[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 *Ul*%!?D  
function sjr=nfdre(~) V#q}Wysft  
q*)+K9LRk  
%系统焦距及各镜间距输入，间距取负正负 4l8BQz}sb  
gX5&d\y  
f=input('f:'); /( 6|{B  
d1=input('d1:'); ->lu#;A5  
d2=input('d2:'); VK3it3FI>3  
d3=input('d3:'); 9TxyZL   
_w ]4~V9  
A=f^2/(d3*d2)-f/d1; k6\^p;!Y  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); vs&8wbS)  
C=d3/d2-f/d1; 'b"TH^\  
[{&jr]w`|  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 AN9[G  
a2=d3/(a1*f);%α2 Ps R>V)L  
b2=a1*(1-a2)*f/d2;%β2 "t(wG{RxY  
b1=(1-a1)*f/(d1*b2);%β1 F#+.>!  
#-cTc&$O;  
7uI#L}y  
%曲率半径 t"s5\;IJ  
?Hy+'sq[  
R1=2*f/(b1*b2) vH?9\3  
R2=2*a1*f/(b2*(1+b1)) yqSY9EX7  
R3=2*a1*a2*f/(1+b2) $EBb"+Y'T  
G5'_a$  
A1=b2^3*(a1-1)*(1+b1)^3; q^bO*bv  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; Nw]
("
.  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; 9XV^z*E(J  
z \?UGxu}  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2);  U w Eiz  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); h[=nx^  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); y@apJ;_R-  
VO`"<  
CB=[C1 B1;C2 B2];  93w~.p  
AB=[A1 B1;A2 B2]; 3eg5oAZ)G8  
AC=[A1 C1;A2 C2]; H=.
K  
LV.&>@*  
%非球面系数 zk>h u<_  
k2=-(det(CB)/det(AB)); v*P[W_.  
k3=-(det(AC)/det(AB)); vR]mSX3)?  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 pT=2e&  
k2=k2 $pFk"]=  
k3=k3 *]{=8zc2  
aIu2>  
end R{<Y4C2~  
.Z5[_'T
  
%有中间像，焦距输入为正数 J~dTVBx  
; J2-rh  
function sjr=yfdre(~) [
.U^Wrd  
.&(8(C  
f=input('f:'); #{w5)|S#JD  
d1=input('d1:'); *8206[y  
d2=input('d2:'); %O/d4  
d3=input('d3:'); [|
<EDR  
)G4rJ~#@  
A=f^2/(d3*d2)-f/d1; YOKR//|3  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); xA9V$#d|  
C=d3/d2-f/d1; ^^ j/  
HPTHF  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); M8Juykw  
a2=d3/(a1*f); Yhk6Uog{4  
b2=a1*(1-a2)*f/d2; (uT^Nn9L=  
b1=(1-a1)*f/(d1*b2); )rbc;{.  
S[.5n]  
%曲率半径
-3`Isv  
?N2X)Y@yi  
R1=2*f/(b1*b2) rr)9Y][l}  
R2=2*a1*f/(b2*(1+b1)) h=Oh9zsz8  
R3=2*a1*a2*f/(1+b2) J5-rp|  
`~|DoSi^d  
A1=b2^3*(a1-1)*(1+b1)^3; v0u\xX[H;  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; 4UazD_`'  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; |zb`&tv}  
9
yDFHz w  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); &EGY+p|2Y  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); GP Ix@k  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); w
Ya0hNd  

Xv8fPP(  
CB=[C1 B1;C2 B2]; b%<164i  
AB=[A1 B1;A2 B2]; u8xk]:%  
AC=[A1 C1;A2 C2]; 9ec0^T  
tb:  
%二次系数 Plb}dID"  
6/VNuQ_#  
k2=-(det(CB)/det(AB)); hzW{_Q.|?  
k3=-(det(AC)/det(AB)); `~0P[>|+  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 Q;=6ag'  
k2=k2 OA!R5sOz"  
k3=k3 TLXhE(o|o  
qjJ{+Rz2  
end

谢谢分享，学习一下 /A%om|+Gq