[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 \=TWYj_Ah  
function sjr=nfdre(~) e=|F(iW  
:6qUSE  
%系统焦距及各镜间距输入，间距取负正负 `1DU b7<  
qM+!f2t  
f=input('f:'); 9p!dQx  
d1=input('d1:'); *NKC\aV`0  
d2=input('d2:'); a .B\=3xn  
d3=input('d3:'); N$L&|4r  
K.c6Rg  
A=f^2/(d3*d2)-f/d1; 9~*_(yjF  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); jnx+wcd  
C=d3/d2-f/d1; GN8`xR{J*  
D<$j`r  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 E9 :|8#b  
a2=d3/(a1*f);%α2 4?*`:  
b2=a1*(1-a2)*f/d2;%β2 "y3dwSS  
b1=(1-a1)*f/(d1*b2);%β1 5[0l08'D  
9e|{z9z[l  
,DW0A//  
%曲率半径 70I4-[/z[d  
M<hs_8_*  
R1=2*f/(b1*b2) w96j,rEC  
R2=2*a1*f/(b2*(1+b1)) -bIpmp?  
R3=2*a1*a2*f/(1+b2) RJ7/I/yD|  
cviN$oL  
A1=b2^3*(a1-1)*(1+b1)^3; 9^=t@  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; FeincZ!M  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; 8O}A/*1FJ  
'3Y0D1`v  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); J/H#d')c  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); '8((;N|I^  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); 8M5!5Jzv  
()rx>?x5  
CB=[C1 B1;C2 B2]; QvT-&|  
AB=[A1 B1;A2 B2]; *U5>j#,  
AC=[A1 C1;A2 C2]; M2;(+8 b  
N:sECGS,  
%非球面系数 }(hYG"5  
k2=-(det(CB)/det(AB)); ~]D\&D9=?  
k3=-(det(AC)/det(AB)); "m\UqQGX  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 4jue_jsle  
k2=k2 q#':aXcv"  
k3=k3 "|~B};|MFF  
1&>nL`E[3  
end Iu)(H
uv  
{?kKpMNNn  
%有中间像，焦距输入为正数 WhVmycdv  
R*c0NJF
 
function sjr=yfdre(~) c Gaz$=/  
T(fR/~:z?  
f=input('f:'); 9_CA5?y$:  
d1=input('d1:'); f T+n-B  
d2=input('d2:'); V.G9J!?<P  
d3=input('d3:'); D;T r  
Vzv.e
6_  
A=f^2/(d3*d2)-f/d1; `Mh<S+/  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); IQ27FV|3  
C=d3/d2-f/d1; BIB>U W  
(J) Rs`_  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); 7;#dX~>@{  
a2=d3/(a1*f); 9"u@<]  
b2=a1*(1-a2)*f/d2; ;@ !d!&  
b1=(1-a1)*f/(d1*b2); h0EGhJs  
H:nu>pzt  
%曲率半径 @|*Z0bn'  
a[{QlD^D  
R1=2*f/(b1*b2) 1Qc(<gM  
R2=2*a1*f/(b2*(1+b1)) ne%OTr4dD  
R3=2*a1*a2*f/(1+b2) yK2*~T,6@  
E'kQ  
A1=b2^3*(a1-1)*(1+b1)^3; 3B_} :  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; Y.hH fSp  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; {G
*:N[pJp  
PXQ9P<m  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); 4~D>oNx4  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); MBTt'6M  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); cX]{RVZo-/  
-gX2{dW  
CB=[C1 B1;C2 B2]; !NY^(^   
AB=[A1 B1;A2 B2]; PQI,vr'R  
AC=[A1 C1;A2 C2]; Q*J ~wuE2  
qt&"cw  
%二次系数 ^OcfM_4pN  
}4ghT(C}$  
k2=-(det(CB)/det(AB)); D;8V{Hs  
k3=-(det(AC)/det(AB)); 
n|`):sP  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 {<{G 1y~  
k2=k2 aFm]?75  
k3=k3 :?XHZ
  
V6!73 iY  
end

谢谢分享，学习一下 ?GfA;O