[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 &F}"Z(B<wK  
function sjr=nfdre(~) p\{-t84n  
ud f
e  
%系统焦距及各镜间距输入，间距取负正负 21RP=0Q:  
7RDDdF E!  
f=input('f:'); Blq8H"3!:  
d1=input('d1:'); !`bio cA  
d2=input('d2:'); RI2f`p8k  
d3=input('d3:'); g/CxXSv@0  
^s.V;R  
A=f^2/(d3*d2)-f/d1; M/Pme&%  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); 5d@t7[]  
C=d3/d2-f/d1; ASPy  
5PcJZi^.l
 
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 w:'dhr':  
a2=d3/(a1*f);%α2 Q%aU42?_1  
b2=a1*(1-a2)*f/d2;%β2  fI\
9\x  
b1=(1-a1)*f/(d1*b2);%β1 RllY-JBO  
n41@iK2l  
oUQ07z\C  
%曲率半径 4em;+ >D6  
?OdJqw0,G  
R1=2*f/(b1*b2) w;v7_  
R2=2*a1*f/(b2*(1+b1)) *)]"27^  
R3=2*a1*a2*f/(1+b2) #y|V|nd
 
Z`3ufXPNlO  
A1=b2^3*(a1-1)*(1+b1)^3; . |*f!
w}5  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; #}^-C&~  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; `MP|Ovns:H  
+jC*'7p@  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); L}#0I+Ml7  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 2wqk,c[]  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); H;aYiy  
9x+<Ik  
CB=[C1 B1;C2 B2]; ;d$qc<2uA  
AB=[A1 B1;A2 B2]; p (FlR?= S  
AC=[A1 C1;A2 C2]; 9
dh>l!2  
Y,8KPg@W  
%非球面系数 ,%bhyww<  
k2=-(det(CB)/det(AB)); G1 o70  
k3=-(det(AC)/det(AB)); I &*_,d  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 ?t@v&s  
k2=k2 ~tB;@
e  
k3=k3 ;DnUQj  
dMx4ykrR  
end N?dvuB  
e
7u^mJ  
%有中间像，焦距输入为正数 *sQcg8{^  
m\/(w_/?  
function sjr=yfdre(~) vFrt|JC_{  
T2?HRx  
f=input('f:'); ~#\i!I;RY}  
d1=input('d1:'); PCc|}*b  
d2=input('d2:'); EPW7+Ve  
d3=input('d3:'); S~$'W
A  
t<:D@J]a  
A=f^2/(d3*d2)-f/d1; Rd+P,PO  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); nRhrWS  
C=d3/d2-f/d1; 6)\dBOz  
x}$e}8|8YL  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); o-7>eE}+  
a2=d3/(a1*f); KRsAv^']  
b2=a1*(1-a2)*f/d2; ,(G%
e  
b1=(1-a1)*f/(d1*b2); _nT{g  
)_zlrX  
%曲率半径 &K^MNd  
*5%*|>  
R1=2*f/(b1*b2) VVWM9x  
R2=2*a1*f/(b2*(1+b1)) YC_3n5F%  
R3=2*a1*a2*f/(1+b2) AV&yoag1  
gM;}#>6  
A1=b2^3*(a1-1)*(1+b1)^3; x2|6
  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; 5TBI<K  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; BdbJ< Is  
!a1i Un9  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); PM$Ee #62R  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); (g :p5Rl  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); 4aZCFdc  
2^exL h  
CB=[C1 B1;C2 B2]; t0PQ~|H<KV  
AB=[A1 B1;A2 B2]; Ni[4OR$-O  
AC=[A1 C1;A2 C2]; "C%!8`K{a*  
*.y'(tj[  
%二次系数 IKvBf'%-  
%IpSK 0<Sp  
k2=-(det(CB)/det(AB));
U6 82Th  
k3=-(det(AC)/det(AB)); w5]"ga>Y  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 ;'RFo?u K  
k2=k2 AZFWuPJo  
k3=k3 ^>~dlS  
1TqF6`;+  
end

谢谢分享，学习一下 o0;7b>Tv