答案: vnz}Pr! c
9n".Q-V;k
average luminance L= Luminous instensity / Emitter_Area =16000cd/ (1.5~2x0.19x0.6)cm^2 =70000cd/cm^2~94000cd/cm^2. TUd=qnu
*icxK
即平均亮度约在70000cd/cm^2~94000cd/cm^2范围,所以specsheet 写90000cd/cm^2是有道理的。 ';x5 $5k'
#+P)X_i`
谨供参考。 JvLa@E)
K:sC6|wG