# i nclude<stdio.h> (g!p>m!Z
# i nclude<stdio.h> ()T[$.(
# i nclude<math.h> `CE^2
#define PI 3.1415926 uZjC
c M
void ydgl(); 2 ][DZl
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; \%jVg\4'
int f; i'/m4 !>h
main() oA-:zz>wL
{ printf("Determaination the prime circle of cam\n"); eDKxn8+(H
printf("----------------------------\n"); G@ \Pi#1
printf( "input ro=");scanf("%f",&ro); QCOo
printf("input h=");scanf("%f",&h); +a@GHx4-
printf("input e=");scanf("%f",&e); i^`9syD
printf("input dt0=");scanf("%f",&dt0); A#wEuX=[
am=0;p=PI/180; [I*!
lbt
printf("The initial data:ro=%f\n",ro); L:nXW z
printf("h=%f e=%f dt0=%f\n",h,e,dt0); ~#K@ADYr
do 6aft$A}XnD
{ro=ro+5; nSx8E7 |V
for(f=0;f<=dt0;f=f+2) ~EiH-z4U
{d=PI*f/dt0; ?i\;:<e4
ydgl(); s54nF\3V
} F0Jx(
} ;F:fM!l=
while(am>30*p); hS [SRa'.
printf("The intermediate results: am=%f\n",am/p); XKOUQc4!R
printf("ro=%f\n",ro); n
1b(\PA
do IXLO>>`
{ro=ro-1; z`Wt%tL(
if(ro<e) &7mW9]
break; ff?t[GS
UKd'+R]
for(f=0;f<=dt0;f=f+2) yc;3Id5?>
{d=PI*f/dt0; )EM7,xMz
ydgl(); !v|ISyK
} cV
K7
} |`k
.y]9
while((am>30*p)||(am<=29.5*p)); kK>X rj6
printf("The final results:max alfa=%f\n",am/p); ]:]H:U]p
printf(" min ro=%f\n",ro); -F/st
getch(); +ZsX*/TOn
} #EO1`9f48x
void ydgl() U%B(5cC
{ d0=dt0*p; M6|I6M<
s=0.5*h*(1-cos(d)); x+5p1sv6
ds=0.5*h*PI*sin(d)/d0; `m@U!X
r=sqrt(ro*ro-e*e); pcS+o
if((s+r)==0) [onqNp
return; 9W7#u}Z
al=atan((ds-e)/(s+r)); D0G-5}s`
if(al>am) %u\26[/
am=al; +%>:0mT
}