# i nclude<stdio.h> L;'C5#GN
# i nclude<stdio.h> _NB8>v
# i nclude<math.h> W2 4n%Ps
#define PI 3.1415926 EV|L~^Q
void ydgl(); am#(ms
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; </33>Fu)
int f; 0=c:O
main() u\P)x~-TM
{ printf("Determaination the prime circle of cam\n"); ZY-mUg
printf("----------------------------\n"); Ops""#Zi
printf( "input ro=");scanf("%f",&ro); 15wwu} X
printf("input h=");scanf("%f",&h); uoe>T:
printf("input e=");scanf("%f",&e); B6"pw0
printf("input dt0=");scanf("%f",&dt0); "MU)8$d
am=0;p=PI/180; sZYTpZgW4L
printf("The initial data:ro=%f\n",ro); LAPCL&Z
printf("h=%f e=%f dt0=%f\n",h,e,dt0); ]]lM)
do +e( (!
{ro=ro+5; 6uubkt
for(f=0;f<=dt0;f=f+2) *tL1t\jY
{d=PI*f/dt0; r:9H>4m
ydgl(); wm
s@1~I
} V SUz+W
} l527>7 eT
while(am>30*p); 0/0rWqg
/
printf("The intermediate results: am=%f\n",am/p); 9Li.B1j
printf("ro=%f\n",ro); 62{[)jt{
do W!4xE
{ro=ro-1; ;P2(C >|
if(ro<e) q<!KtI4
break; &{(8EvuDd
u(P;) E"1
for(f=0;f<=dt0;f=f+2) "U%jG`q
{d=PI*f/dt0; ybgAyJ{J<
ydgl(); Cd51.Sk(l
} 2Ik@L,
} ljRR{HOl
while((am>30*p)||(am<=29.5*p)); 5"8R|NU:\0
printf("The final results:max alfa=%f\n",am/p); 6v9A7g;4.
printf(" min ro=%f\n",ro); .Wq"
getch(); *r]Mn~3
} f+Da W
void ydgl() VKXZA2<?'
{ d0=dt0*p; PbN"+q M
s=0.5*h*(1-cos(d)); ky98Bz%
ds=0.5*h*PI*sin(d)/d0; ZeYkZzN
r=sqrt(ro*ro-e*e); }c-tvK1g
if((s+r)==0) >5}jM5$
return; 'c|Y*2@
al=atan((ds-e)/(s+r)); V;SXa|,
if(al>am) d*TpHLm
am=al; RXU#.=xvy
}