利用菲涅尔公式计算光波在两种介质表面折反射率及折反射能流密度 1jmhh!,
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clear {yyg=AMz
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close all <O$'3_S"D
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n1=1,n2=1.45; q){]fp.,@
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theta=0:0.1:90; l^`!:BOtR
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a=theta*pi/180; .M>u:,v
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rp=(n2*cos(a)-n1*sqrt(1-(n1/n2*sin(a)).^2))./(n2*cos(a)+n1*sqrt(1-(n1/n2*sin(a)).^2)); 3UC8iq*
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rs=(n1*cos(a)-n2*sqrt(1-(n1/n2*sin(a)).^2))./(n1*cos(a)+n2*sqrt(1-(n1/n2*sin(a)).^2)); `ss]\46>
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tp=2*n1*cos(a)./(n2*cos(a)+n1*sqrt(1-(n1/n2*sin(a)).^2)); n^Z?u9VR
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ts=2*n1*cos(a)./(n1*cos(a)+n2*sqrt(1-(n1/n2*sin(a)).^2)); A94VSUDA:
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figure(1) r.ajw&J2
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subplot(1,2,1); WgPL4D9=
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plot(theta,rp,'-',theta,rs,'--',theta,abs(rp),':',theta,abs(rs),'-.','LineWidth',2) _ux6SIyp`
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legend('r_p','r_s','|r_p|','|r_s|') R&xD|w8UjM
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xlabel('\theta_i') +}+hTY$a
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ylabel('Amplitude') Olxb`x
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title(['n_1=',num2str(n1),',n_2=',num2str(n2)]) }= <!j5:
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axis([0 90 -1 1]) J"83S*2(j
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grid on d'3'{C|kk
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subplot(1,2,2); :m$%D]WY
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plot(theta,tp,'-',theta,ts,'--',theta,abs(tp),':',theta,abs(ts),'-.','LineWidth',2) O_iX1@SW
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legend('t_p','t_s','|t_p|','|t_s|') uk'<9g^
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xlabel('\theta_i') '6WDs]\
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ylabel('Amplitude') +?@qux!
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title(['n_1=',num2str(n1),',n_2=',num2str(n2)]) '\_)\`a|
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axis([0 90 0 1]) AT9SD vJ
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grid on cEQa 6
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Rp=abs(rp).^2; & {/u>,
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Rs=abs(rs).^2; &GZR-/
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Rn=(Rp+Rs)/2; QV 'y6m\
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Tp=1-Rp; hBqu,A
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Ts=1-Rs; O71rLk;
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Tn=(Tp+Ts)/2; S8cFD):q
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figure(2) e^an` </{
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subplot(1,2,1); ZT8j9zs
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plot(theta,Rp,'-',theta,Rs,'--',theta,Rn,':','LineWidth',2) 1e+?O7/
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legend('R_p','R_s','R_n') b>(lF%M
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xlabel('\theta_i') P3|<K-dFAK
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ylabel('Amplitude') `->k7a0<b1
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title(['n_1=',num2str(n1),',n_2=',num2str(n2)]) Yt'o#"R)
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axis([0 90 0 1]) x M[#Ah)
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grid on $g^;*>yr
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subplot(1,2,2); ]>,|v,i
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plot(theta,Tp,'-',theta,Ts,'--',theta,Tn,':','LineWidth',2) ZSSgc0u^?
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legend('T_p','T_s','T_n') F{+`F<r
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xlabel('\theta_i') jdp:G
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ylabel('Amplitude') A%O#S<sa
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title(['n_1=',num2str(n1),',n_2=',num2str(n2)]) e-CW4x
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axis([0 90 0 1]) Sx"I]N
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grid on 9 JtG&^*
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