# i nclude<stdio.h> &0[L2x}7
# i nclude<stdio.h> 2`;XcY4A
# i nclude<math.h> Q3=5q w^
#define PI 3.1415926 H[s+.&^
void ydgl(); l,Y5VGiH#
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; R0#scr
int f; R!/JZ@au<
main() h*JN0O<b
{ printf("Determaination the prime circle of cam\n"); />I5,D'h
printf("----------------------------\n"); bWb/>hI8
Q
printf( "input ro=");scanf("%f",&ro); j+-`P5
printf("input h=");scanf("%f",&h); Wz R)R9x]
printf("input e=");scanf("%f",&e); v4E=)?
printf("input dt0=");scanf("%f",&dt0); cs\=8_5
am=0;p=PI/180; oI`Mn3N
printf("The initial data:ro=%f\n",ro); YWd2bRb
printf("h=%f e=%f dt0=%f\n",h,e,dt0); F[O147&C
do "]p&7
{ro=ro+5; kR^">s/H#
for(f=0;f<=dt0;f=f+2) 0e#PN@
{d=PI*f/dt0; HH6H4K3Zj
ydgl(); ?&,6Y'"
} k0PwAt)65
} $$0<
&
while(am>30*p); wDoCc:
printf("The intermediate results: am=%f\n",am/p); ]<YS7.pT
printf("ro=%f\n",ro); _8K8Ai-~.>
do 8r[TM
{ro=ro-1; aw lq/
if(ro<e) [];wP'*
break; ,%x2SyA
%nq<nfDT
for(f=0;f<=dt0;f=f+2) ,Js_d
{d=PI*f/dt0; %YF
/=l
ydgl(); s/J7z$NEU
} (DvGA I
} I+kL;YdS
while((am>30*p)||(am<=29.5*p)); 3j$,L(
printf("The final results:max alfa=%f\n",am/p); 2<n18-|OQ
printf(" min ro=%f\n",ro); "8zMe L
getch(); Jn|<G
} *wmkcifF;
void ydgl() Cpd>xXZz&S
{ d0=dt0*p; yr>J^Et%_
s=0.5*h*(1-cos(d));
E>*b,^J7g
ds=0.5*h*PI*sin(d)/d0; `g(#~0R
r=sqrt(ro*ro-e*e); <bCB-lG*Kb
if((s+r)==0) CiHx.5TiC
return; =&"pG`x
al=atan((ds-e)/(s+r)); $(0<T<\
if(al>am) @|ZUyat
am=al; !E00I0W-h
}