切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 9931阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: </{Zb.  
    yV!4Im.>  
    2K91E}  
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: 4k;FZo]S  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) NUFz'MPv  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 'Rn-SD~gIr  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 ?bB>}:~j)  
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: ^c\O , *:  
    1.判断点在区域中函数 &kg^g%%  
    2.计算夹角函数 RV~fml9c  
    3.转置函数 IOl_J>D]F  
    4.得到区域中心点,及区域半径函数 fu "cX;  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) Hf`i~6  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 +U o NJ   
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single YN8x|DLi?  
       cax = x2 - x1 UR sx>yx  
       cay = y2 - y1 U#3N90,N=  
       cbx = x2 - x3 axC|,8~tq  
       cby = y2 - y3 *()['c#CC  
       mo_jj = cax * cbx + cay * cby ],]Rv#`  
       mo_ca = Sqr(cax * cax + cay * cay) %B%_[<B  
       mo_cb = Sqr(cbx * cbx + cby * cby) cJo%j -AM  
       cos_acb = mo_jj / (mo_ca * mo_cb) /Y0~BQC7!  
       'ff_cos = cos_acb 0?7yM:!l  
       If cos_acb >= 1 Then -n _Y.~  
       nn = 0 H/D=$)3op  
       ElseIf cos_acb <= -1 Then P<]U  
       nn = 3.14159265258979 J>Ar(p  
       Else AFAg3/  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) $J7V]c*-b  
       End If ,!:c6F+  
       'ff_angle = nn  FOiwA.:0  
       ff_angle = nn * 180 / 3.14159265258979 d0aXA+S%  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 #HcQ*BiF3  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean B {Cm`f8E  
    Dim aob, boc, cod, doa, sum As Single @M'k/jl  
      If ppx = p1x And ppy = p1y Then G@7^M}  
         point_in = True c9|4[_&B~  
         Exit Function UFB|IeX?q  
      End If ?{J1&;j*  
      If ppx = p2x And ppy = p2y Then \RDN_Z  
         point_in = True tV++QC7@L  
         Exit Function /uw@o9`~2-  
      End If yhH2b:nY(9  
       If ppx = p3x And ppy = p3y Then lS=YnMs6a  
         point_in = True ZX_QnSNZ?  
         Exit Function Q7+WV`&  
      End If 7?fgcb3  
         wkt4vE87  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) nDrRK  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) Il =6t  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) eXl?f_9  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) c^|8qvS $  
        sum = aob + boc + cod + doa }u^bTR?3  
        If 360.01 > sum And sum > 359.99 Then 2zj` H9  
           point_in = True Hca(2 ]T-  
        Else  <$nPGz)}  
           point_in = False Q 8]X  
        End If fN9{@)2Mz  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 as:=QMV  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() tN{0C/B9  
        '求得中心点坐标 O!Ue0\1Kj0  
    Dim tt As String Yyk~!G/@  
    Dim rt(3) As Single }Z <I%GT  
        '判断是否平行 >D=X Tgqqq  
       acx = p3x - p1x X}[1Y3~y  
       acy = p3y - p1y l"8g9z  
       bdx = p4x - p2x QmBHD;Gf  
       bdy = p4y - p2y #|\|G3Si %  
       If acx * bdy = acy * bdx Then 0+0 Y$;<  
          rt(0) = 0 D u<P^CE  
          Exit Function ?3DL .U{  
       Else iu{y.}?  
          '判断斜率存在否  !5 S#  
          If p1x = p3x And p2x <> p4x Then 0Cc3NNdz  
             tt = "ac_n_bd_y" `c:r`Oi?  
          ElseIf p1x <> p3x And p2x = p4x Then S> Fb'rJ3  
             tt = "ac_y_bd_n" OBFM70K  
          ElseIf p1x <> p3x And p2x <> p4x Then R1*&rjB  
             tt = "ac_y_bd_y" NiG&Lw*8  
          End If s\.r3U&6  
        Select Case tt ;4+z~7Je]^  
             Case "ac_n_bd_y" c'$y_]  
                'bd线段方程 PR;Bxy  
                k_bd = bdy / bdx +46& Zb35  
                b_bd = p2y - k_bd * p2x DI{Qs[  
                p_x = p1x V^(W)\  
                p_y = k_bd * p_x + b_bd s#~VN;-I  
             Case "ac_y_bd_n" !le#7Kii  
                'ac线段方程 + fvVora  
                k_ac = acy / acx FkMM>X  
                b_ac = p1y - k_ac * p1x ZrYRLg  
                p_x = p2x uToi4]w"y  
                p_y = k_ac * p_x + b_ac %5ov!nm7  
            Case "ac_y_bd_y" *o=Z~U9z  
               'ac,bd线段都要求 Sn97DCdk  
               k_ac = acy / acx :4:U\k;QwA  
               b_ac = p1y - k_ac * p1x KjA7x  
               k_bd = bdy / bdx $1X !Ecq_  
               b_bd = p2y - k_bd * p2x ~Q- /O~  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) KYhL}C+  
               p_y = k_ac * p_x + b_ac +o.#']}Pl  
            End Select uxW |&q  
          rt(1) = p_x %PVu>^  
          rt(2) = p_y 1\TkI=N3  
         HELTL$j,b  
    '计算最大半径 @$b7 eu  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) rl"yE=  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) Vl7V?`_4  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) 98}l`J=i  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) Nj;(QhYZ  
    Dim bb(5) As Single tjZS:@3 Z  
      bb(1) = rr1 T5[(vTp  
      bb(2) = rr2 r*7J#M /  
      bb(3) = rr3 IFSIQ q  
      bb(4) = rr4 gd)VL}k  
      nb = rr1 d.snD)X  
    For i = 1 To 4 N,)rrBD  
        If nb <= bb(i) Then y_IF{%i  
           nb = bb(i) i;2V   
        End If 4YMUkwh  
    Next i Ud-c+, xX  
        rt(0) = Sqr(nb) Swv =gu  
        rr = rt() m,J9:S<5;  
      End If C-2#-{<  
             gZ (\/m8Z  
    End Function
    离线lifei0715
    发帖
    1236
    光币
    8439
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  kEM|;&=_  
    m&8'O\$  
    有热压工艺方面的人才或者资料分享下; !@kwHJkv  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 iwnFCZVS  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.