# i nclude<stdio.h> R80|q#h,]
# i nclude<stdio.h> .li)k[] ts
# i nclude<math.h> g26 l:1P
#define PI 3.1415926 -ilhC Y@M
void ydgl(); z,VXH ?.Zo
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; QEmktc1 7
int f; IEfm>N-]
main() 3[~LmA
{ printf("Determaination the prime circle of cam\n"); ;]rj Kc=
printf("----------------------------\n"); <FN+
printf( "input ro=");scanf("%f",&ro); 6O@Lx]t
printf("input h=");scanf("%f",&h); 8"u.GL.
printf("input e=");scanf("%f",&e); 4dh>B>Q
printf("input dt0=");scanf("%f",&dt0); {4%ddJn[.)
am=0;p=PI/180; ~fO#En
printf("The initial data:ro=%f\n",ro); &d"scM5
printf("h=%f e=%f dt0=%f\n",h,e,dt0); :rvBx"
do TdoH((nY
{ro=ro+5; E,4*a5Fi
for(f=0;f<=dt0;f=f+2) I."s&]FZ
{d=PI*f/dt0; \;"S>dg
ydgl(); T$V8n_;
} ![Vrbe P
} qtP*O#1q
while(am>30*p); 4@-Wp]
printf("The intermediate results: am=%f\n",am/p); (c[DQS j
printf("ro=%f\n",ro); kioIyV\=
do @*$"6!3s5
{ro=ro-1; #;"lBqxY`
if(ro<e) `Cu9y+t
break; r&XxF>
>Q)S-4iR
for(f=0;f<=dt0;f=f+2) ;!m_RQPFF
{d=PI*f/dt0; TQ5kT?/{
ydgl(); e"2x!(&n(
} nYK!'x$
} vLCm,Bb2L
while((am>30*p)||(am<=29.5*p)); YDEb MEMd/
printf("The final results:max alfa=%f\n",am/p); t9_&n.z
printf(" min ro=%f\n",ro); tTJ$tx
getch(); "2I{T
} =1mIk0H`
void ydgl() };cH5bYF
{ d0=dt0*p; #;'*W$Wk2
s=0.5*h*(1-cos(d)); n$"BF\eM
ds=0.5*h*PI*sin(d)/d0; B{1yMJA
r=sqrt(ro*ro-e*e);
<XnxAA
if((s+r)==0) o1Wf#Zq
return; V_)465g
al=atan((ds-e)/(s+r)); j*_#{niy:
if(al>am) m9Dg%\B
am=al; <|:$_&(
}