切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 9999阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: OgC,oj,!/  
    ?nbu`K6T  
    La '6k  
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: YVgH[-`,  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) s2|.LmC3|B  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 =7H\llL4BC  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 3c,4 wyn  
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: &oHr]=xA  
    1.判断点在区域中函数 m;{HlDez  
    2.计算夹角函数 rXMc0SPk  
    3.转置函数 IO 0nT  
    4.得到区域中心点,及区域半径函数 p_&B+ <z  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) f+s)A(?3  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 71P. 9Iz  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single Q%?%zuU  
       cax = x2 - x1 s[h;9 I1w  
       cay = y2 - y1 uM\\(g}  
       cbx = x2 - x3 Kg>B$fBx)  
       cby = y2 - y3 XXA'B{@Y)  
       mo_jj = cax * cbx + cay * cby !> +Lre@  
       mo_ca = Sqr(cax * cax + cay * cay) 5EI"5&`*  
       mo_cb = Sqr(cbx * cbx + cby * cby) +2 oZML  
       cos_acb = mo_jj / (mo_ca * mo_cb) $V?sD{=W  
       'ff_cos = cos_acb RfD#/G3|  
       If cos_acb >= 1 Then W% Lrp{  
       nn = 0 VWK/(>TP  
       ElseIf cos_acb <= -1 Then F}meKc?a  
       nn = 3.14159265258979 u1u;aG  
       Else {fl[BX]kZ  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) &1^~G0 Rh\  
       End If Z`GEF|eh  
       'ff_angle = nn %@)q=*=y  
       ff_angle = nn * 180 / 3.14159265258979 iM:-750n/  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 \eQPv kx2  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean A=|a!N/  
    Dim aob, boc, cod, doa, sum As Single G"u4]!$/  
      If ppx = p1x And ppy = p1y Then mSu$1m8  
         point_in = True *)^ ZUk  
         Exit Function g +gcH  
      End If 3PRU  
      If ppx = p2x And ppy = p2y Then ip{ b*@K  
         point_in = True lnjs{`^  
         Exit Function tq'hiS(b  
      End If z4(\yx  
       If ppx = p3x And ppy = p3y Then Wrp+B[ {r\  
         point_in = True T>#~.4A0  
         Exit Function rZ-< Ryg  
      End If }.9a!/@Aj  
         qyKR]%yzi  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) 4Jc~I  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) MwSfuP  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) 7iM@BeIf  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) Q7v1xBM  
        sum = aob + boc + cod + doa  g;AW  
        If 360.01 > sum And sum > 359.99 Then 09Eg ti.  
           point_in = True P()W\+",n  
        Else 2MYez>D  
           point_in = False y ,`0f|  
        End If E U RKzJk  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 N;!!*3a9=  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() KX cRm)  
        '求得中心点坐标 bi@'m?XwJ  
    Dim tt As String !lsa5w{  
    Dim rt(3) As Single 4u41M,nJQd  
        '判断是否平行 N,VI55J:y>  
       acx = p3x - p1x -Ks)1w>l  
       acy = p3y - p1y tr/.pw6  
       bdx = p4x - p2x -*T0Cl.  
       bdy = p4y - p2y ]{+Y!tD  
       If acx * bdy = acy * bdx Then *(]ZdB_2  
          rt(0) = 0 q?]KZ_a  
          Exit Function .V_5q:tu  
       Else QpoC-4F  
          '判断斜率存在否 K g.O2F77  
          If p1x = p3x And p2x <> p4x Then 7'{Vh{.  
             tt = "ac_n_bd_y" #NL'r99D/o  
          ElseIf p1x <> p3x And p2x = p4x Then TPKD'@:x  
             tt = "ac_y_bd_n" uocFOlU0n  
          ElseIf p1x <> p3x And p2x <> p4x Then }K,3SO(:  
             tt = "ac_y_bd_y" r5(efTgAd+  
          End If D ZH2U+K  
        Select Case tt 1Id"|/b%$  
             Case "ac_n_bd_y" swJQwY   
                'bd线段方程 $cm 9xW&  
                k_bd = bdy / bdx Wy/h"R\=  
                b_bd = p2y - k_bd * p2x \GioSg  
                p_x = p1x a gL@A  
                p_y = k_bd * p_x + b_bd mC(YO y  
             Case "ac_y_bd_n" EaL>~: j  
                'ac线段方程 {/aHZ<I&^h  
                k_ac = acy / acx 01RW|rN  
                b_ac = p1y - k_ac * p1x {9XNh[NbP  
                p_x = p2x I};*O6D`  
                p_y = k_ac * p_x + b_ac +/M%%:>mY  
            Case "ac_y_bd_y" ;3bUgI}.J  
               'ac,bd线段都要求 u'DpZ  
               k_ac = acy / acx [io|qLr}\  
               b_ac = p1y - k_ac * p1x ;$4&Qp:#  
               k_bd = bdy / bdx R)isWw4  
               b_bd = p2y - k_bd * p2x 0&2`)W?9  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) Xi\c>eALO  
               p_y = k_ac * p_x + b_ac SdnO#J}{  
            End Select 0B}2~}#  
          rt(1) = p_x }*qj,8-9  
          rt(2) = p_y IAe/)  
         G!%8DX5  
    '计算最大半径 C 'Y2kb  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) !<~cjgdx  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) /J&DYxl":  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) b8vZ^8tBV  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) fl2XI=[v4  
    Dim bb(5) As Single E2>+V{TF  
      bb(1) = rr1 /Ah&d@b  
      bb(2) = rr2 N&Ho$,2s  
      bb(3) = rr3 0O*kC43E_  
      bb(4) = rr4 n;>=QG -v  
      nb = rr1 9ZY,T]ym?  
    For i = 1 To 4 9zIqSjos"  
        If nb <= bb(i) Then P4/~_$e  
           nb = bb(i) %so{'rQl  
        End If A&WC})H5  
    Next i E7aG&K  
        rt(0) = Sqr(nb) =1,1}OucP  
        rr = rt() ev_'.t'  
      End If kBoQjOV`  
             ~gNFcJuy  
    End Function
    离线lifei0715
    发帖
    1237
    光币
    8444
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  0.w7S6v|&  
    n_9Ex&?e  
    有热压工艺方面的人才或者资料分享下; nw%`CnzT  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 2{vAs  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.