# i nclude<stdio.h> 1jF`5k
# i nclude<stdio.h> ~15N7=wCM
# i nclude<math.h> Y*vW!yu
#define PI 3.1415926 7*Ej. HK
void ydgl(); *5^Q7``
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; b7p@Dn?E
int f; LB a[:j2
main() ?qWfup\S
{ printf("Determaination the prime circle of cam\n"); = < oBgD0k
printf("----------------------------\n"); ZP\-T*)l$
printf( "input ro=");scanf("%f",&ro); #kaY0M
printf("input h=");scanf("%f",&h); OD6\Mr2=
printf("input e=");scanf("%f",&e); lUvpszH=
printf("input dt0=");scanf("%f",&dt0); U5.LDv;
am=0;p=PI/180; 6U R2IxbE
printf("The initial data:ro=%f\n",ro); Gf<'WQ[
printf("h=%f e=%f dt0=%f\n",h,e,dt0); ?1K#dC52#
do m4l&
eEp
{ro=ro+5; ''\Ov
for(f=0;f<=dt0;f=f+2) PC-"gi=h
{d=PI*f/dt0; ([m
mPyp>L
ydgl(); O4V.11FnW
} ne_TIwf w-
} f m)pulz
while(am>30*p); O#S;q5L@
printf("The intermediate results: am=%f\n",am/p); /! "|_W|n
printf("ro=%f\n",ro); qfMo7e@6*
do G#u6Am)T
{ro=ro-1; +>{Y.`a;Jo
if(ro<e) h1B16)
break; AN/;)wc
c_'OPJ
for(f=0;f<=dt0;f=f+2) 2;DuHO1
{d=PI*f/dt0; C8V/UbA
/
ydgl(); |6K+E6H
} @c;|G$E@3
} #0P$M!%
while((am>30*p)||(am<=29.5*p)); YW( Qmo7
printf("The final results:max alfa=%f\n",am/p); iiS-9>]/
printf(" min ro=%f\n",ro); &)AVzN+*h
getch(); rLI8pA|.
} lE&&_INHQ
void ydgl() 6sx'S?Qa*
{ d0=dt0*p; d\R,Q
s=0.5*h*(1-cos(d)); I uMQ9&
ds=0.5*h*PI*sin(d)/d0; !y@NAa0
r=sqrt(ro*ro-e*e); 06c>$1-?
if((s+r)==0) j/f?"VEr
return; ?&63#B,iZ
al=atan((ds-e)/(s+r)); j/_s"}m{
if(al>am) y)W@{@{kl
am=al; Of[XKFn_
}