答案: 5pKvNLy.t
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average luminance L= Luminous instensity / Emitter_Area =16000cd/ (1.5~2x0.19x0.6)cm^2 =70000cd/cm^2~94000cd/cm^2. q|Pt>4c5?
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即平均亮度约在70000cd/cm^2~94000cd/cm^2范围,所以specsheet 写90000cd/cm^2是有道理的。 ~T p8>bmSR
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谨供参考。 6|"!sW`%N
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