What solid angle does that angular pixel represent?
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O!3= 0 g6V*wjC To answer that question we project out from the local axis of the detector to construct a sphere some long distance away from the detector, centered on the detector.
We then (conceptually) fire rays from this point at x, y angles of (5, 40), (5, 41), (6, 41), and (6, 40). Now we know that patch of area, we can compute the solid angle subtended by that angular pixel.
H/$q]i*#K How is Radiant Intensity Defined f/yK|[g~ b ~gF,^w `Nn?G 红色标出的那句是什么意思?
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