# i nclude<stdio.h> r9b`3yr=
# i nclude<stdio.h> ^QYI`u` 4
# i nclude<math.h> uVp R^
#define PI 3.1415926 <a$cB+t
void ydgl(); jg%D
G2
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; N3x}YHFF
int f; 0&5}[9?V'
main() 'JkK0a2D
{ printf("Determaination the prime circle of cam\n"); d%]7:
printf("----------------------------\n"); I"DV}jg6|
printf( "input ro=");scanf("%f",&ro); b~#rUOXb8?
printf("input h=");scanf("%f",&h); -09<; U
printf("input e=");scanf("%f",&e); Q FX|ZsmK
printf("input dt0=");scanf("%f",&dt0); !knYD}Rxd
am=0;p=PI/180; $f)Y
!<bC
printf("The initial data:ro=%f\n",ro); aP"i_!\.aa
printf("h=%f e=%f dt0=%f\n",h,e,dt0); ]0`[L<_r
do \OY2|
{ro=ro+5; nG8]c9\Q#
for(f=0;f<=dt0;f=f+2) kkzXv`+
{d=PI*f/dt0; FEdyh?$
ydgl(); d]@9kG
} $1?YVA7
} E)Hp.
while(am>30*p); F,lQj7
printf("The intermediate results: am=%f\n",am/p); j?.VJ^Ff/u
printf("ro=%f\n",ro); y<;#*wB
do }*BY!5
{ro=ro-1; nk-?$'i9q
if(ro<e) :!r_dmJ
break; A#8/:t1AW
=)y=M!T2
for(f=0;f<=dt0;f=f+2) =Wl
CE_
{d=PI*f/dt0; z6Mf>q
ydgl(); JFZZ-t;*
} M
rVtxzH
} F]~`57
while((am>30*p)||(am<=29.5*p)); ?;i6eg17<
printf("The final results:max alfa=%f\n",am/p); !hJKI.XH
printf(" min ro=%f\n",ro); ap=M$9L'
getch(); szKs9er&
} q@^=im
void ydgl() xpSMbX{e
{ d0=dt0*p; W=G[hT5L{
s=0.5*h*(1-cos(d)); 6lZhV[~Z/
ds=0.5*h*PI*sin(d)/d0; o#6j+fo!n
r=sqrt(ro*ro-e*e); IS8ppu&E
if((s+r)==0) ea B-u
return; P/ug'
al=atan((ds-e)/(s+r)); /Wzic+v<>
if(al>am) FTk!Mn88
am=al; ;=_KLG <
}