# i nclude<stdio.h> VCfHm"'E8
# i nclude<stdio.h> <8(=Lv`)q
# i nclude<math.h> hr;^.a^
#define PI 3.1415926 ?a#Gn2
void ydgl(); qg{gCG
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; 1RJFPv
int f; U0t|i'Hx
main() P0y DL:X[
{ printf("Determaination the prime circle of cam\n"); A|GtF3:G
printf("----------------------------\n"); TG[u3Y4
printf( "input ro=");scanf("%f",&ro); ~P#mvQE)
printf("input h=");scanf("%f",&h); /v^'5j1o
printf("input e=");scanf("%f",&e); Vbt!, 2_)
printf("input dt0=");scanf("%f",&dt0); C7ug\_,s
am=0;p=PI/180; D%~tU70a
printf("The initial data:ro=%f\n",ro); w i[9RD@
printf("h=%f e=%f dt0=%f\n",h,e,dt0); :`e#I/,
do +N=HI1^54R
{ro=ro+5; vof8bQ{&
for(f=0;f<=dt0;f=f+2) U|]cB
{d=PI*f/dt0; T:u>7?8o
ydgl(); vP x/&x
} TKM^
} tPQ|znB|
while(am>30*p); 1l$2T
y+
=
printf("The intermediate results: am=%f\n",am/p); sEFQ8S
printf("ro=%f\n",ro); g:z<CSIq/
do arDl2T,igF
{ro=ro-1; T[ZmD{6l
if(ro<e) .6P.r}
break;
xRe`Duy:
n74\{`8]o
for(f=0;f<=dt0;f=f+2) Ux7LN@4og
{d=PI*f/dt0; x>}ml\R
ydgl(); @>HTbs6W
} [02rs@c>
} b%0p<*:a/
while((am>30*p)||(am<=29.5*p)); q)i %*IY
printf("The final results:max alfa=%f\n",am/p); SK
lvZ
printf(" min ro=%f\n",ro); =}0Uw4ub(u
getch(); >=[uLY[aK
} (iX8YP$ %
void ydgl() W}f)VC;D
{ d0=dt0*p; =..Bh8P71!
s=0.5*h*(1-cos(d)); \P*_zd@%
ds=0.5*h*PI*sin(d)/d0; 8
MQq3
r=sqrt(ro*ro-e*e); 0n{.96r0R
if((s+r)==0) H:@hCO[a
return; 7pm'b,J<
al=atan((ds-e)/(s+r)); !HvA5'|:}
if(al>am) @khFk.LBD
am=al; d.FU))lmD
}