切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 9124阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: <[7.+{qfW  
    cv["Ps#;`W  
    uIvE~<  
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: m>'sM1s  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) ;p#)z/zZ  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 T?c:z?j_9  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 DxT8;`I%  
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: &/4W1=>(  
    1.判断点在区域中函数 ?*a:f"vQ  
    2.计算夹角函数 FMuM:%&J]  
    3.转置函数 : \w\K:  
    4.得到区域中心点,及区域半径函数 Dm[4`p@IY\  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) A\_cGM2  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 jx&pRjP  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single GH![rK  
       cax = x2 - x1 j9sf~}D>  
       cay = y2 - y1 [Zk|s9  
       cbx = x2 - x3 !L+*.k:  
       cby = y2 - y3 vW 0m%  
       mo_jj = cax * cbx + cay * cby yK<%AV@v  
       mo_ca = Sqr(cax * cax + cay * cay) 52BlFBNV  
       mo_cb = Sqr(cbx * cbx + cby * cby) {mMrD 5  
       cos_acb = mo_jj / (mo_ca * mo_cb) :Q=Jn?Gjb  
       'ff_cos = cos_acb IDb|J%e^P  
       If cos_acb >= 1 Then . Yg)|/  
       nn = 0 0}k[s+^  
       ElseIf cos_acb <= -1 Then n3-u.Fb  
       nn = 3.14159265258979 vAi kd#C)  
       Else ?ZDXT2b~~  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) &""~Pn8  
       End If G:$wdT(u  
       'ff_angle = nn [>Kkj;*  
       ff_angle = nn * 180 / 3.14159265258979 xCD|UC46?X  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 @kn0f`  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean mF [w-<:.d  
    Dim aob, boc, cod, doa, sum As Single i2A>T/?{  
      If ppx = p1x And ppy = p1y Then "?hEGJ;m"  
         point_in = True &!vJ3:  
         Exit Function s={AdQ  
      End If /cUcfe#X  
      If ppx = p2x And ppy = p2y Then J5}-5sV^  
         point_in = True gYfN ?A*`_  
         Exit Function c 's=>-X  
      End If R$4&>VBu  
       If ppx = p3x And ppy = p3y Then ~mx me6"v  
         point_in = True DTk)Y-eQ  
         Exit Function Mb=vIk{B f  
      End If ]d}Z2I'  
         >nkd U  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) So\(]S  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) [WnX'R R  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) <Vm+Lt9  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) 2@@OjeANsX  
        sum = aob + boc + cod + doa -mOSB(#bo  
        If 360.01 > sum And sum > 359.99 Then }BS.OK?  
           point_in = True iXK.QktHw  
        Else r4k =i4  
           point_in = False Nt9M$?\P  
        End If ByoSwQ  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 )1wC].RFYm  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() :2iNw>z1  
        '求得中心点坐标 NypM+y  
    Dim tt As String >Lx,<sE  
    Dim rt(3) As Single #'fh'$5"  
        '判断是否平行 |9T3" _MmJ  
       acx = p3x - p1x losm<  
       acy = p3y - p1y Ppi/`X  
       bdx = p4x - p2x je@F:5  
       bdy = p4y - p2y 16ahU$@-  
       If acx * bdy = acy * bdx Then $$ouqLu  
          rt(0) = 0 8TGO6oY+=  
          Exit Function _^;+_6&[  
       Else {I0b%>r=  
          '判断斜率存在否 pQAG%i^mF  
          If p1x = p3x And p2x <> p4x Then a~E@scD  
             tt = "ac_n_bd_y" )zz^RB\p  
          ElseIf p1x <> p3x And p2x = p4x Then ;[TC`DuNj0  
             tt = "ac_y_bd_n" 1$T;u~vg  
          ElseIf p1x <> p3x And p2x <> p4x Then yH5^EY7rQ  
             tt = "ac_y_bd_y" $51M' Qu  
          End If `!WtKqr%B  
        Select Case tt P,U$ X+  
             Case "ac_n_bd_y" qpzzk9ba[  
                'bd线段方程 f.8Jp<S2K  
                k_bd = bdy / bdx |^9+c2   
                b_bd = p2y - k_bd * p2x l?Vm/YXb  
                p_x = p1x (?R;u>  
                p_y = k_bd * p_x + b_bd s+IU%y/9$a  
             Case "ac_y_bd_n" A/V"&H[  
                'ac线段方程 "~-H]9  
                k_ac = acy / acx &AM<H}>  
                b_ac = p1y - k_ac * p1x VQ wr8jXye  
                p_x = p2x u"eO&Vc  
                p_y = k_ac * p_x + b_ac vM )2F  
            Case "ac_y_bd_y" z{XN1'/V  
               'ac,bd线段都要求 "c5C0 pK0  
               k_ac = acy / acx -}avH  
               b_ac = p1y - k_ac * p1x OiBDI3,|+  
               k_bd = bdy / bdx ms9zp?M  
               b_bd = p2y - k_bd * p2x W*?mc2;/  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) Mx? ]7tI  
               p_y = k_ac * p_x + b_ac n.9k<  
            End Select |m{Q_zAB  
          rt(1) = p_x Z9P rw/8P  
          rt(2) = p_y qZw4"&,j$  
         >d#oJ?goX  
    '计算最大半径 }xhat,9  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) Gt;@. jY&  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) :eIPPh|\  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) 'lmZ{a6  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) %f??O|O3  
    Dim bb(5) As Single F>N3GPRl  
      bb(1) = rr1 V.<$c1#=$  
      bb(2) = rr2 vn oI.;H,  
      bb(3) = rr3 :(IP rQ  
      bb(4) = rr4 o=/Cje  
      nb = rr1 X( Q*(_  
    For i = 1 To 4 jvfVB'Tmr  
        If nb <= bb(i) Then &qR1fbw"  
           nb = bb(i) iV+'p->/  
        End If +Smt8O<N  
    Next i -anLp8G*  
        rt(0) = Sqr(nb) OPm ?kr  
        rr = rt() g;p]lVx=>  
      End If ?l\1n,!:8  
             ~vf&JH'!  
    End Function
    离线lifei0715
    发帖
    1224
    光币
    8234
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  %EPqJ(T  
    (l 2 2p  
    有热压工艺方面的人才或者资料分享下; ?o0#h  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 ` w Sg/  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.