[求助]求教CHIEF RAY ANGLE在Zmax中如何可以看出来? [复制链接]

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? Y`j$7!j  

我這邊有一個zpl可以直看出來~ <)T| HKx  
如下: k^%=\c  
!RIH: CHIEF RAY HEIGHT ON IMA 2QaE&8vW  
L/:l>Ko>7  
!CRA: CHIEF RAY ANGLE IN IMA SPACE +I3Vfv  
n%F _3`  
!和取最?視角度 sF!#*Y  
4aOz=/x2  
MAXFIELD = MAXF() aNu.4c/5  
gEk;Tj  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 EX_j|/&tZ  
7e+C5W*9b  
!獲曲面數 F@Sk=l(  
jyIIE7.I"  
n = NSUR() 0V<kpC,4  
.S|7$_9;b  
!主光線錐激 
o
C|oh  
A^z{n/DiL  
,VVA^'+  
C+**!uYIB  
RAYTRACE  0, 1, 0, 0, PWAV() KUU{X~w  
l0,VN,$Yl  
9 o,`peH  
nIg 88*6b,  
MAX_RIH = RAYY(n) [+D]!&P  
p48enH8CO  
[>
v1JN  
yq;[1O_9C  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   E\/[hT  
6Pl|FIJF  
3&})gU&a  
i+O7,"(@  
PRINT   "MAX FIELD: " , maxfield, 14'\@xJMM  
aC}\`.Kb  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , nBk&+SN  
k'O.1  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH %l!A%fn(  
Qq:}Z7 H  
#l}Fk
)dj  
23r(4  
PRINT "FIELD ",   ]#G s6CsT|  
W|8VE,"7  
PRINT "CHIEF RAY ANGLE," &7\}Sqp  
o_Zs0/  
PRINT  "CHIEF RAY HEIGFHT ON IMA." 2p, U ^h  
H-pf8
 
"yQBHYP  

A4f"v)vM  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for 129\H< m  
K[iAN;QCe%  
nV8'QDQ:Al  
d\>XfS  
For j, 0, 20, 1 R-m5(  
LujLC&S  
FHY = j/20 :dW\Q&iW  
#3*cA!V.<  
RAYTRACE  0, FHY, 0, 0, PWAV() Kfb(wW  
"T=j\/Q  
CRA = ACOS(RAYN(n-1))*180/3.1416 15jQ87)  
v K{2  
OLDX = CRA .
9x*YS  
K*5gb^Ul  
OLDY = RAYY(n) zlEI_th:~  
yQ/O[(  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY VLm\PS   
wb62($  
#$W5)6ch  
O W.CU=XU  
8lx}0U  
/#vt\I<x  
NEXT }i^
M<A O  
)zO|m7  
!繪出該點數據 ?S
& yF  
o}r_+\n  
yn!;Z._  

Ns
h/  
GRAPHICS WwsNAJ  
<6-73LsHcP  
I<RARB-j  
#"-_~  
RAYTRACE 0, 1, 0, 0, PWAV() -Wa<}Tz  
Ry}4MEq]  
MAX_RIH = RAYY(n) _5S0A0  
BTwc(oL  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 S8AbLl9G@>  
g5+m]3#t  
X_WIDE = XMAX() /1.6 Fq~Zr;A  
=KQIrS:  
Y_WIDE = YMAX() /1.6 %'WC7s  
mRAt5a#is  
SEGMENT = 40 ?<.a>"!  
qnyacI  
FOR j, 0, SEGMENT-1,1 v`mB82s  
vmNo~clt\  
Xbmsq,*]  
Lbo3fwW  
FHY = j/SEGMENT JZ`u?ZaJ/s  
L *\[;.mk  
RAYTRACE 0, FHY, 0, 0, PWAV() x7e0&  
8Y8bFWuc  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 )
6%*=-  
#f(tzPD  
RIH = RAYY(n) ;/V])4=  
~6t<`&f  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) V?yQm4  
H.iCYD_=  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20)  g4q{ ]  
;Egl8Vhr  
dpE^BWv3  
xKBi".wA  
o% Q7 el$f  
R%r25_8  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() v(Kj6'  
M^\`~{*T  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 Efe(tH2q  
z l`m1k-X  
RIH = RAYY(n)       -ewR:Y@j  
Xk!{UxQKQ  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) *6<4ECa7C  
/zh:7N  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) ,Vj&  
c]1AM)xo  
!oi {8X@  
Z2*?a|3  
LINE OLDX,OLDY,NEWX,NEWY e~*tQ4  
Ys_LGfK  
A$ = "0" G"3KYBN>  
z7BFkZ6+  
gtext OLDX,OLDY,0, A$ D]fgBW-  
wvisu\V  
NEXT "D>/#cY1/  
eu)""l  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " dpchZ{  
)$1j"mV  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" /m>SEo\{C  
?`Mk$Y%my  
lmUCrs37  
\2~\c#-k  
GRAPHICS OFF Q;l%@)m+~  
~C>;0a;<:  

楼上的回答非常棒！谢谢分享这个宏！ R)N^j'R~=  
还有一个简单的方法，利用Ray Trace观察主光线的ray angle以及imaging height，参见http://www.opticsky.cn/read-htm-tid-51156.html，此贴介绍的很详细。 f6SXXkO+  

学习了！！！！！！！！！！！！！！！！！！！

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