利用菲涅尔公式计算光波在两种介质表面折反射率及折反射能流密度 h4i$z-!
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clear BT#g?=n#`
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close all ,#O8:s
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n1=1,n2=1.45; <\EfG:e
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theta=0:0.1:90; gQDK?aQX
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a=theta*pi/180; nGd
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rp=(n2*cos(a)-n1*sqrt(1-(n1/n2*sin(a)).^2))./(n2*cos(a)+n1*sqrt(1-(n1/n2*sin(a)).^2)); e!Okc*,
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rs=(n1*cos(a)-n2*sqrt(1-(n1/n2*sin(a)).^2))./(n1*cos(a)+n2*sqrt(1-(n1/n2*sin(a)).^2)); -;-"i J0
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tp=2*n1*cos(a)./(n2*cos(a)+n1*sqrt(1-(n1/n2*sin(a)).^2)); _q4m7C<
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ts=2*n1*cos(a)./(n1*cos(a)+n2*sqrt(1-(n1/n2*sin(a)).^2)); 4,DsB'
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figure(1) ,?/<fxIY
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subplot(1,2,1); d vxEXy
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plot(theta,rp,'-',theta,rs,'--',theta,abs(rp),':',theta,abs(rs),'-.','LineWidth',2) j!)p NZW.<
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legend('r_p','r_s','|r_p|','|r_s|') uJ\Nga<?
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xlabel('\theta_i') ~Xw?>&
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ylabel('Amplitude') #wiP{+%b
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title(['n_1=',num2str(n1),',n_2=',num2str(n2)]) sdD[`#
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axis([0 90 -1 1]) >#|Yoc
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grid on $SR]7GZ
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subplot(1,2,2); %/zZ~WIf
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plot(theta,tp,'-',theta,ts,'--',theta,abs(tp),':',theta,abs(ts),'-.','LineWidth',2) v{Vesf
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legend('t_p','t_s','|t_p|','|t_s|') E
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xlabel('\theta_i') Ghc0{M<
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ylabel('Amplitude') QGy=JHb
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title(['n_1=',num2str(n1),',n_2=',num2str(n2)]) n.RhA-O
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axis([0 90 0 1]) ppKCY4
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grid on cO&9(.d
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Rp=abs(rp).^2; AAgA]OD,
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Rs=abs(rs).^2; KL]!E ~i
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Rn=(Rp+Rs)/2; _9r{W65s
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Tp=1-Rp; KW^aARJ)
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Ts=1-Rs; kELyD(^P`
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Tn=(Tp+Ts)/2; taaAwTtk?A
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figure(2) HC,@tfS
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subplot(1,2,1); P^W47
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plot(theta,Rp,'-',theta,Rs,'--',theta,Rn,':','LineWidth',2) ?Nql7F4
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legend('R_p','R_s','R_n') HH@xnd
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xlabel('\theta_i') 1s[-2^D+EM
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ylabel('Amplitude') `wd* &vl