[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 PaI63 !  
function sjr=nfdre(~) jJQfCOD$  
D~?*Xv]s~  
%系统焦距及各镜间距输入，间距取负正负 ~map5@Kd  
/@}# KP=  
f=input('f:'); ,^[37
/S  
d1=input('d1:'); b020U>)v  
d2=input('d2:'); ,ui'^8{gK  
d3=input('d3:'); Jj!tRZT  
<;Z~ vZ]  
A=f^2/(d3*d2)-f/d1;  X_S]8Aa  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); /*2W?ZM~H  
C=d3/d2-f/d1; 5*'N Q010  
a9JJuSRC  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 UHszOl  
a2=d3/(a1*f);%α2 Uy'ZL(2  
b2=a1*(1-a2)*f/d2;%β2 EGO@`<"h  
b1=(1-a1)*f/(d1*b2);%β1 d#,V^  
r<H^%##,w  
dOgM9P  
%曲率半径 <.XoC?j  
*"L:"i`*$  
R1=2*f/(b1*b2) U.} =j'Us+  
R2=2*a1*f/(b2*(1+b1)) 5fv6RQD  
R3=2*a1*a2*f/(1+b2) =umS^fJ5`  
T1 .@Tbbt  
A1=b2^3*(a1-1)*(1+b1)^3; #`wfl9tj  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; 5]ob;tAm  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; 4nXS9RiF2  
l),13"?C(  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); hpKc_|un  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); ~OfKn1D  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); / UBAQ8TR  
SvJ8Kl OV  
CB=[C1 B1;C2 B2]; j`hbQp\`  
AB=[A1 B1;A2 B2]; dL"i\5#%A  
AC=[A1 C1;A2 C2]; #Ih(2T i  
TyXOd,%zl  
%非球面系数 m5
g: Q  
k2=-(det(CB)/det(AB)); )Em,3I/.l  
k3=-(det(AC)/det(AB)); HYa!$P3}[  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 7-B'G/PS/  
k2=k2 S8<aq P  
k3=k3 W]]2Uo.  
@&> +`kgU-  
end l'R`XGT  
nXW1:  
%有中间像，焦距输入为正数 i<![i5uAI  
lK@r?w|<M  
function sjr=yfdre(~) Kwau:_B  
:fUmMta  
f=input('f:'); 6-}9m7#Y  
d1=input('d1:'); t')I c6.?i  
d2=input('d2:'); B}T72!a  
d3=input('d3:'); mJqP#Unik  
^jC0S[csw2  
A=f^2/(d3*d2)-f/d1; qA[}\8}
h  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); -v&srd^  
C=d3/d2-f/d1; }k~0R-m  
3F3?be  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); |
mX8fRh  
a2=d3/(a1*f); >?xVr  
b2=a1*(1-a2)*f/d2; pYQs|5d  
b1=(1-a1)*f/(d1*b2); _"TG:RP  
1yf&ck1R  
%曲率半径 r73Xh"SL  
RmCR"~  
R1=2*f/(b1*b2) VW/1[?HG5  
R2=2*a1*f/(b2*(1+b1)) 9`b3=&i\  
R3=2*a1*a2*f/(1+b2) )A"7l7?.n)  
T[J_/DE@  
A1=b2^3*(a1-1)*(1+b1)^3; 3e:y?hpeL  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; D':A-E
  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; !Zx>)V6.  
=cY]cPO  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); YN3uhd[2  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); c0~'5Mlp  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); >n62csO  
SuSZ,>  
CB=[C1 B1;C2 B2]; Bf'(JJ7&N  
AB=[A1 B1;A2 B2]; =X):Zi   
AC=[A1 C1;A2 C2]; #{a<{HX  
P*Nl3?T  
%二次系数 I-I5^s  
Z )I4U  
k2=-(det(CB)/det(AB)); JKGZ0yn  
k3=-(det(AC)/det(AB)); ]a()siT  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 }W J`q`g  
k2=k2 7#`:m|$  
k3=k3 XafyI*pOX  
7;V5hul  
end

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