# i nclude<stdio.h> zWhzU|=8
# i nclude<stdio.h> h+cOOm-)
# i nclude<math.h> Y(ClG*6 ++
#define PI 3.1415926 ^)$T`
void ydgl(); R!\._m?\h
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; (Hmh b}H
int f; hh.`Yu L
main() bGwj` lue
{ printf("Determaination the prime circle of cam\n"); mZ3Z8q}%P
printf("----------------------------\n"); 5-'Z.[ImB?
printf( "input ro=");scanf("%f",&ro); OMab!
printf("input h=");scanf("%f",&h); V=PK)FJ
printf("input e=");scanf("%f",&e); N
;n55N
printf("input dt0=");scanf("%f",&dt0); %+;am Rb
am=0;p=PI/180; 41rS0QAM
printf("The initial data:ro=%f\n",ro); =NPo<^Lae
printf("h=%f e=%f dt0=%f\n",h,e,dt0); NID2$ p
do {n<1uh9~$8
{ro=ro+5; |h((SreO
for(f=0;f<=dt0;f=f+2) $z5C+K@
{d=PI*f/dt0; MQy,[y7I
ydgl(); b=L|GV@$
} /"R{1
} =~dXP
while(am>30*p); fq):'E)
printf("The intermediate results: am=%f\n",am/p); 4s <ZKU
printf("ro=%f\n",ro); 3XUsw1,[
do N~(?g7
{ro=ro-1; /$FpceB!W
if(ro<e) ; H]]H!
break; 5fp&!HnG
<){J|O
for(f=0;f<=dt0;f=f+2) Oe k$f,J-
{d=PI*f/dt0; aLQ]2m
ydgl(); !;Ctz'wz
} @ "CP@^
} t-]~^s
while((am>30*p)||(am<=29.5*p)); N'21I$ D
printf("The final results:max alfa=%f\n",am/p); ag!q:6&
printf(" min ro=%f\n",ro); ,twm)%caU
getch(); Z22#lF\ N
} _M- PF$
void ydgl() }\W^$e-
{ d0=dt0*p; o'YK\L!p
s=0.5*h*(1-cos(d)); Dd)L~`k{)
ds=0.5*h*PI*sin(d)/d0; edlsS}8^
r=sqrt(ro*ro-e*e); ZM57(D
if((s+r)==0) T@r%~z
return; 'W~6-c9y
al=atan((ds-e)/(s+r)); @4]dv> Z
if(al>am) /86PqKU(P
am=al; 9tCF m.m
}