mainsquall |
2015-06-17 15:46 |
请大家来看看这个宏到底什么问题
U=>S|>daR FORMAT 20.9 bOY;IB
_ GETSYSTEMDATA 1 PnsBDf%v Nbc1=VEC1(1) gcLz}84 Nbc2=VEC1(4) 74s{b]jN'- Nbc3=VEC1(5) _|HhT^\P Nbc4=VEC1(6) "LyD Nbc5=VEC1(7) }d$-:l,w Nbc6=VEC1(8) R>'
%}|v/ Nbc7=VEC1(9) ]@q%dsz Nbc8=VEC1(10) <LX\s*M) Nbc9=VEC1(11) v=`yfCX-qX Nbc10=VEC1(12) lQA5HzC\ Nbc11=VEC1(13) `-NK:;^ Nbc12=VEC1(14) {.Tx70kn Nbc13=VEC1(15) :yay:3qv Nbc14=VEC1(16) N2r zHK Nbc15=VEC1(17) V0ze7tSG[f Nbc16=VEC1(18) =TB_|`5;j -[>de!
T3$ !////////////////////////////////////////////////////// m 2H4V+M+ f~IJ4T2#N lU
WXXuO] 37AVk`a 0^;2 n=nsur() |diI(2w L"_XWno +9)JtmoL PARAXIAL ON t0)1;aBZ RAYTRACE 0,0,0,1 H`EhsYYK R=RAYM(n)/RAYN(n) QV4|f[Ki% ld=-1*RAYY(n-1)/R 7Q
3!=b ld$=$STR(ld) Gvb2>ZN Lx"GBEkt7 $:ush"=f8^ [g}Cve#i PARAXIAL OFF _\!]MV RAYTRACE 0,0,0,1 MJn-] E r_1h=RAYM(n)/RAYN(n) uo F.f$%" ld_1h=-1*RAYY(n-1)/r_1h sEhvx+( ld_1h$=$STR(ld_1h) g` rr3jP F^ q{[Z HB07 n4 | PARAXIAL OFF PK\Z Rl RAYTRACE 0,0,0,0.7 }$6L]
r_0.7h=RAYM(n)/RAYN(n) g?j)p y ld_0.7h=-1*RAYY(n-1)/r_0.7h =j7Du[?Vu ld_0.7h$=$STR(ld_0.7h) gt kV=V /\J0)V 6jE.X DLD_1H=ld_1h-ld yR[6s#F/h DLD_0.7H=ld_0.7h-ld 0b& | |