切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 9363阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: aU +uPP  
    sfG9R"  
    rfdA?X{Q0  
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: ctgH/SU  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) 'bji2#z[  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 UHl1>(U  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 qsN}KgTjg  
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: 5',b~Pp  
    1.判断点在区域中函数 "g!/^A!!  
    2.计算夹角函数 Y^?PHz'Go  
    3.转置函数 3z 5"Ckzb  
    4.得到区域中心点,及区域半径函数 )]}68}9  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) Q|Pm8{8  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 n22OPvp  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single ?7*J4.  
       cax = x2 - x1 28,HZaXhc  
       cay = y2 - y1 ;xE1#ZT  
       cbx = x2 - x3 ?rwHkPJ{*  
       cby = y2 - y3 +Kg3qS"  
       mo_jj = cax * cbx + cay * cby )% ?SWuS?N  
       mo_ca = Sqr(cax * cax + cay * cay) H`U>ZJ.  
       mo_cb = Sqr(cbx * cbx + cby * cby) (7P VfS>;  
       cos_acb = mo_jj / (mo_ca * mo_cb) Bk4|ik}  
       'ff_cos = cos_acb <C7/b#4>\  
       If cos_acb >= 1 Then p["20 ?^  
       nn = 0 h6gtO$A|p=  
       ElseIf cos_acb <= -1 Then `XwKCI  
       nn = 3.14159265258979 fPsUIlI/A  
       Else [%7oq;^J  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) .`N&,&H  
       End If oth=#hfU^  
       'ff_angle = nn Ru`7Xd.  
       ff_angle = nn * 180 / 3.14159265258979 U[l{cRT   
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 `BZX\LPHm  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean \rf2O s  
    Dim aob, boc, cod, doa, sum As Single +LAjh)m  
      If ppx = p1x And ppy = p1y Then <</ Le%  
         point_in = True f<~S0[H  
         Exit Function *+'l|VaVq\  
      End If VYN1^Tp  
      If ppx = p2x And ppy = p2y Then &8wluOs/5  
         point_in = True n*fsdo~  
         Exit Function Gj([S17\0:  
      End If ;;l-E>X0  
       If ppx = p3x And ppy = p3y Then E#cZM>  
         point_in = True dy*CDRU4  
         Exit Function #EdsB  
      End If eMC0 )B  
         #>\+6W17U  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) 0?nm`9v6  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) -( ,iwF b  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) ]):kMRv  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) G_a//[p  
        sum = aob + boc + cod + doa {]\!vG6  
        If 360.01 > sum And sum > 359.99 Then C %o^AR  
           point_in = True Tb6c]?'U  
        Else ~'l.g^p bv  
           point_in = False ?]L:j  
        End If 0if~qGm=!  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 ;tF7 GjEp  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() SrVJ Q~ :>  
        '求得中心点坐标 3%W R  
    Dim tt As String c*g(R.!  
    Dim rt(3) As Single U\A*${  
        '判断是否平行 Lc<C1I 5=  
       acx = p3x - p1x E}$K&<J'-  
       acy = p3y - p1y 85fBKpEe  
       bdx = p4x - p2x `_;VD?")*l  
       bdy = p4y - p2y Wh)QCp0|n  
       If acx * bdy = acy * bdx Then _YH)E^If  
          rt(0) = 0 YrR}55V,  
          Exit Function m{bw(+r  
       Else b)A$lP%`  
          '判断斜率存在否 =kspHP<k  
          If p1x = p3x And p2x <> p4x Then AdtAc$@xK  
             tt = "ac_n_bd_y" 7='M&Za  
          ElseIf p1x <> p3x And p2x = p4x Then @Ooh}V#J  
             tt = "ac_y_bd_n" m*BtD-{  
          ElseIf p1x <> p3x And p2x <> p4x Then }>w;(R  
             tt = "ac_y_bd_y" *HwTq[y  
          End If q lL6wzq,  
        Select Case tt l\yFx  
             Case "ac_n_bd_y" #isBE}sT{  
                'bd线段方程 j!;?=s  
                k_bd = bdy / bdx .s_wP  
                b_bd = p2y - k_bd * p2x H! ZPP8]j>  
                p_x = p1x ?hS n)  
                p_y = k_bd * p_x + b_bd 3H%oTgWk  
             Case "ac_y_bd_n" g|PVOY+|^  
                'ac线段方程 7K`A2  
                k_ac = acy / acx 3`&2 -  
                b_ac = p1y - k_ac * p1x 7 3k3(rZ  
                p_x = p2x Aov=qLWJ  
                p_y = k_ac * p_x + b_ac -, ~n|ceI  
            Case "ac_y_bd_y" DiAPs_@  
               'ac,bd线段都要求 )ll`F7B-  
               k_ac = acy / acx >Z?3dM~[  
               b_ac = p1y - k_ac * p1x J*8fGR%  
               k_bd = bdy / bdx /0 ,#c2aq  
               b_bd = p2y - k_bd * p2x ?R0sY ?u  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) M[0@3"}}  
               p_y = k_ac * p_x + b_ac aT#R#7<Eg  
            End Select H;<hmbN?d  
          rt(1) = p_x ' hL\xf{  
          rt(2) = p_y 6ZVJ2xs[%  
         +gTnq")wnI  
    '计算最大半径 A8OV3h6]  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) #`/KF_a3\>  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) nVoPTr  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) zQ}:_  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) {vAq08  
    Dim bb(5) As Single @7%nMTZ@&v  
      bb(1) = rr1 ocy fU=}X  
      bb(2) = rr2 kzGD *  
      bb(3) = rr3 Nl7"|()e  
      bb(4) = rr4 >U9*  
      nb = rr1 pHY~_^B4&  
    For i = 1 To 4 O'" &9  
        If nb <= bb(i) Then 8J%^gy>m]  
           nb = bb(i) 1P4jdp=~  
        End If V2%FWo|  
    Next i :t]YPt  
        rt(0) = Sqr(nb) <?,o {  
        rr = rt() &@A(8(%  
      End If 5 %q26&  
             }}Eko7'^  
    End Function
    离线lifei0715
    发帖
    1235
    光币
    8293
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  > F&Wuf  
    !uii|"  
    有热压工艺方面的人才或者资料分享下; H*!j\|v0  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 [2gK^o&t  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.