5; $8jaapNm@
for(f=0;f<=dt0;f=f+2) lo"j )Zt
{d=PI*f/dt0; 6_W <hevI
ydgl(); \|v `l{
} {d| |q<.-
} J
cP~-cp
while(am>30*p); YKc>6)j
printf("The intermediate results: am=%f\n",am/p); nHrP>zN
printf("ro=%f\n",ro); 1#/6r :
do I!61 K
{ro=ro-1; ,o BlJvm
if(ro<e) PoJmW^:}
break; U ?^OD
;?0_Q3IML
for(f=0;f<=dt0;f=f+2) L {!ihJr
{d=PI*f/dt0; p`\3if'
ydgl(); 9H>BWjS
} s\6N }[s
} FH4u$ g+
while((am>30*p)||(am<=29.5*p)); Ft3I>=f{
printf("The final results:max alfa=%f\n",am/p); }I\-HP8!gv
printf(" min ro=%f\n",ro); 3QIdN
getch(); P= e4lF.
} yDzdE;
void ydgl() %Nl`~Kz9U
{ d0=dt0*p; Jth=. 9mrM
s=0.5*h*(1-cos(d)); :]yg
ds=0.5*h*PI*sin(d)/d0; Jff 79)f
r=sqrt(ro*ro-e*e); ;8BA~ ,4l
if((s+r)==0) Hc M~
return; `n6/ A)
al=atan((ds-e)/(s+r)); 9WOu8Ia
if(al>am) s\ _l=v3
am=al; !z?0 :Jg
}
