[求助]求教CHIEF RAY ANGLE在Zmax中如何可以看出来? [复制链接]

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? oM/(&"  

我這邊有一個zpl可以直看出來~ -K hXb  
如下: HUiW#x%;  
!RIH: CHIEF RAY HEIGHT ON IMA s,XKl5'+8e  
kFZw"5hb  
!CRA: CHIEF RAY ANGLE IN IMA SPACE 6*u#^">,<  
r e.chQ6  
!和取最?視角度 Dk
sSD
 
9`yG[OA  
MAXFIELD = MAXF() *xR;}%s\  

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IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 ,rVm81-2  
D[U[D  
!獲曲面數 vU0j!XqE  
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n = NSUR() rK)aR  
/_}xTP"9  
!主光線錐激 0l#gS;  
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":EfR`A#  
2mN>7Tj:  
RAYTRACE  0, 1, 0, 0, PWAV() Cg<:C?>!p  
Cy-q9uTm  
nQ2V  
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MAX_RIH = RAYY(n) )_N|r$i\  
H)S" `j  
NPy{ =#k4  
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MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   }UNRe]ft$  
. #`lW7  
F!OVx<  
Q= IA|r
N  
PRINT   "MAX FIELD: " , maxfield, >fRI^Q,  
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PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , gBfYm  
9,wd,,ta  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH X-&t!0O4}`  
ZRN*.  
!N:!x[5  
b)RU+9x &  
PRINT "FIELD ",   m`CcU`s  
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PRINT "CHIEF RAY ANGLE," l6Wa~E  
fWiefv[&  
PRINT  "CHIEF RAY HEIGFHT ON IMA."  *X- 6]C  
l]D?S]{a  
!i=LQUi.  
0; GnR0  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for
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5q?2?j/h  
For j, 0, 20, 1  U, _nEx  
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FHY = j/20 6U[`CGL66  
;BzbWvBo  
RAYTRACE  0, FHY, 0, 0, PWAV() ?,~B@Kx  
,>%2`Z)  
CRA = ACOS(RAYN(n-1))*180/3.1416 ?oF+?l  
SXkUtY$  
OLDX = CRA W FVx7  
, 6 P:S7  
OLDY = RAYY(n) (XW\4msB)I  
*6D0>F  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY hbm%{*d  
KP{|xQ>  
'q%56WAJ
 

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3a
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Ay\=&4dv  
NEXT }z{2~ 0,  
( HCB\!g  
!繪出該點數據 eF+:w:\h  
^Xv_y+  
:xOne<@  
QHOA__?  
GRAPHICS c\"t+/Z  
'p<lfT  
I3 /^{-n  
)p*I(y  
RAYTRACE 0, 1, 0, 0, PWAV() T"7Ue  
hTgWqp  
MAX_RIH = RAYY(n) Qvc "?yx8}  
&)jBr^x#>  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 a@(4X/|  
O[ tD7!1  
X_WIDE = XMAX() /1.6 m(MPVY<X  
<vxj*M;  
Y_WIDE = YMAX() /1.6 Co[fq3iX#  
*Ju$A  
SEGMENT = 40 O.61-rp  
Gx Z'"x  
FOR j, 0, SEGMENT-1,1 ' >a(|  
o!:V=F  
X(sHFVU+  
wdS4iQD  
FHY = j/SEGMENT lAjP'(  

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RAYTRACE 0, FHY, 0, 0, PWAV() =!}n .  
h'*>\eC6  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 _$s ;QI]x  
( R2432R}J  
RIH = RAYY(n) cp D=9k!*K  
D7q%rO|F'  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) /.PjHTM<  
_dQVundH  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) f#4,2Xf  
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-+vA9,pI  
5f5bhBZ<  
,w>WuRN"  
+; /]'  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() u,h,;'J  
fL^+Qb}  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 h)S223[  
$ = uz  
RIH = RAYY(n)       2R}9wDP  
QuG=am?l`  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) =W+ h.?  
=Xw
r*
FTr  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) 8?p40x$m%  
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;F>$\"aG  
hC1CISm.U  
LINE OLDX,OLDY,NEWX,NEWY y3!r;>2k=  
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A$ = "0" >%qk2h>  
h7],
/? s  
gtext OLDX,OLDY,0, A$
KDx~^OO  
w8MQA!=l  
NEXT 2|="!c8K  
W lDcKY  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " 8GRp1'\Hi  
82w;}(!  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" $U3|.4  
7Jm&z/  
$bf&ct*$h  
U[l7n3Y=  
GRAPHICS OFF \*>r[6]*&5  
R$[nYw  

楼上的回答非常棒！谢谢分享这个宏！ 2Fi~GY_  
还有一个简单的方法，利用Ray Trace观察主光线的ray angle以及imaging height，参见http://www.opticsky.cn/read-htm-tid-51156.html，此贴介绍的很详细。 _G$SA-W(  

学习了！！！！！！！！！！！！！！！！！！！

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