切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 10447阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: !Y7$cU &  
    |JWYsqJ0U  
    wxj}k7_(`A  
    本主题包含附件,请 登录 后查看, 或者 注册 成为会员
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: eX}aa0  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) T@#?{eA  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了  < ]+Mdy  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 BzWkZAX  
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: `r3 klL,W'  
    1.判断点在区域中函数 Pw7uxN`  
    2.计算夹角函数 %0}}Qt  
    3.转置函数 wS&D-!8v  
    4.得到区域中心点,及区域半径函数 k&f/f  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) C|w<mryx  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 t# y,9>6  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single l`:u5\ rM  
       cax = x2 - x1 N$C+le  
       cay = y2 - y1 |4 2;171  
       cbx = x2 - x3 R)*l)bpZ#  
       cby = y2 - y3 *vIP\NL?H  
       mo_jj = cax * cbx + cay * cby "zQ<)Q]U  
       mo_ca = Sqr(cax * cax + cay * cay) #9.%>1{6Y  
       mo_cb = Sqr(cbx * cbx + cby * cby) Ij =NcP  
       cos_acb = mo_jj / (mo_ca * mo_cb) vx ' ];  
       'ff_cos = cos_acb 6Uq;]@k%  
       If cos_acb >= 1 Then JEWc{)4QD  
       nn = 0 #G`K<%{?f  
       ElseIf cos_acb <= -1 Then >#l: ]T  
       nn = 3.14159265258979 `"yxmo*0  
       Else W+U0Y,N6  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) XE2rx2k  
       End If v#<{Y' K  
       'ff_angle = nn JXq!v:w6  
       ff_angle = nn * 180 / 3.14159265258979  (#O"  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 !.t D.(XP  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean *mJ#|3I<  
    Dim aob, boc, cod, doa, sum As Single $M!iQ"bb  
      If ppx = p1x And ppy = p1y Then /3SEu(d!  
         point_in = True (y&sUc9  
         Exit Function N|>JLZ>  
      End If }mIN)o  
      If ppx = p2x And ppy = p2y Then 9Oq(` 4  
         point_in = True #>,E"-]f  
         Exit Function AJ& j|/  
      End If f8N* [by  
       If ppx = p3x And ppy = p3y Then (U# Oj"  
         point_in = True 8-k`"QI=  
         Exit Function JN`$Fq+  
      End If #ley3rJW]  
         A?}[rM Z  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) C#yRop_d]o  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) =H;'.!77Hx  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) /J/V1dC}]D  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) GI,TE  
        sum = aob + boc + cod + doa [XDV-6KCE.  
        If 360.01 > sum And sum > 359.99 Then \-[bU6\A\  
           point_in = True ~"J1 @<  
        Else } eHxw+.  
           point_in = False oPni4^g i  
        End If _kMHF  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 jN*wbqL  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() /!?Tv8TPp  
        '求得中心点坐标 js Z"T  
    Dim tt As String &oHr]=xA  
    Dim rt(3) As Single 32SkxcfrCK  
        '判断是否平行 ^p9V5o  
       acx = p3x - p1x W#NZnxOX"  
       acy = p3y - p1y |nnFjGC`~  
       bdx = p4x - p2x myN2G?>;  
       bdy = p4y - p2y sZr \mQ~  
       If acx * bdy = acy * bdx Then X`WS&!C<  
          rt(0) = 0 |? fAe {*  
          Exit Function V59!}kel1%  
       Else $t}W,?   
          '判断斜率存在否 L?j<KW  
          If p1x = p3x And p2x <> p4x Then oi,KA  
             tt = "ac_n_bd_y" u pUJF`3  
          ElseIf p1x <> p3x And p2x = p4x Then 0uW)&>W  
             tt = "ac_y_bd_n" '/ Hoq  
          ElseIf p1x <> p3x And p2x <> p4x Then Fv %@k{  
             tt = "ac_y_bd_y" ?Sa,n^b*H  
          End If C R?}*  
        Select Case tt $b{8 $<;9  
             Case "ac_n_bd_y" t1mG]  
                'bd线段方程 \ctzv``/n  
                k_bd = bdy / bdx *aWh]x9TlU  
                b_bd = p2y - k_bd * p2x MnF|'t  
                p_x = p1x p"~@q}3  
                p_y = k_bd * p_x + b_bd /<$|tp\Rc  
             Case "ac_y_bd_n" 4~$U#$u_  
                'ac线段方程  + @f  
                k_ac = acy / acx ^%Cd@!dk  
                b_ac = p1y - k_ac * p1x 7_qsVhh]$E  
                p_x = p2x oPaoQbR(A  
                p_y = k_ac * p_x + b_ac XP}5i!}}7=  
            Case "ac_y_bd_y" dz/fSA  
               'ac,bd线段都要求 ^OIo  
               k_ac = acy / acx dnwzf=+>e  
               b_ac = p1y - k_ac * p1x W?E,"z  
               k_bd = bdy / bdx w_@{v wM$A  
               b_bd = p2y - k_bd * p2x n7Eh!<  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) }b}jw.2Wu  
               p_y = k_ac * p_x + b_ac .6 0yQ[aE  
            End Select z2,NWmP|w  
          rt(1) = p_x -#/DK   
          rt(2) = p_y nFGX2|d  
         R_GA`U\ {  
    '计算最大半径 K,|3?CjS  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) P{`fav  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) C Q iHk  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) eX"Ecl{  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) ELMz~vp  
    Dim bb(5) As Single #`%S[)RT  
      bb(1) = rr1 S[/udA   
      bb(2) = rr2 . a @7  
      bb(3) = rr3 O_th/hl  
      bb(4) = rr4 wG)[Ik6:  
      nb = rr1 D aHbOs_<  
    For i = 1 To 4 :PY8)39@K  
        If nb <= bb(i) Then ~-lUS0duh  
           nb = bb(i) ]|w~{X!b4  
        End If p= x &X~  
    Next i !XI9evJw  
        rt(0) = Sqr(nb) z4(\yx  
        rr = rt() Wrp+B[ {r\  
      End If T>#~.4A0  
             rZ-< Ryg  
    End Function
    离线lifei0715
    发帖
    1256
    光币
    8545
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  >T0`( #Lm  
    s+&0Z3+  
    有热压工艺方面的人才或者资料分享下; /"~UGn]R  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 t pxk8Ys  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.