# i nclude<stdio.h> ,j ('QvavJ
# i nclude<stdio.h> JqdNO:8
# i nclude<math.h> d.7Xvx0Yww
#define PI 3.1415926 995^[c1o6
void ydgl(); 2rw<]Ce
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; A_t<SG5
int f; +"]'h~W
main() 3o'SY@'W
{ printf("Determaination the prime circle of cam\n"); 8bX\^&N
printf("----------------------------\n"); Ccocv>=Q&J
printf( "input ro=");scanf("%f",&ro); \4SFD3$&
printf("input h=");scanf("%f",&h); '7F`qL\/#(
printf("input e=");scanf("%f",&e); QsmG(1=
printf("input dt0=");scanf("%f",&dt0); iDO~G($C
am=0;p=PI/180; y^ C;?B<
printf("The initial data:ro=%f\n",ro); b'N"?W^YQ
printf("h=%f e=%f dt0=%f\n",h,e,dt0); ,
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pN
do FVsNOU
{ro=ro+5; #oYX0wvl
for(f=0;f<=dt0;f=f+2) VmTk4?V4
{d=PI*f/dt0; rrSA.J{
ydgl(); fxLhVJ"b
} X/1Z9a+W
} s8``U~D
while(am>30*p); !qH=l-7A
printf("The intermediate results: am=%f\n",am/p); rr4yJ;qpeP
printf("ro=%f\n",ro); U[S;5xeF.j
do ftq~AF
{ro=ro-1; ,Z%!38gGsu
if(ro<e) 8I C((
break; -o#0Yt}3
q<JI!n1O
for(f=0;f<=dt0;f=f+2) #k=!>%+E
{d=PI*f/dt0; 0;TMwE
ydgl(); U2ANu|
} 6x@-<{L
} ,XP9NHE
while((am>30*p)||(am<=29.5*p)); N13 <!QQ
printf("The final results:max alfa=%f\n",am/p); 7k3":2:
printf(" min ro=%f\n",ro); RpLm'~N'
getch(); >[xQUf,p
} TF^]^XS'
void ydgl() }qz58]fyx
{ d0=dt0*p; 4r(rWlM
s=0.5*h*(1-cos(d)); 7<.f&1MgI
ds=0.5*h*PI*sin(d)/d0; WaMn[/{
r=sqrt(ro*ro-e*e); dm$:xE":
if((s+r)==0) kd\yHI9A
return; `hlyN]L
al=atan((ds-e)/(s+r)); ur#"f'|-
if(al>am) Q)a*bPz
am=al; <{-DYRiN
}