ZEMAX中priscription data会给出系统的许多有用的数据,其中包括effective focal length的数据和主平面位置的数据。但是我发现直接给出的effective focal length数据和根据其定义结合主平面的数据算出来的结果不一致,这时怎么回事? lA4TWU (]
一下是我的Prescription Data数据: ? ^`fPH=
GENERAL LENS DATA: 6LabFX@{&
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Surfaces : 3 Fj"/jdM
Stop : 1 EIPX q
System Aperture : Object Space NA = 0.12 pB7^l|\]
Glass Catalogs : Schott t~8H~%T>v
Ray Aiming : Paraxial Reference, Cache On 3h}i="i
X Pupil shift : 0 MXDUKh7v3
Y Pupil shift : 0 'p[B`Ft3F
Z Pupil shift : 0 f|~X}R
Apodization : Gaussian, factor = 1.00000E+000 |AS<I4+&
************************************************************* .=9d3uWJ/
Effective Focal Length : 1.639158 (in air at system temperature and pressure) er3`ITp:dp
Effective Focal Length : 1.639158 (in image space) fm
q(!
************************************************************* 4^:$|\?]
Back Focal Length : -1.061568 Q&/WVRD
Total Track : 4.318 3{|]@ L
Image Space F/# : 3.417255 O9AFQ)u
Paraxial Working F/# : 2.950535 s5)y%,E
Working F/# : 2.961912 > iYdr/^a
Image Space NA : 0.1670788 ^$[iLX
Object Space NA : 0.12 }^^c/w_
Stop Radius : 0.2398355 >B;KpO"+m
Paraxial Image Height : 0 [.&n,.k
Paraxial Magnification : 0 |f(*R_R
Entrance Pupil Diameter : 0.4796709 ^sqzlF
Entrance Pupil Position : 0 %.HLO.A
Exit Pupil Diameter : 2.511155 =T1Xfib
Exit Pupil Position : 7.420935 q4,/RZhzh
Field Type : Angle in degrees WuTkYiF
Maximum Field : 0 8]rObT9>
Primary Wave : 1.31 G#A6<e/
Lens Units : Millimeters VmRfnH"
Angular Magnification : 0 DhD##5a
h.NCG96S
Fields : 1 .}:*tvot
Field Type: Angle in degrees V/zmbo)
# X-Value Y-Value Weight gAf4wq
1 0.000000 0.000000 1.000000 @jrxbo;5
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Vignetting Factors :[0)Uu{
# VDX VDY VCX VCY VAN RL fQT_V
1 0.000000 0.000000 0.000000 0.000000 0.000000 ^dE[ ;
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Wavelengths : 1 14*6+~38m&
Units: Microns [70 5[
# Value Weight QS1lg
1 1.310000 1.000000 )<qL8#["U
^Y5I OX:
CARDINAL POINTS: |$~]|SK
wSPmiJ/!
Object space positions are measured with respect to surface 1. +wQ}ZP&
Image space positions are measured with respect to the image surface. [JV?Mdzu
The index in both the object space and image space is considered. $\bVu2&I
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Object Space Image Space (@;^uVJP
W = 1.310000 (Primary) R~fk/T?
************************************************************ u]i%<Yy89
Focal Length : -1.639015 1.639015 bm4Bq>*=U
************************************************************ xvomn`X1
Focal Planes : 0.313078 -1.159568 Wu(^k25
Principal Planes : 1.952094 -2.798584 =E^/gc%X
Anti-Principal Planes : -1.325937 0.479447 gQJLqs"F
Nodal Planes : 1.952094 -2.798584 CF@*ki3X
Anti-Nodal Planes : -1.325937 0.479447 owb+,Gk(
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我用*号,标出了需要注意的地方,请高手指教!