ZEMAX中priscription data会给出系统的许多有用的数据，其中包括effective focal length的数据和主平面位置的数据。但是我发现直接给出的effective focal length数据和根据其定义结合主平面的数据算出来的结果不一致，这时怎么回事？ RXbZaje$
一下是我的Prescription Data数据： _d3/ ="=
GENERAL LENS DATA: eN
I6V/\`
%|?PG i@5
Surfaces : 3 X57\sggK
Stop : 1 8~h.i1L
System Aperture : Object Space NA = 0.12 )G9, 5[
Glass Catalogs : Schott : WN*wd
Ray Aiming : Paraxial Reference, Cache On Q<Th*t
X Pupil shift : 0 c< g{ &YJ
Y Pupil shift : 0 pS)/yMlVj
Z Pupil shift : 0 q% }54E80
Apodization : Gaussian, factor = 1.00000E+000 fYZ)5xnj
************************************************************* & Pzr)W(
Effective Focal Length : 1.639158 (in air at system temperature and pressure) XiUae{j`
Effective Focal Length : 1.639158 (in image space) 6rzXM`cs
************************************************************* J$i5A9IUr
Back Focal Length : -1.061568 p%y|w
Total Track : 4.318 ;(9q, )
Image Space F/# : 3.417255 ucC' SS
Paraxial Working F/# : 2.950535 cH\.-5NQ
Working F/# : 2.961912 C&KH.h/N
Image Space NA : 0.1670788 e? !A]2
Object Space NA : 0.12 ^T/d34A;SP
Stop Radius : 0.2398355 Yf,U2A\
Paraxial Image Height : 0 #s^~'2^%4
Paraxial Magnification : 0 `zOQ*Y&
Entrance Pupil Diameter : 0.4796709 \P0>TWE
Entrance Pupil Position : 0 |B. tBt^
Exit Pupil Diameter : 2.511155 L(eLxw e%
Exit Pupil Position : 7.420935 Q68q76
Field Type : Angle in degrees *H,vqs\}y
Maximum Field : 0 Ucz`^}+
Primary Wave : 1.31 2q.J1:lW
Lens Units : Millimeters bIahjxd :
Angular Magnification : 0 p_2-(n@
V, )bw
Fields : 1 seEG ~/U<
Field Type: Angle in degrees 8!{F6DG
# X-Value Y-Value Weight x0_ $,Tz@
1 0.000000 0.000000 1.000000 pElAY3
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Vignetting Factors W-+~r
# VDX VDY VCX VCY VAN op|/_I$
1 0.000000 0.000000 0.000000 0.000000 0.000000 =E''$b?Em
%$L!N-U6
Wavelengths : 1 +\n8##oAI
Units: Microns E)w^od wMU
# Value Weight H$i4OQ2
1 1.310000 1.000000 VdV18-ea
=tE7XC3X_
CARDINAL POINTS: yb:Xjg7
B'Ll\<mq@
Object space positions are measured with respect to surface 1. 2-*zevPiG=
Image space positions are measured with respect to the image surface. V.*0k~
The index in both the object space and image space is considered.
*CtO Q
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Object Space Image Space .A`Q!
W = 1.310000 (Primary) 9'|NF<
************************************************************ c~a:i=y67
Focal Length : -1.639015 1.639015 MxO0#
************************************************************ b-rgiR$cg
Focal Planes : 0.313078 -1.159568 o%E^41M7E
Principal Planes : 1.952094 -2.798584 HG/`5$L
+}
Anti-Principal Planes : -1.325937 0.479447 3 ;6Criq}
Nodal Planes : 1.952094 -2.798584 n$fYgZKn
Anti-Nodal Planes : -1.325937 0.479447 IP E2t
k_ ;+z
我用*号，标出了需要注意的地方，请高手指教！
