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    [讨论]如何分析Ghost focus generator的结果 [复制链接]

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    离线sansummer
     
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    只看楼主 正序阅读 楼主  发表于: 2011-06-27
    例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html s=8H< 'l  
    i'ap8Dr  
    其中使用Ghost focus generator后的结果为: z!}E2j_9P  
    dFz"wvu` o  
    Ghost Trace Data
    File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx <h#*wy:o2  
    Title: A SIMPLE COOKE TRIPLET.
    Units are Millimeters.
    Wavelength: 0.550000 μm V*?cMJ_G  
    Type: Double Bounces VF?H0}YSHb  
    The '****' denotes a possible internal focus b| L;*<KU  
    RMS is the RMS spot radius on axis at the primary wavelength. $)M3fZ$#  
    RMS values of 0.00 indicate that an accurate RMS D+7xMT8pqH  
    could not be computed, usually due to ray errors.
    This analysis may be inaccurate if the system is 0*{(R#  
    non-rotationally symmetric or uses non-standard surfaces.
    Ghost reflection off surface 2 then 1. (GH002001.ZMX) \J^#2{d  
    Surf     Marginal          F/#          RMS ;.}L# '0j  
       1  5.0000E+000     5.737068  3.5355E+000 &N} "4  
       2  4.7160E+000     4.595701  3.3570E+000 qb"S   
       1  4.3614E+000     0.990012  3.1277E+000 x9l7|G/$  
       2  2.7155E+000     0.607262  1.9876E+000 i2<z"v63  
       3 -2.2309E+000     0.916280  2.6065E+000 o}AXp@cqi  
       4 -2.7766E+000     0.514753  0.0000E+000 alb3oipOB  
       5 -7.3909E+000     0.888038  0.0000E+000 R$&;  
       6 -9.0530E+000     0.823473  0.0000E+000 NW\CEJV  
       7 -3.4681E+001     0.823473  0.0000E+000 VX)8 pV$  
    Marginal ray height    :       -34.6809 Xh"9Bcjf  
    Chief ray height       :       -24.8107 't<iB&wgF  
    Distance to ghost pupil:       -50.9613 "| '~y}v_  
    Distance to ghost focus:       -57.1176 ? }HK!feU  
    Effective focal length :         8.2347
    'va[)~!  
    请问这个结果怎么看? 3&-rOc  
    $f:uBhM  
    其中:Ghost reflection off surface 2 then 1,什么意思? {hS!IOM  
    最后的光线高度能用来分析什么?? OUulG16kK  
    Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 YSnh2 Bq  
    Effective focal length : 8.2347 LHY7_"u#  
    这有代表什么,求高手啊
     
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    离线superyu2009
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    只看该作者 2楼 发表于: 2011-11-22
    用CODE V分析更好
    离线sansummer
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    只看该作者 1楼 发表于: 2011-06-27
    我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? J^8j|%h%e  
    UBd+,]"f  
    Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦