| 冷不凡5 |
2015-01-14 19:18 |
求问下面这个ASAP的sample中的案例如何解析(关于结构)
求问下面这个ASAP的sample中的案例如何解析 m=9b/Nr4 ),N,!15j, !! Initialization UiV#w#&P eWv:wNouk SYSTEM NEW !! clear out any existing geometry O/#3QK RESET !! clear out rays/sources i.6 b% UNITS MM n)5t! XMEMORY NORM `"CA$Se8 FRESNEL BOTH moxmQ>xoH SPLIT 6 MONTECARLO :&
Dv!z kBk>1jn" NRAYS=100000 !! Number of rays to trace Q9OCf"n $ NPIXELS=81
ZJs~,Q QTa\&v[f !! Media and coating definitions... ?X|q <1I4JPh>x MEDIA IWv5UmjN 1.52 'GLASS' }w4OCN\1
1.4 'PLASTIC' .\$A7DD+A =A,B'n\R COATINGS PROPERTIES M2cGr 0.000000 0.000000 'ABSORB' bh5D}w 1.000000 0.000000 'REFLECT' )e0kr46 0.000000 1.000000 'TRANSMIT' 9cB+x`+Lu 0.600000 0.000000 'FIL_COIL' [#Apd1S_ -51LF=(!L !! ====================================================================== LI.WcI3uS Vc5>I_ !! source definition macro !o`7$`%Wz\ Ci-Ze j DEFINE_SOURCE { 4 !! (X,Y,Z,NRAYS) tUH?N/qn $LOC POSX,POSY,POSZ,NRAYS )lLeL#]FLO POSX=#1 *CXc{{ POSY=#2 AcuZ?LYzK POSZ=#3 vzs4tkG NRAYS=#4 +r"}@8/\1 sTP\} $ECHO NONE t!3s@ A{\?]]/ CURVES I]d-WTd LINE -2.500000 -2.500000 -.5000000 2.500000 -2.500000 -.5000000 6HBDs: LINE 2.500000 -2.500000 -.5000000 2.500000 2.500000 -.5000000 ( gg )? LINE 2.500000 2.500000 -.5000000 -2.500000 2.500000 -.5000000 g|uyQhsg LINE -2.500000 2.500000 -.5000000 -2.500000 -2.500000 -.5000000 RN 4?]8 COMPOSITE bDl#806P L OBJECT =SOURCE.BASE.TrimSrf 1 \k=dqWBr7 INTERFACE COATING "ABSORB" "AIR" "AIR" bu6Sp3g REDEFINE COLOR 22 Az y`4 FACETS 3 3 &C | |