# i nclude<stdio.h> * 4Izy14e
# i nclude<stdio.h> -(#iIgmP
# i nclude<math.h> F>cv<l
=6l
#define PI 3.1415926 N?>vd*
void ydgl(); iIogx8[
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; _? OG1t!
int f; s0_nLbWwO
main() qv"$Bd:]r
{ printf("Determaination the prime circle of cam\n"); f9\X>zzB2|
printf("----------------------------\n"); ((I%'
printf( "input ro=");scanf("%f",&ro); +]50D xflA
printf("input h=");scanf("%f",&h); ,: ->ErP
printf("input e=");scanf("%f",&e); r4f~z$QK
printf("input dt0=");scanf("%f",&dt0); \G3rX9xG
am=0;p=PI/180; "T"h)L<
printf("The initial data:ro=%f\n",ro); &w~d_</
printf("h=%f e=%f dt0=%f\n",h,e,dt0); -GgA&dh
do ; Hd7*`$
{ro=ro+5; J'2X&2
for(f=0;f<=dt0;f=f+2) ,iq4Iw
{d=PI*f/dt0; d:{O\
ydgl(); eN~=*Mn(za
} O#u=c1
?:
} ^BL"wk
while(am>30*p); 6(e>P)
printf("The intermediate results: am=%f\n",am/p); _7)n(1h[3b
printf("ro=%f\n",ro); C/&-l{7
do Ydy9
{ro=ro-1; XGMiW0j0B
if(ro<e) $2el&I
break; t. '!`5G
2T TdH)
for(f=0;f<=dt0;f=f+2) rc>6.sM
%
{d=PI*f/dt0;
JSg$wi8
ydgl(); i2^>vYCsl
} pU7lnS[
} Yir
[!{
while((am>30*p)||(am<=29.5*p)); W 8!Qv8rf
printf("The final results:max alfa=%f\n",am/p); Lu0x
(/
printf(" min ro=%f\n",ro); S/I /-Bp~
getch(); ^<-+@v*
} 3<zp
void ydgl() ;]jNk'oa
{ d0=dt0*p; lUiL\~Gq
s=0.5*h*(1-cos(d)); L z1ME(
ds=0.5*h*PI*sin(d)/d0;
EUgs6[w 4
r=sqrt(ro*ro-e*e); ]]juN
if((s+r)==0) 63~
E#Dt4
return; ED&
`_h7?
al=atan((ds-e)/(s+r)); @jlw_ob2g
if(al>am) c\V7i#u[d;
am=al; uc"P3,M
}