切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 8152阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    285
    光币
    29
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: 7JBr{3;eS  
    Q(4~r+  
    G9@5 !-  
     
    分享到
    离线safeng1122
    发帖
    285
    光币
    29
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: {XwDvLZ  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) WC b 5  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 ~yA^6[a=  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 mP?}h  
    离线safeng1122
    发帖
    285
    光币
    29
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: S"`{ JCW$  
    1.判断点在区域中函数 'R99m?"  
    2.计算夹角函数 ngk:q5Tp  
    3.转置函数 ?v'CuWS  
    4.得到区域中心点,及区域半径函数 C IRMAX  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) 7Q,<h8N\5  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    285
    光币
    29
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 Ok}e|b[D  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single aJc>"#+ o  
       cax = x2 - x1 llCE}Vdh  
       cay = y2 - y1 a FWTm,)  
       cbx = x2 - x3 ' -aLBAxy  
       cby = y2 - y3 _^!C4?2!  
       mo_jj = cax * cbx + cay * cby ETR7% 0$r  
       mo_ca = Sqr(cax * cax + cay * cay) hqwsgJ  
       mo_cb = Sqr(cbx * cbx + cby * cby) &v9"lR=_k  
       cos_acb = mo_jj / (mo_ca * mo_cb) v[?gM.SF  
       'ff_cos = cos_acb QD1&"T<.d.  
       If cos_acb >= 1 Then )0Vj\>  
       nn = 0 ucbtPTFYvr  
       ElseIf cos_acb <= -1 Then zB\ 8<97 C  
       nn = 3.14159265258979 %:dd#';g  
       Else -W: @3\{  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) Dhk$e  
       End If pTJ_DH  
       'ff_angle = nn ?wjk=hM2  
       ff_angle = nn * 180 / 3.14159265258979 8-smL^~%#  
    End Function
    离线safeng1122
    发帖
    285
    光币
    29
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 % 5BSXAc  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean _sHeB7K  
    Dim aob, boc, cod, doa, sum As Single $A(3-n5=  
      If ppx = p1x And ppy = p1y Then ~\%H0.P6  
         point_in = True dE (d'*+a  
         Exit Function {4%ddJn[.)  
      End If "{jVsih0  
      If ppx = p2x And ppy = p2y Then Af^9WJ  
         point_in = True = @FT$GQ  
         Exit Function T8j<\0WW  
      End If 9s*UJIL  
       If ppx = p3x And ppy = p3y Then YKx+z[A/p  
         point_in = True QKoJxjR=^  
         Exit Function m^^#3*qa  
      End If 0BOL0<Wq  
         ,yi@?lc  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) sr:hR Q27  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) zS?DXE  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) lB|.TCbW  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) -1R7 8(1  
        sum = aob + boc + cod + doa 0s.4]Zg>5  
        If 360.01 > sum And sum > 359.99 Then (k%r_O6  
           point_in = True fY|vq amA;  
        Else t"6u  
           point_in = False mn\GLR.  
        End If  ww\2  
    End Function
    离线safeng1122
    发帖
    285
    光币
    29
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 u 0 K1n_  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() cP0(Q+i7  
        '求得中心点坐标 J!zL)u|  
    Dim tt As String  1oG'm  
    Dim rt(3) As Single )/{~&L U  
        '判断是否平行 ?gXdi<2Qn  
       acx = p3x - p1x 4{" v  
       acy = p3y - p1y SN#N$] y5s  
       bdx = p4x - p2x l +O\oD?-  
       bdy = p4y - p2y 6x8lnXtA  
       If acx * bdy = acy * bdx Then '_xa>T}  
          rt(0) = 0 @OC*:?!4  
          Exit Function QFEc?sEe  
       Else [g: KFbEY  
          '判断斜率存在否 cHwN=mg]S  
          If p1x = p3x And p2x <> p4x Then 7L!q{%}  
             tt = "ac_n_bd_y" =5h ,ZB2A  
          ElseIf p1x <> p3x And p2x = p4x Then QST-!`]v  
             tt = "ac_y_bd_n" %#7^b=;=  
          ElseIf p1x <> p3x And p2x <> p4x Then f<@`{oP@  
             tt = "ac_y_bd_y" DZ5h<1  
          End If x4@IK|CE  
        Select Case tt 0"`|f0}c  
             Case "ac_n_bd_y" QWK\6  
                'bd线段方程 Dn;$4Dak(  
                k_bd = bdy / bdx Oxh . &  
                b_bd = p2y - k_bd * p2x e&=T`  
                p_x = p1x A#w*r-P  
                p_y = k_bd * p_x + b_bd UC"_#!3  
             Case "ac_y_bd_n" })ic@ Mmd$  
                'ac线段方程 w;T?m,"  
                k_ac = acy / acx G~Fjla\?Q  
                b_ac = p1y - k_ac * p1x a]R1Fi0n  
                p_x = p2x qg8T}y>  
                p_y = k_ac * p_x + b_ac 1=Q3WMT  
            Case "ac_y_bd_y" 0bR})}a+Yg  
               'ac,bd线段都要求 M Y>o8A  
               k_ac = acy / acx p87VJ}  
               b_ac = p1y - k_ac * p1x @{8SC~ha  
               k_bd = bdy / bdx  /w(t=Y  
               b_bd = p2y - k_bd * p2x k+Ay^i}s.  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) @jH8x!5u:  
               p_y = k_ac * p_x + b_ac dn= g!=  
            End Select }9(:W</}  
          rt(1) = p_x /%h<^YDBf  
          rt(2) = p_y J(x42Q}*S  
         Pb@9<NXm'  
    '计算最大半径 7_AcvsdW  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) %%k`+nK~  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) ~,P."  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) 4 O~zkg  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) '~kAsn*/  
    Dim bb(5) As Single =Ev* Q[  
      bb(1) = rr1 ADN  
      bb(2) = rr2 pL)o@-k#%  
      bb(3) = rr3 a`uHkRX )U  
      bb(4) = rr4 AP_2.V=Sn  
      nb = rr1 F /% 5 r{  
    For i = 1 To 4 +;wu_CQu  
        If nb <= bb(i) Then -OV!56&  
           nb = bb(i) GOhGSV#  
        End If >2?O-WXe  
    Next i )]C7+{ImC  
        rt(0) = Sqr(nb) ^H UNq[sQ  
        rr = rt() B*j AD2  
      End If l*C(FPw4  
             sDvtk]4o-4  
    End Function
    离线lifei0715
    发帖
    1191
    光币
    7810
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    285
    光币
    29
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  ?th`5K30  
    +IiL(\ew  
    有热压工艺方面的人才或者资料分享下; q1Vh]d  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 %{*}KsS`p  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.