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    [讨论]如何分析Ghost focus generator的结果 [复制链接]

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    离线sansummer
     
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    只看楼主 倒序阅读 楼主  发表于: 2011-06-27
    例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html _l9fNf!@  
    IWu=z!mO  
    其中使用Ghost focus generator后的结果为: 6=]Gom&S  
    9oJM?&i  
    Ghost Trace Data
    File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx Mu>  
    Title: A SIMPLE COOKE TRIPLET.
    Units are Millimeters.
    Wavelength: 0.550000 μm A .&c>{B7  
    Type: Double Bounces nSyLt6zn\  
    The '****' denotes a possible internal focus n5kGHL2   
    RMS is the RMS spot radius on axis at the primary wavelength. =F$?`q`  
    RMS values of 0.00 indicate that an accurate RMS eZOR{|z  
    could not be computed, usually due to ray errors.
    This analysis may be inaccurate if the system is 3eE=>E4,  
    non-rotationally symmetric or uses non-standard surfaces.
    Ghost reflection off surface 2 then 1. (GH002001.ZMX) [tk x84M8  
    Surf     Marginal          F/#          RMS neM.M)0  
       1  5.0000E+000     5.737068  3.5355E+000 u!|_bI3  
       2  4.7160E+000     4.595701  3.3570E+000 %]}JWXo f  
       1  4.3614E+000     0.990012  3.1277E+000 Ztmh z_u7  
       2  2.7155E+000     0.607262  1.9876E+000 D/Ki^E  
       3 -2.2309E+000     0.916280  2.6065E+000  Kg';[G\  
       4 -2.7766E+000     0.514753  0.0000E+000 buX(mj:&  
       5 -7.3909E+000     0.888038  0.0000E+000 */h(4Hz  
       6 -9.0530E+000     0.823473  0.0000E+000 Oq~{HJ{  
       7 -3.4681E+001     0.823473  0.0000E+000 m@XX2l9:9  
    Marginal ray height    :       -34.6809 xR0*w7YE  
    Chief ray height       :       -24.8107 S'34](9n6  
    Distance to ghost pupil:       -50.9613 tV(iC~/  
    Distance to ghost focus:       -57.1176 vU,7Y|t`  
    Effective focal length :         8.2347
    > f X^NX  
    请问这个结果怎么看? UUDUd a  
    bK%F_v3'  
    其中:Ghost reflection off surface 2 then 1,什么意思? [T_[QU:A  
    最后的光线高度能用来分析什么?? QD,m`7(  
    Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 w{DU<e:  
    Effective focal length : 8.2347 wA$7SWC  
    这有代表什么,求高手啊
     
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    离线sansummer
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    只看该作者 1楼 发表于: 2011-06-27
    我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? L-E &m*%  
    (9]1p;  
    Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦
    离线superyu2009
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    只看该作者 2楼 发表于: 2011-11-22
    用CODE V分析更好