我這邊有一個zpl可以直看出來~ [[ }ukG4
如下: HEK?z|Ne
!RIH: CHIEF RAY HEIGHT ON IMA ;b_<5S
x LK,Je
!CRA: CHIEF RAY ANGLE IN IMA SPACE a4q02 cV
ZCfd<NS?
!和取最?視角度 1X?q4D"
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MAXFIELD = MAXF() ;N
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IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 hm1.UE
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!獲曲面數 FGpV
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n = NSUR() l@@qpaH
~k ]$J|}za
!主光線錐激 XKT[8o<L
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` ^z
l =
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RAYTRACE 0, 1, 0, 0, PWAV() OoZv\"}!_
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