ZEMAX中priscription data会给出系统的许多有用的数据,其中包括effective focal length的数据和主平面位置的数据。但是我发现直接给出的effective focal length数据和根据其定义结合主平面的数据算出来的结果不一致,这时怎么回事? <J{'o`{
一下是我的Prescription Data数据: ra6o>lI(,
GENERAL LENS DATA: rg QEUDEQ
hOk00az
Surfaces : 3 <4`eQ
Stop : 1 |qN'P}L
System Aperture : Object Space NA = 0.12 eon!CE0
Glass Catalogs : Schott *"{&FEV
Ray Aiming : Paraxial Reference, Cache On KfY$ka[}"S
X Pupil shift : 0 -kj< 1~YW
Y Pupil shift : 0 C"w
{\
&R
Z Pupil shift : 0 Pz"`MB<'Ik
Apodization : Gaussian, factor = 1.00000E+000 t?)pl2!A
************************************************************* TMVryb
Effective Focal Length : 1.639158 (in air at system temperature and pressure) @aG&n(.!u*
Effective Focal Length : 1.639158 (in image space) xN"Z1n7t
************************************************************* C+V*
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Back Focal Length : -1.061568 M>H=z#C>/A
Total Track : 4.318 E~hzh /,34
Image Space F/# : 3.417255 53OJ-m%a
Paraxial Working F/# : 2.950535 8E^@yZo{
Working F/# : 2.961912 *cv}*D
Image Space NA : 0.1670788 *nTU#U
Object Space NA : 0.12 \fLvw
Stop Radius : 0.2398355 Q<"[C
1Lj
Paraxial Image Height : 0 ANMg
Paraxial Magnification : 0 k#JQxLy#
Entrance Pupil Diameter : 0.4796709 0ZI(/r
Entrance Pupil Position : 0 saZ>?Owz
Exit Pupil Diameter : 2.511155 2k
-+^}r
Exit Pupil Position : 7.420935 -X1X)0v$
Field Type : Angle in degrees 4? (W%?
Maximum Field : 0 z; }6f
Primary Wave : 1.31 C;rG]t^%
Lens Units : Millimeters @R2at
Angular Magnification : 0 = (,
^du'
z3?\:Yz
Fields : 1 uGJ"!K
Field Type: Angle in degrees Iw=Sq8
# X-Value Y-Value Weight @xWdO,#
1 0.000000 0.000000 1.000000 hfM;/
40P) 4w
Vignetting Factors n \G Ry'
# VDX VDY VCX VCY VAN WE!vSZ3R
1 0.000000 0.000000 0.000000 0.000000 0.000000 w!3>N"em
cPF<D$B
Wavelengths : 1 ":W%,`@$
Units: Microns >yK0iK{
# Value Weight 0~gO'*2P
1 1.310000 1.000000 `$RA< 3
{I1~-8
CARDINAL POINTS: o|8`>!hF
tpf7_YP_!-
Object space positions are measured with respect to surface 1. g:)DNy
Image space positions are measured with respect to the image surface. 1(dj[3Mt
The index in both the object space and image space is considered. tbDoP
Y
"5|Lz) =
Object Space Image Space ^HA
%q8| n
W = 1.310000 (Primary) ?pGkk=,KB
************************************************************ &*,:1=p
Focal Length : -1.639015 1.639015 o4^Fo p
************************************************************ U bz"rCjq
Focal Planes : 0.313078 -1.159568 OEgI_=B
Principal Planes : 1.952094 -2.798584 v> z@
Anti-Principal Planes : -1.325937 0.479447 Q=cQLf;/'
Nodal Planes : 1.952094 -2.798584 kJK,6mN
Anti-Nodal Planes : -1.325937 0.479447 SAv<&
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我用*号,标出了需要注意的地方,请高手指教!