ZEMAX中priscription data会给出系统的许多有用的数据，其中包括effective focal length的数据和主平面位置的数据。但是我发现直接给出的effective focal length数据和根据其定义结合主平面的数据算出来的结果不一致，这时怎么回事？ =L F9im
一下是我的Prescription Data数据： ecqL;_{o
GENERAL LENS DATA: p J #<e
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Surfaces : 3 8^U+P%
Stop : 1 Ip&Q'"HYj
System Aperture : Object Space NA = 0.12 5.o{A#/NTl
Glass Catalogs : Schott "i1 r9TLc
Ray Aiming : Paraxial Reference, Cache On 0<4Sw j3s7
X Pupil shift : 0 .`5BgX7W
Y Pupil shift : 0 |.;LI= CT
Z Pupil shift : 0 2[e^mm&.
Apodization : Gaussian, factor = 1.00000E+000 k,M %"FLQ
************************************************************* lRr ={
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Effective Focal Length : 1.639158 (in air at system temperature and pressure) G&f~A;'7k
Effective Focal Length : 1.639158 (in image space) |`c=`xK7'
************************************************************* c_+y~X)i
Back Focal Length : -1.061568 f8 3Tl~
Total Track : 4.318 @, %IVKg\
Image Space F/# : 3.417255 Ix1[ $9
Paraxial Working F/# : 2.950535 N8K @ch3=P
Working F/# : 2.961912 idLCq^jnJ
Image Space NA : 0.1670788 =j$!N# L
Object Space NA : 0.12 DAHQ7#qfQC
Stop Radius : 0.2398355 l We1Q #
Paraxial Image Height : 0 +~] :oj
Paraxial Magnification : 0 ~V?3A/]
Entrance Pupil Diameter : 0.4796709 <&Q(I+^
Entrance Pupil Position : 0 qTd6UKg
Exit Pupil Diameter : 2.511155 0s+pcqOd^
Exit Pupil Position : 7.420935 qt&zo5
Field Type : Angle in degrees 9p '#a:
Maximum Field : 0 ;~
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Primary Wave : 1.31 Ad'b{C%
Lens Units : Millimeters /N?vVp
Angular Magnification : 0 q(YFt* (;w
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Fields : 1 wNt-mgir-Q
Field Type: Angle in degrees yccF#zU
# X-Value Y-Value Weight DTi\ 4&41
1 0.000000 0.000000 1.000000 Dw-i!dq
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Vignetting Factors ^+)q@{\8Y
# VDX VDY VCX VCY VAN Zv8I`/4?
1 0.000000 0.000000 0.000000 0.000000 0.000000 3.vQ~Fvl
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Wavelengths : 1 jh3X G
Units: Microns UC{Tm f
# Value Weight sM0o,l(5
1 1.310000 1.000000 i rRe}
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CARDINAL POINTS: g\O&gNq<)-
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Object space positions are measured with respect to surface 1. +C F"Bm8@
Image space positions are measured with respect to the image surface. y5AJ1A6 ?E
The index in both the object space and image space is considered. 3$hbb6N%6.
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Object Space Image Space V`;$Ua;y
W = 1.310000 (Primary) +&:?*(?Q
************************************************************ us,1:@a)a
Focal Length : -1.639015 1.639015 P
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************************************************************ u^{6U(%
Focal Planes : 0.313078 -1.159568 IC:wof "
Principal Planes : 1.952094 -2.798584 yk< $XNc
Anti-Principal Planes : -1.325937 0.479447 !"e~HZmr
Nodal Planes : 1.952094 -2.798584 Q#$#VT!F
Anti-Nodal Planes : -1.325937 0.479447 tEE1`10Mt
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我用*号，标出了需要注意的地方，请高手指教！
