# i nclude<stdio.h> i <bFF03*S
# i nclude<stdio.h> mV`Z]-$$i
# i nclude<math.h> 6peO9]Zy
#define PI 3.1415926 `8xe2=Ub
void ydgl(); ?*4&Z.~J
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; :5U(}\dL{
int f; n|SsV
main() V`S6cmwdc\
{ printf("Determaination the prime circle of cam\n"); !7AW_l9`i
printf("----------------------------\n"); M `Y~IG}
printf( "input ro=");scanf("%f",&ro);
@5acTYQ
printf("input h=");scanf("%f",&h); DD"]as"#
printf("input e=");scanf("%f",&e); /ta-jOcRH&
printf("input dt0=");scanf("%f",&dt0); hP`3Ao
am=0;p=PI/180; b&HA_G4
printf("The initial data:ro=%f\n",ro); 1xL2f&bG
printf("h=%f e=%f dt0=%f\n",h,e,dt0); 8$OE<c?#5n
do [% |i
{ro=ro+5; i?qS8h{
for(f=0;f<=dt0;f=f+2) Rw^4S@~T
{d=PI*f/dt0; #kA/,qyM
ydgl(); s7(mNpo
} =6ZZ/+6b
} vs7Hg)F
while(am>30*p); 9N5&N3
printf("The intermediate results: am=%f\n",am/p); asj^K|.z
printf("ro=%f\n",ro); b0PF7PEEQ
do a&.8*|w3
{ro=ro-1; 4@/[aFH
if(ro<e) BNQ~O^R0
break; ^Ml)g=Fq
Rl.3p<sX
for(f=0;f<=dt0;f=f+2) xo6-Y=c8
{d=PI*f/dt0; S,n*1&ogj
ydgl(); qI^6}PB
} %^2LTK(P
} *]W{83rXQ
while((am>30*p)||(am<=29.5*p)); lyF~E
printf("The final results:max alfa=%f\n",am/p); #J)sz,)(
printf(" min ro=%f\n",ro); TW{.qed8^
getch(); ~>k<I:BtrT
} &h`s:Y
void ydgl() c,!Ijn\;(
{ d0=dt0*p; zy
s=0.5*h*(1-cos(d)); s34{\/'D+
ds=0.5*h*PI*sin(d)/d0; CS:j->
r=sqrt(ro*ro-e*e); x: `oqbd
if((s+r)==0) 9=ns.r
return; C6M|A3^T
al=atan((ds-e)/(s+r)); pzg|?U
if(al>am) (6^v`SZ
am=al; Owo2DsT t
}