[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 823Y\x~>  
function sjr=nfdre(~) y}" O U  
'uSn}hm  
%系统焦距及各镜间距输入，间距取负正负 K7_UP&`=J  
'T*&'RQr  
f=input('f:'); & p  
d1=input('d1:'); itt3.:y  
d2=input('d2:'); JE"x  
d3=input('d3:'); -:+|zF@f  
xX&+WR  
A=f^2/(d3*d2)-f/d1; 'urafE4M  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); |.: 
q  
C=d3/d2-f/d1; ]vUwG--*  
M6"PX *K  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 !Iy_UfW  
a2=d3/(a1*f);%α2 'x#~'v
*  
b2=a1*(1-a2)*f/d2;%β2 tKOmoC  
b1=(1-a1)*f/(d1*b2);%β1 zZPO&akB"  
C`hU]  
%v M-mbX  
%曲率半径 3wF;GG  
X]TG<r  
R1=2*f/(b1*b2) *aM=Z+  
R2=2*a1*f/(b2*(1+b1)) hR?{3d#x2  
R3=2*a1*a2*f/(1+b2) EeE7#$l  
I3L<[-ZE  
A1=b2^3*(a1-1)*(1+b1)^3; me$Z~/Akm  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; gh]cXuph  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; DMr\ TN  
N)X3XTY  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); R`qFg/S  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); r(TIw%L$  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); NIry)'"  
Rsm^Z!sn  
CB=[C1 B1;C2 B2]; &jJL"gq"  
AB=[A1 B1;A2 B2]; 7;(`MIFXs  
AC=[A1 C1;A2 C2]; /hR&8 `\\  
>y7?-*0  
%非球面系数 +Mb.:_7'  
k2=-(det(CB)/det(AB)); *Hn8)x}E  
k3=-(det(AC)/det(AB)); L,/%f<wd  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 %$Tji  
k2=k2 eu-*?]&Di  
k3=k3 d7;um<%zn  
m+[Ux{$  
end IFL*kB   
ydA8wL  
%有中间像，焦距输入为正数 lTgjq:mn  
""G'rN_=Bi  
function sjr=yfdre(~) U?Zq6_M&  
\!ZTL1b8t  
f=input('f:'); &U#|uc!+  
d1=input('d1:'); YK'<NE3 4  
d2=input('d2:'); rq].UCj  
d3=input('d3:'); Xc-'Y"}|`t  
A?P_DA  
A=f^2/(d3*d2)-f/d1; IOmfF[  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); +I|vzz`ZVr  
C=d3/d2-f/d1; 7Ovi{xd@  
Ow,w$0(D  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); |/{=ww8|  
a2=d3/(a1*f); f.$af4 u  
b2=a1*(1-a2)*f/d2; 8cIKvHx  
b1=(1-a1)*f/(d1*b2); dUZ ,m9u  
?k{?GtSs  
%曲率半径 *^ZV8c}  
VY4yS*y  
R1=2*f/(b1*b2) $<EM+oJ|ER  
R2=2*a1*f/(b2*(1+b1)) Z@!+v19^  
R3=2*a1*a2*f/(1+b2) Wh*uaad7  
BW4J>{  
A1=b2^3*(a1-1)*(1+b1)^3; 5U$0F$BBp  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; U'bEL^Jf  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; "+G8d'%YV  
mCVFS=8V  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); @*((
1(q  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); '5$b-x6F  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); )jP1or  
oUU1+F-  
CB=[C1 B1;C2 B2]; Tyx_/pJT  
AB=[A1 B1;A2 B2]; h S&R(m  
AC=[A1 C1;A2 C2]; zQ
d 2  
b8 likP"T  
%二次系数 kt:! 7  
[7Oe3=  
k2=-(det(CB)/det(AB)); uKHxe~  
k3=-(det(AC)/det(AB)); -[.[>&`/  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 (f"4,b^]  
k2=k2 "^%cJAnLX  
k3=k3 h2d(?vOT  
CLRdm^B  
end

谢谢分享，学习一下 S)@j6(HC4