# i nclude<stdio.h> TJ)Nr*U3_
# i nclude<stdio.h> 2tU3p<[
# i nclude<math.h> MdX4Rp'
#define PI 3.1415926 6I[*p0j5
void ydgl(); =u0=)\0@r
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; Wv>`x?W
int f; I/'>MDB!
main() +s}!+I8P
{ printf("Determaination the prime circle of cam\n"); {F_>cyR
printf("----------------------------\n"); $7X;FmlG&
printf( "input ro=");scanf("%f",&ro); /5%'q~
printf("input h=");scanf("%f",&h); '4{@F~fu
printf("input e=");scanf("%f",&e); /{({f?k<\/
printf("input dt0=");scanf("%f",&dt0); oD%n}
am=0;p=PI/180; NO/$}vw
printf("The initial data:ro=%f\n",ro); C,,T7(: k
printf("h=%f e=%f dt0=%f\n",h,e,dt0); ?Gf'G{^}
do :qS~"@ ?<
{ro=ro+5; bLTX_
R
for(f=0;f<=dt0;f=f+2) +:m)BLA4l
{d=PI*f/dt0; H#F"n"~$
ydgl(); "P.sKhuo
} *7*_QW%?A
} E.yFCaL
while(am>30*p); tL&_@PD)3
printf("The intermediate results: am=%f\n",am/p); U>IsmF>m
printf("ro=%f\n",ro); #WA7}tHb
do OL=X&Vaf<
{ro=ro-1; kFJ]F |^7
if(ro<e) };2Lrz9<
break; {\?f|mmq
&=zJ MGa
for(f=0;f<=dt0;f=f+2) %AV3eqghCg
{d=PI*f/dt0; 5i$P$ R
ydgl(); uUl ;}W
} ldG8hK
} *{JD=ua
while((am>30*p)||(am<=29.5*p)); b`wT*&
printf("The final results:max alfa=%f\n",am/p); FpttH?^
printf(" min ro=%f\n",ro); %jUZc:06
getch(); GDj_+G;tO\
} ;8F6a:\v
void ydgl() m:EYOe,w
{ d0=dt0*p; -8:O?]+Q/
s=0.5*h*(1-cos(d)); 7|Qb}[s
ds=0.5*h*PI*sin(d)/d0; b6 g9!
r=sqrt(ro*ro-e*e); u 'ng'j'
if((s+r)==0) Q0PqyobD
return; q9zeN:><
al=atan((ds-e)/(s+r)); 9(&$Gwi
if(al>am) cB;DB)0P
am=al; ^wIP`dn
}