# i nclude<stdio.h> 5V5w:U>_z
# i nclude<stdio.h> U[\Vj_?(I
# i nclude<math.h> 8P: spD0
#define PI 3.1415926 uGVy6,
void ydgl(); QP(BZJC
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; 9A$m$
int f; k%81f'H
main() QlZ@ To
{ printf("Determaination the prime circle of cam\n"); u{e-G&]^;
printf("----------------------------\n"); :d,^I@]
printf( "input ro=");scanf("%f",&ro); $l[Rh1z`;+
printf("input h=");scanf("%f",&h); UKBJ_r
printf("input e=");scanf("%f",&e); ~Y!kB:D5;~
printf("input dt0=");scanf("%f",&dt0); 04@cLDX8uB
am=0;p=PI/180; nsuX*C7
printf("The initial data:ro=%f\n",ro); TnH\O$
printf("h=%f e=%f dt0=%f\n",h,e,dt0); nt
:N!suP3
do 3iX?~
{ro=ro+5; CA s>AXbs
for(f=0;f<=dt0;f=f+2) h2q/mi5{
{d=PI*f/dt0; Y%aWK~O
ydgl(); F"jt&9jg
} KY9n2u&4
} 8y2+$
while(am>30*p); (p)!Mq
"^
printf("The intermediate results: am=%f\n",am/p); \XzM^K3
printf("ro=%f\n",ro); X$n(-65
do $'wq1u
{ro=ro-1; i@P}{
if(ro<e) @%ECj)u`O
break; q6d~V]4:
g=8un`]7
for(f=0;f<=dt0;f=f+2) P:xT0gtt
{d=PI*f/dt0; D-p.kA3MJ
ydgl(); Ctu?o+^;z
} 7<\C?`q"
} B4H!5b
while((am>30*p)||(am<=29.5*p)); nHXX\i
printf("The final results:max alfa=%f\n",am/p); Ri7((x]H"
printf(" min ro=%f\n",ro); GZ #aj|
getch(); Sv[ 5NZn0&
} ]+Ixi o
void ydgl() I:j3sy
{ d0=dt0*p; (R}ii}&
s=0.5*h*(1-cos(d)); R{hf9R ,
ds=0.5*h*PI*sin(d)/d0; XP?rOOn
r=sqrt(ro*ro-e*e); r7mD{0s*
if((s+r)==0) qL
/7^)(
return; H*I4xT@
al=atan((ds-e)/(s+r)); 2[yBD-":
if(al>am) Am4lEvb
am=al; %eWqQ3{P]
}