'判断点在区域内函数 % 5BSXAc
Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean _sHeB7K
Dim aob, boc, cod, doa, sum As Single $A(3-n5=
If ppx = p1x And ppy = p1y Then ~\%H0.P6
point_in = True dE(d'*+a
Exit Function {4%ddJn[.)
End If "{jVsih0
If ppx = p2x And ppy = p2y Then Af^9WJ
point_in = True =
@FT$GQ
Exit Function T8j<\0WW
End If 9s*UJIL
If ppx = p3x And ppy = p3y Then YKx+z[A/p
point_in = True QKoJxjR=^
Exit Function m^^#3*qa
End If 0BOL0<Wq
,yi@?lc
aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) sr:hRQ27
boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) zS?DXE
cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) lB|.TCbW
doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) -1R7 8(1
sum = aob + boc + cod + doa 0s.4]Zg>5
If 360.01 > sum And sum > 359.99 Then (k%r_O 6
point_in = True fY|vq
amA;
Else t"6u
point_in = False mn\GLR.
End If ww\2
End Function