[求助]请教：Tracepro中照度图选项中选择归一化和不选择归一化选项有什么区别？ [复制链接]

在Tracepro的照度图选项中有一项“Normalize to emitted flux”，选择和不选择的情况出来的照度图有什么区别？哪位能详细解答一下。 K{.s{;#  

说明书：规范从所有发光源发出的所有出射通量给图的数据，这个选项允许你使通量和光照规范为总共的通量，如果这个框被选中后，TracePro在光照度图中使用出色通量来除以总通量。这对于在光学系统计算的系统透射率和照明系统中计算发光效率，会非常有用。 \HLI y  
也就是说，比如你的总光源有10lm，得出的照度图在没有选择norm～选项的时候是显示正常的照度，在勾选了之后显示的照度值是原来的/总流明，可以认为是没流明所产生的照度值

谢谢版主的耐心解答，^_^

suezl9 Rn~FCj,-  
哈哈

有中文说明书么？可以共享一下么？

Normalize qb(#{Sw0  
Normalize the map data to the total emitted flux from all sources. .w/#S-at  
This option allows you to have the flux and irradiance normalized to the total >C y  
emitted flux. When this box is checked, TracePro divides the values in the r`XIn#o  
irradiance map and the total flux by the emitted flux. This is especially useful for |7]7~ 6l  
calculating system transmittance for an optical system, or lighting efficiency for a WXu:mv,'e  
lighting calculation. tW53&q\=  
Example 1: System Transmittance UMwB.*  
Suppose you need to calculate the system transmittance of an optical system. 7)$U>|=  
You would probably use the grid raytrace option, and the emitted flux is equal to 0cZyO$.  
the sum of the flux in all the emitted rays. When you display an irradiance map, ;l> xXSB7$  
the system transmittance is equal to the total flux, displayed at the bottom of the $fhrGe  
irradiance map window, divided by the emitted flux. To get the system Dww]D|M  
transmittance, check the Normalize to emitted flux box and press the Apply @;kw6f:{d  
button. The map will be redisplayed, and the Normalized Flux value will be equal q9.)p  
to the system transmittance. au7%K5  
Example 2: Lighting Efficiency (Z5=GJM?$  
Suppose you need to calculate the lighting efficiency of a luminaire in illuminating F{)YdqQ  
a plane. You would probably choose the Surface Source raytrace option, and the 2 P+RfE`o  
emitted flux is equal to the flux you specified when you defined the sources. When ;Q&38qI  
you display an irradiance map, the total flux incident on the observation plane is u8qL?Aj^  
displayed at the bottom of the window. The lighting efficiency is equal to the total O-Hu:KuIf  
flux divided by the emitted flux. To get the lighting efficiency directly, check the {9U<!  
Normalize to emitted flux box and press the Apply button. The map will be /Y5I0Ko Uw  
redisplayed, and the Normalized Flux value will be equal to the lighting efficiency 'E
U{%\qM  
of the luminaire.

可以看成均匀性吗？