# i nclude<stdio.h> BO[A1'>
# i nclude<stdio.h>
"= UP&=
# i nclude<math.h> {'}Ofj
#define PI 3.1415926 &=7ur
void ydgl(); ;hZ(20
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; +zw<iB)J
int f; 4< H-ol
main() XM=`(e
o
{ printf("Determaination the prime circle of cam\n"); 8;Pdd1GyUL
printf("----------------------------\n"); `o*eL Lk
printf( "input ro=");scanf("%f",&ro); ]kKsGch
printf("input h=");scanf("%f",&h); ' Uc|[l]
printf("input e=");scanf("%f",&e); z&t6,0q`5
printf("input dt0=");scanf("%f",&dt0); d5],O48A
am=0;p=PI/180; {9=U6m^R2
printf("The initial data:ro=%f\n",ro); [Q$"+@jw
printf("h=%f e=%f dt0=%f\n",h,e,dt0); je{5iIr3/
do j5HOdy2
{ro=ro+5; *yX_dgC>[
for(f=0;f<=dt0;f=f+2) h\ybh
{d=PI*f/dt0; sP&E{{<QTF
ydgl(); 43VuH
} IM@Qe|5
} HL!-4kN
<$
while(am>30*p); \o3i9Q9C
printf("The intermediate results: am=%f\n",am/p); I7Eg$J&
printf("ro=%f\n",ro); HmiwpI
do k&?QeXW
{ro=ro-1; nv8,O=#s
if(ro<e) }Jtaq[y\r
break; oC?b]tzj
1ii.nt1u
for(f=0;f<=dt0;f=f+2) i &KbzOY
{d=PI*f/dt0; =kCpCpET
ydgl(); mee-Qq:}
} n/8fv~zU
} [+%*s3`c#
while((am>30*p)||(am<=29.5*p)); ~/.&Z`ls
printf("The final results:max alfa=%f\n",am/p); Y{S/A *X
printf(" min ro=%f\n",ro); i4-L!<bJ
getch(); =o-qu^T^u
} >/n/n{{
void ydgl() Vw#07P#A
{ d0=dt0*p; @z,'IW74V
s=0.5*h*(1-cos(d)); kOc'@;_O
ds=0.5*h*PI*sin(d)/d0; '-~86Q
r=sqrt(ro*ro-e*e); MdKZH\z/
if((s+r)==0) IaJ(T>"+
return; TRiB|b]8Q#
al=atan((ds-e)/(s+r)); 0I&rZMpF&
if(al>am) M6I1`Lpf
am=al; K~E]Fkw!;
}