下面这个函数大家都不会陌生,计算zernike函数值的,并根据此可以还原出图像来, A0Hs d
我输入10阶的n、m,r,theta为38025*1向量,最后得到的z是29525*10阶的矩阵, #PRkqg+|
这个,跟我们用zygo干涉仪直接拟合出的36项zernike系数,有何关系呢? ,NaNih1
那些系数是通过对29525*10阶的矩阵每列的值算出来的嘛? $'VFb=?XrK
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function z = zernfun(n,m,r,theta,nflag) Xn3Ph!\Z5e
%ZERNFUN Zernike functions of order N and frequency M on the unit circle. +lqX;*a=N
% Z = ZERNFUN(N,M,R,THETA) returns the Zernike functions of order N [&
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% and angular frequency M, evaluated at positions (R,THETA) on the 4h~o>(Sq
% unit circle. N is a vector of positive integers (including 0), and "o[j'
% M is a vector with the same number of elements as N. Each element Ik4U+'z6
% k of M must be a positive integer, with possible values M(k) = -N(k) F&lvofy23
% to +N(k) in steps of 2. R is a vector of numbers between 0 and 1, +Te;LJP
% and THETA is a vector of angles. R and THETA must have the same tcf>9YsOr
% length. The output Z is a matrix with one column for every (N,M) ]T! >]
% pair, and one row for every (R,THETA) pair. x,
^j=n
% ceR zHq=
% Z = ZERNFUN(N,M,R,THETA,'norm') returns the normalized Zernike B@Q Ate7
% functions. The normalization factor sqrt((2-delta(m,0))*(n+1)/pi), C_=WL(
% with delta(m,0) the Kronecker delta, is chosen so that the integral C2<