[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 Un@dWf6'  
function sjr=nfdre(~) 7'CdDB6&.  
ioz4kG!  
%系统焦距及各镜间距输入，间距取负正负 j%Usui<DL  
PkMN@JS  
f=input('f:'); oyK'h9Wt1  
d1=input('d1:'); <Zn]L:  
d2=input('d2:'); H $XO]\  
d3=input('d3:'); "V}WV!w  
~"#qG6dP  
A=f^2/(d3*d2)-f/d1; 6||zfH  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); Z`T]jm-3  
C=d3/d2-f/d1; ? 0
p_/mZ  
&M&*3  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 MA6(VII
 
a2=d3/(a1*f);%α2 3c}@_Yn  
b2=a1*(1-a2)*f/d2;%β2 o7;l
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b1=(1-a1)*f/(d1*b2);%β1 gwm!Pw j  
C[6} 8J|  
n#|ljC  
%曲率半径 wQEsq<  
kc-=5l  
R1=2*f/(b1*b2) #p*D.We  
R2=2*a1*f/(b2*(1+b1)) i}[cq_wJ  
R3=2*a1*a2*f/(1+b2) gNUYHNzDM(  
_(l?gj  
A1=b2^3*(a1-1)*(1+b1)^3; tp*.'p-SI  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; L`NY^  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; xhK
8Q  
?I{L^j^#4  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); _wH>h$E  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); %PM&`c98z7  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); dhv?36uE  
R-LMV  
CB=[C1 B1;C2 B2]; }IEwGoDwNs  
AB=[A1 B1;A2 B2]; SO4?3wg7  
AC=[A1 C1;A2 C2]; 6I2`oag  
^F,sV*  
%非球面系数 G%iTL"6  
k2=-(det(CB)/det(AB)); & 6'Rc#\P  
k3=-(det(AC)/det(AB)); x<5ARK6\=  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 }@x!r=O)I  
k2=k2 GXC,p(vbE  
k3=k3 +`,;tz=?  
:^7>k
J5?  
end hh8Gr
l;  
];xDXQd  
%有中间像，焦距输入为正数 P q0%oz  
P9`R~HO'`  
function sjr=yfdre(~) 4>A|2+K\  
xt_:R~/[  
f=input('f:'); V6Mt;e)C  
d1=input('d1:'); 5`Q j<
  
d2=input('d2:'); % IHIXncv[  
d3=input('d3:'); Y<L35 ?  
e,
N}z  
A=f^2/(d3*d2)-f/d1; Hvb8+"?~  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); m/z,MT74*J  
C=d3/d2-f/d1; 3xT9/8*  
rk6K0TQ8  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); <d @9[]  
a2=d3/(a1*f); #
u}%r{T  
b2=a1*(1-a2)*f/d2; 1U% /~  
b1=(1-a1)*f/(d1*b2); jp_|pC'  
Kci. ,I  
%曲率半径 AbxhNNK  
\yl|*h3  
R1=2*f/(b1*b2) 8N%nG( 0  
R2=2*a1*f/(b2*(1+b1)) K+pVRDRcs  
R3=2*a1*a2*f/(1+b2) Z
\?2"4H  
AtewC
Yo  
A1=b2^3*(a1-1)*(1+b1)^3; u\V^g  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; I)tiXcJw  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; <+k"3r{y"  
m>%b4M  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); N0H=;CIQ  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 2]1u0-M5L  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); ;-6-DEL  
N+'j on}U  
CB=[C1 B1;C2 B2]; LRVcf  
AB=[A1 B1;A2 B2]; y(o)}m*0  
AC=[A1 C1;A2 C2]; GlnO8cAB  
T]\c2U  
%二次系数 12a`,~  
i|J%jA  
k2=-(det(CB)/det(AB)); wqhktgG  
k3=-(det(AC)/det(AB)); } vmRm*8z  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 #0>xa]S  
k2=k2 ]QhTxrF"  
k3=k3 7~SwNt,  
x2rAB5r6  
end

谢谢分享，学习一下 !R=@Nr>