# i nclude<stdio.h> ~e)`D nJ
# i nclude<stdio.h> )|` # BC
# i nclude<math.h> ?_+h+{/@B
#define PI 3.1415926 #CaT 0#v
void ydgl(); kZsat4 r
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; { J}Zv5
int f; u{-J?t&`
main() =[ $zR>o*%
{ printf("Determaination the prime circle of cam\n"); ?5> Ep:{+/
printf("----------------------------\n"); {' QA0K
printf( "input ro=");scanf("%f",&ro); U6pG
printf("input h=");scanf("%f",&h); 1gZ W~6a}
printf("input e=");scanf("%f",&e); m'Thm{Y,?n
printf("input dt0=");scanf("%f",&dt0); ^nS'3g^"
am=0;p=PI/180; O'G,
printf("The initial data:ro=%f\n",ro); $g?`yE(K
printf("h=%f e=%f dt0=%f\n",h,e,dt0); Yzr|Z7r q}
do Zu$30&U
{ro=ro+5; 'WA]DlO
for(f=0;f<=dt0;f=f+2) Q0}Sju+HX
{d=PI*f/dt0; B tZycI
ydgl(); 2[Ja|W\If
} "s6O|=^*
} % e@Jc 3
while(am>30*p); sK kk+-J4
printf("The intermediate results: am=%f\n",am/p); ?G#T6$E8
printf("ro=%f\n",ro); m ),3J4(q
do E_aDkNT
{ro=ro-1; A7;|~??
if(ro<e) ^E5[~C*o3
break; Z5vpo$l
} h.]sF
for(f=0;f<=dt0;f=f+2) Rr#vv
{d=PI*f/dt0; DKjkO5R\
ydgl(); l ~/g^lN
} -qPYm ?$
} ~t $zypw
while((am>30*p)||(am<=29.5*p)); hY?x14m$3
printf("The final results:max alfa=%f\n",am/p); c&+p{hH+
printf(" min ro=%f\n",ro); kc3dWWPe
getch(); Y+k)d^6r
} k-v@sb24_
void ydgl() H'L ~8>
{ d0=dt0*p; O~r.sJ}
s=0.5*h*(1-cos(d)); QT5,_+ho
ds=0.5*h*PI*sin(d)/d0; @q?zh'@;
r=sqrt(ro*ro-e*e); Btmv{'T_y@
if((s+r)==0) `g;`yJX<
return; .H, wdzg)
al=atan((ds-e)/(s+r)); ]"3(UKx
if(al>am) e7j3 0Iy
am=al; FQbF)K~e
}
