# i nclude<stdio.h> IU%|K~_n
# i nclude<stdio.h> yw3"jdcl
# i nclude<math.h> g{65 QP
#define PI 3.1415926 {m.$EoS
void ydgl(); wHc
my
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; $cCC
1=dW
int f; \*xB<mq
main() &XP(D5lf`B
{ printf("Determaination the prime circle of cam\n"); Y`|+sND
printf("----------------------------\n"); |\5^ub,m
printf( "input ro=");scanf("%f",&ro); G 6sK3K
printf("input h=");scanf("%f",&h); T~TP
printf("input e=");scanf("%f",&e); }h5i Tc
printf("input dt0=");scanf("%f",&dt0); ~C.*Vc?|
am=0;p=PI/180; @;Ttdwg#J
printf("The initial data:ro=%f\n",ro); 1 DWoL}Z
printf("h=%f e=%f dt0=%f\n",h,e,dt0); CLb6XnkcA\
do '|C3t!H`
{ro=ro+5; kI{DxuTad
for(f=0;f<=dt0;f=f+2) yPm2??5MW>
{d=PI*f/dt0; ^QB[;g.O
ydgl(); C6_(j48&
} vJkc/7
} 7|P
kc(O
while(am>30*p); Y::0v@&(
printf("The intermediate results: am=%f\n",am/p); Ykbg5Z
printf("ro=%f\n",ro); ^URCnJ67Se
do %`vzQt`>
{ro=ro-1; kIrrbD
if(ro<e) g*|j+<:7
break; 5Wt){rG0Z
f-=\qSo
for(f=0;f<=dt0;f=f+2) m7 =$*1k
{d=PI*f/dt0; iTVe8eI
ydgl(); \U~4b_aN
} jcH@*c=%e
} JE?p'77C
while((am>30*p)||(am<=29.5*p)); $Gn.G_"v
printf("The final results:max alfa=%f\n",am/p); pMc6p0
printf(" min ro=%f\n",ro); \INH[X#>
getch(); XZ
rI w
} QFyL2Xes/
void ydgl() &K)8
{ d0=dt0*p; ::L2zVq5V
s=0.5*h*(1-cos(d)); R`?l.0
ds=0.5*h*PI*sin(d)/d0; +jN}d=N-
r=sqrt(ro*ro-e*e); |m19fg3u
if((s+r)==0) =lXj%V^8N
return; fn#8=TIDf
al=atan((ds-e)/(s+r)); B{-7
if(al>am) 'm%{Rz>j
am=al; 73WSW/^F
}