y=0 kEP<[K
declare X, double, 1,10 8Z8Y[p
|^Kjz{
X(1)=(5) ch })ivFP[
X(2)=(-6) 9g]M4*?C9P
X(3)=(98) "8/dD]=f^a
X(4)=(-1) >r}Vf9 5[N
X(5)=(3) h(N=V|0
X(6)=(-8) vgThK9{m;
X(7)=(1) 9@y3IiZ"}
X(8)=(-5) XU9'Rfp
X(9)=(4) Le@?
/
X(10)=(-3) Ue7 6py9
%?=)!;[
RL&lKHA
for a,1,10,1 OKPJuV`y6
if X(a)<y then y=X(a) d)KF3oA
else y=y i!,HB|wQ
endif m
=k%,J_
print X(a)," ",y ;J=:IEk
next .
#U}q 7X
print "last result:", y "&-C$J5
Id
7>,rvW:]
一个小例子,应该可以解决你的问题