# i nclude<stdio.h> 5:l*Ib:s7
# i nclude<stdio.h> &ppE|[{
# i nclude<math.h> `rz`3:ZH
#define PI 3.1415926 h/1nm U]
void ydgl(); m]0^
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; Siz!/O!'
int f; kMl @v`
main() +EST58
{ printf("Determaination the prime circle of cam\n"); ' 1P=^
printf("----------------------------\n"); ,5eH2W
printf( "input ro=");scanf("%f",&ro); t,=@hs
hN
printf("input h=");scanf("%f",&h); 4-]Do?
printf("input e=");scanf("%f",&e); *R_'$+
printf("input dt0=");scanf("%f",&dt0); *Z]5!$UpC
am=0;p=PI/180; FXOT+9bg
printf("The initial data:ro=%f\n",ro); 4f4 i1i:
printf("h=%f e=%f dt0=%f\n",h,e,dt0); I~p8#<4#b
do 9n>$}UI\
{ro=ro+5; T6h;Y
for(f=0;f<=dt0;f=f+2) t$]&,ucW#
{d=PI*f/dt0; `ICcaRIN8I
ydgl(); lFp!XZ!
} ASzzBR;?_
} CB*`
while(am>30*p); /S7+B]
printf("The intermediate results: am=%f\n",am/p); [cGt
printf("ro=%f\n",ro); ~K5Cr
do vp\PYg;x
{ro=ro-1; *[d~Nk%Y$
if(ro<e) F=oHl@
break; .k# N7[q=
nB cp7e
for(f=0;f<=dt0;f=f+2) a.
h?4+^bN
{d=PI*f/dt0; 0Jm]f/iZ
ydgl(); 6QN1+MwB
} QD$}-D[
} Cz'xGW{
while((am>30*p)||(am<=29.5*p)); <@u0.-]
printf("The final results:max alfa=%f\n",am/p); /]ku$.mr\
printf(" min ro=%f\n",ro); eaV3)uP
getch(); %B#hb<7}
} 6#E]zmXO2
void ydgl() -Bo86t)F
{ d0=dt0*p; ^G}# jg.
s=0.5*h*(1-cos(d)); Bz~ -2#l
ds=0.5*h*PI*sin(d)/d0; !"g=&Uy&
r=sqrt(ro*ro-e*e); .cw!ls7d
if((s+r)==0) !2GHJHxv]c
return; KK:N [x
al=atan((ds-e)/(s+r)); Q,zC_
if(al>am) ' 2>l
am=al; >?S\~Y
}