# i nclude<stdio.h> qvN"1=nJ
# i nclude<stdio.h> EP0a1 .C
# i nclude<math.h> \P?--AI q<
#define PI 3.1415926 Fo LDMx(
void ydgl(); h&$P y
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; Bn_g-WrT
int f; JilKZQmk
main() &z QW Iv
{ printf("Determaination the prime circle of cam\n"); 9/Wn!Ld
printf("----------------------------\n"); +Wd L
printf( "input ro=");scanf("%f",&ro); * 2%oZX F
printf("input h=");scanf("%f",&h); q06@SD$
printf("input e=");scanf("%f",&e); .> ,Z k S
printf("input dt0=");scanf("%f",&dt0); 8'% +G
am=0;p=PI/180; :1NYpsd.i
printf("The initial data:ro=%f\n",ro); [[$Mh_MD
printf("h=%f e=%f dt0=%f\n",h,e,dt0); >E~~7Yal
do .Map
{ro=ro+5; E]?2!)mgce
for(f=0;f<=dt0;f=f+2) VHj*aBHB
{d=PI*f/dt0; 5 Af?Yxv
ydgl(); {~"Em'}J
} LiF. w:}
} !&6-(q9
while(am>30*p); ^:U;rHY
printf("The intermediate results: am=%f\n",am/p); b2W; |
printf("ro=%f\n",ro); "| \94
do qWkx:-g]
{ro=ro-1; CCy .
if(ro<e) lvG3<ls0K$
break; 2t.fD@
qm~Kw!kV
for(f=0;f<=dt0;f=f+2) R<t&F\>
{d=PI*f/dt0;
rA2qV
ydgl(); 7V |"~%
} WE7>?H*Ro
} 75PS^5T,
while((am>30*p)||(am<=29.5*p)); zEAx:6`c
printf("The final results:max alfa=%f\n",am/p); Mc.^s
printf(" min ro=%f\n",ro); &9k"9
getch(); ]KzJ u`O%G
} % ghJ*iHR
void ydgl() S [ i$ e
{ d0=dt0*p; T<_+3kw
s=0.5*h*(1-cos(d)); $F<%Jl7_Z
ds=0.5*h*PI*sin(d)/d0; 5,Qy/t}K
r=sqrt(ro*ro-e*e); %jpH:-8'2
if((s+r)==0) "rL"K
return; &#$2;-q8+
al=atan((ds-e)/(s+r)); t%
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if(al>am) /Lj%A
am=al; T$f:[ye]Z
}
