[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 pAEx#ck  
function sjr=nfdre(~) V&i;\
9  
BUFv|z+H  
%系统焦距及各镜间距输入，间距取负正负 X&zis1A<  
}u|q0>^8  
f=input('f:'); 8L XHk l  
d1=input('d1:'); 9F
lb|G%  
d2=input('d2:'); rNM;ZPF#  
d3=input('d3:'); J,G lIv.A  
6zkaOA46V  
A=f^2/(d3*d2)-f/d1; qR.Q,(b|  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); ;<5q]/IHK  
C=d3/d2-f/d1; q4q6c")zp  
m|# y >4  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 ]_Xl
q_[/r  
a2=d3/(a1*f);%α2 Vi}_{ Cy  
b2=a1*(1-a2)*f/d2;%β2
0V]s:S  
b1=(1-a1)*f/(d1*b2);%β1 ;4a{$Lw~^9  
wBzC5T%,  
{*KEP  
%曲率半径 BY*Q_Et  
!W0v >p  
R1=2*f/(b1*b2) Al'3?  
R2=2*a1*f/(b2*(1+b1)) M2|is ~  
R3=2*a1*a2*f/(1+b2) /(T?j!nPE  
u>$t'  
A1=b2^3*(a1-1)*(1+b1)^3; J
RFtsio*  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; =xrv~  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; d3Rw!slIq  
DJir{ \F  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); 5IN(|B0  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); -8Xf0_  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); -N@|QK>  
*H122njH+T  
CB=[C1 B1;C2 B2]; h~26WLf.  
AB=[A1 B1;A2 B2]; Wm|lSisY  
AC=[A1 C1;A2 C2]; t Pf40`@  
6RM/GM  
%非球面系数 1cGmg1U;  
k2=-(det(CB)/det(AB)); ~Z
+%d9ode  
k3=-(det(AC)/det(AB)); 3F0 N^)@
 
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 9cgUT@a  
k2=k2 2%>FR4a  
k3=k3 C7vxw-o|&p  
Tr|JYLwF
 
end P$sxr  
X|[`P<'N<  
%有中间像，焦距输入为正数 8_tQa^.n\  
S$k&vc(0  
function sjr=yfdre(~) 2(nlJ7R  
I|J/F}@p  
f=input('f:'); OH"XrCX7n  
d1=input('d1:'); {U1m.30n  
d2=input('d2:'); w:l"\Tm  
d3=input('d3:'); s7EinI{^  

TKjFp%  
A=f^2/(d3*d2)-f/d1; @H<q"-J  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); <X5fUU"+U  
C=d3/d2-f/d1; <1pEwI~  
J=L5=G7(  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); kR9-8I{J  
a2=d3/(a1*f); d"N
LE'R  
b2=a1*(1-a2)*f/d2; or]IZ2^n  
b1=(1-a1)*f/(d1*b2); rH>)oThA#  
[r-p]"R  
%曲率半径 s79r@])=  
LF7SS;&~f  
R1=2*f/(b1*b2) %UM *79  
R2=2*a1*f/(b2*(1+b1)) %bfZn9_m  
R3=2*a1*a2*f/(1+b2) "mNq&$  
=mGez )T5\  
A1=b2^3*(a1-1)*(1+b1)^3; Wl Sm  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; njw|JnDv  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; e|9A716x  
wAd
9  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); Bj~+WwD)QR  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); {iLT/i%  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); 9/;P->wy  
Ru~j,|0r4  
CB=[C1 B1;C2 B2]; nOz.G"  
AB=[A1 B1;A2 B2]; 05k0n E  
AC=[A1 C1;A2 C2]; Z8oK2Dw  
o]:9')5^  
%二次系数 G9:l'\  
bTu9;(  
k2=-(det(CB)/det(AB)); 1QJL .  
k3=-(det(AC)/det(AB)); r9lR|\Ax2U  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 3Y~>qGQwh  
k2=k2 iIogx8[  
k3=k3 _?OG1t!  
@R  6@]Dm  
end

谢谢分享，学习一下 ]cN1c}