# i nclude<stdio.h> .@ZqCH
# i nclude<stdio.h> 6]rIYc[,
# i nclude<math.h> aR ao\Wp|
#define PI 3.1415926 11}X2j~Ww
void ydgl(); | Uf6k`
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; k:Sxs+)?1
int f; K?,eIZ{.S
main() h.ojj$f,
{ printf("Determaination the prime circle of cam\n");
mHB*4L
printf("----------------------------\n"); tzJdUZJ
printf( "input ro=");scanf("%f",&ro); \B8tGog
printf("input h=");scanf("%f",&h); wGD".CS0
printf("input e=");scanf("%f",&e); m+||t
printf("input dt0=");scanf("%f",&dt0); X90VJb]
am=0;p=PI/180; @T
printf("The initial data:ro=%f\n",ro); -$J\BkI
printf("h=%f e=%f dt0=%f\n",h,e,dt0); {$)zC*l
do %+YLe-\?
{ro=ro+5; mBSa*s)
for(f=0;f<=dt0;f=f+2) -gefdx6ES
{d=PI*f/dt0; N|Xx#/
ydgl(); s3kHNDdC
} [URo#
} )4>M<BO
while(am>30*p); l7]:b8
printf("The intermediate results: am=%f\n",am/p); n]?Yv E
printf("ro=%f\n",ro); G
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do |}
;&xI
{ro=ro-1; q%%8oaEI
if(ro<e) z$$ E7i
break; 2%i_SX[
S#6{4x4
for(f=0;f<=dt0;f=f+2) =<R")D]4z
{d=PI*f/dt0; |9T3" _MmJ
ydgl(); oa$-o/DhB
} 5A
oKlJrY
} O*xC}$OOn
while((am>30*p)||(am<=29.5*p)); B :#5U85m
printf("The final results:max alfa=%f\n",am/p); ~A2{$C
printf(" min ro=%f\n",ro); Xptb4]
getch(); VTQ V]>|
} B/.+&AJw
void ydgl() JpqZVu"7
{ d0=dt0*p; a~E@scD
s=0.5*h*(1-cos(d)); )zz^RB\p
ds=0.5*h*PI*sin(d)/d0; GTL gj'B
r=sqrt(ro*ro-e*e); G66sPw
if((s+r)==0) gcDo o2RE
return; @TF^6)4f
al=atan((ds-e)/(s+r)); `!WtKqr%B
if(al>am) .'N:]G@!
am=al; qpzzk9ba[
}