[求助]求教CHIEF RAY ANGLE在Zmax中如何可以看出来? [复制链接]

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? Nbi.\  

我這邊有一個zpl可以直看出來~ [k;\SXDZo  
如下: Pu*6"}#~  
!RIH: CHIEF RAY HEIGHT ON IMA w.YiO5|y  
dE4L=sTEsy  
!CRA: CHIEF RAY ANGLE IN IMA SPACE q$B>|y U  
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!和取最?視角度 =pS5uR~  
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MAXFIELD = MAXF() JSCZ{vJ$  
uP~@U"!  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 _0]S69lp  
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!獲曲面數 O06"bi5Y  
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n = NSUR() %&w3;d;c  
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!主光線錐激 `OXpU,Z 6U  
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RAYTRACE  0, 1, 0, 0, PWAV() 2ZG5<"DQ"  
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MAX_RIH = RAYY(n) XkXHGDEf1  
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MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   v*
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PRINT   "MAX FIELD: " , maxfield, #xQr<p$L6  
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PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , -bT)]gA2  
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PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH 2.l Z:VLN  
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PRINT "FIELD ",   -EkWs/'h  
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PRINT "CHIEF RAY ANGLE," t>urc  
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PRINT  "CHIEF RAY HEIGFHT ON IMA." f78An 8  
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!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for si
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For j, 0, 20, 1 #LL?IRH9^  
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FHY = j/20 %l}D.ml  
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RAYTRACE  0, FHY, 0, 0, PWAV() wsIW |@  
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CRA = ACOS(RAYN(n-1))*180/3.1416 ]b7zJUz  
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OLDX = CRA {*0<T|<n  
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OLDY = RAYY(n) Tx|Ir+f6L  
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PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY hbzC#@q  
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NEXT 0-HqPdjR  
Q[vJqkgT  
!繪出該點數據 B_nVP  
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GRAPHICS P7nc7a  
=(NB%}  
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RAYTRACE 0, 1, 0, 0, PWAV() Z:,U]Z(  
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MAX_RIH = RAYY(n) !%^^\,  
zVXC1u9B  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 b$ve sJ  
10<x.8fSP  
X_WIDE = XMAX() /1.6 J pFfzb  
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Y_WIDE = YMAX() /1.6 0fF(Z0R,  
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SEGMENT = 40 n[T[DCQ,  
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FOR j, 0, SEGMENT-1,1 Mr;E<Lj ^K  
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d F9!G;V  
FHY = j/SEGMENT 4 Y;Nm1@  
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RAYTRACE 0, FHY, 0, 0, PWAV() pP*zq"o  
%\D)u8}  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 ,sA[)wP{  
f!oT65Vmi  
RIH = RAYY(n) =Z P%mW&;}  
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OLDX = X_WIDE * (CRA/MAX_CRA+2/20) bvv|;6  
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OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) 'oF%,4 !Y  
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RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() 5b!vgm#])  
+W:=e,=  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 Wc,~{  
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RIH = RAYY(n)       #JgH}|&a$  
eoai(&o0$  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) $nb[G$  
bu:S:`  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) *+j*{>E  
$^OvhnL/  
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7![,Q~Fy  
LINE OLDX,OLDY,NEWX,NEWY rM .|1(u  
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A$ = "0" n#q<`}u,
 
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gtext OLDX,OLDY,0, A$ v}1QH  
eZ|%<Wpu  
NEXT iVB86XZ`  
r<K(jG[:{f  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " CjlKMbnBH  
k"NVV$;  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" JHz [7  
^Wc@oa`  
-u2P ?~  
5Yl<h)1  
GRAPHICS OFF k`0>36  
EQf[,  

楼上的回答非常棒！谢谢分享这个宏！ U-IpH+E  
还有一个简单的方法，利用Ray Trace观察主光线的ray angle以及imaging height，参见http://www.opticsky.cn/read-htm-tid-51156.html，此贴介绍的很详细。 Wn(6,MDUN  

学习了！！！！！！！！！！！！！！！！！！！

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