qlmi |
2006-08-10 13:34 |
关于Effective focal length的问题
ZEMAX中priscription data会给出系统的许多有用的数据,其中包括effective focal length的数据和主平面位置的数据。但是我发现直接给出的effective focal length数据和根据其定义结合主平面的数据算出来的结果不一致,这时怎么回事? /lSz8h2 一下是我的Prescription Data数据: q"5iza__H GENERAL LENS DATA: K+D`U6& 5Cd>p< Surfaces : 3 ?9_<LE
q Stop : 1 9cAb\5c| System Aperture : Object Space NA = 0.12 x-k}RI Glass Catalogs : Schott BF2,E<^A Ray Aiming : Paraxial Reference, Cache On KAm v7 X Pupil shift : 0 ^0R.U+?+ Y Pupil shift : 0 k+2~=# Z Pupil shift : 0 f0fN1 Apodization : Gaussian, factor = 1.00000E+000 <jT6|2' ************************************************************* R74kt36M Effective Focal Length : 1.639158 (in air at system temperature and pressure) @kUCc1LT Effective Focal Length : 1.639158 (in image space) S*6P=O* ************************************************************* _|xO4{X Back Focal Length : -1.061568 [rv"tz= Total Track : 4.318 kC"<4U Image Space F/# : 3.417255 eOjoxnD-$ Paraxial Working F/# : 2.950535 etj8M
y6= Working F/# : 2.961912 !Ac <A. Image Space NA : 0.1670788 >&tPIrz Object Space NA : 0.12 7=t4;8|j; Stop Radius : 0.2398355 ]:JoGGE a0 Paraxial Image Height : 0 p q7G[ Paraxial Magnification : 0 BEyg63= Entrance Pupil Diameter : 0.4796709 ^!-*xH.dK Entrance Pupil Position : 0 *D1^Se Exit Pupil Diameter : 2.511155 Jz
s.) Exit Pupil Position : 7.420935 zR(}X8fP Field Type : Angle in degrees 9D:p~_"g Maximum Field : 0 m
UpLD+-j Primary Wave : 1.31 q-gN0"z^6$ Lens Units : Millimeters " 4#V$V Angular Magnification : 0 <<gk<_7` WF<`CQ g[ Fields : 1 Rz1&(_Ps Field Type: Angle in degrees wQ qI@ # X-Value Y-Value Weight W[[3'J TF 1 0.000000 0.000000 1.000000 sPn[FuT>+s '5.n28W> Vignetting Factors G=!1P]M{ # VDX VDY VCX VCY VAN 6+(g4MW 1 0.000000 0.000000 0.000000 0.000000 0.000000 6wx;grt'Z *z;4.
OX Wavelengths : 1 9l9nT Units: Microns Vm6G5QwM # Value Weight Tw"u{%t 1 1.310000 1.000000 HDZB)'I Y;d$x}dh CARDINAL POINTS: =4uL1[0' BpZE Object space positions are measured with respect to surface 1. :zZK%}G< Image space positions are measured with respect to the image surface. ~~k_A|& The index in both the object space and image space is considered. 6Y0k}+j|>E 6U6,Wu Object Space Image Space $^?"/;8P5 W = 1.310000 (Primary) Aa-L<wZVPt ************************************************************ 5mUHk]W Focal Length : -1.639015 1.639015 ik)T>rYg0 ************************************************************ MW8GM }Ho[ Focal Planes : 0.313078 -1.159568 7{=/rbZT? Principal Planes : 1.952094 -2.798584 &{NN!X Anti-Principal Planes : -1.325937 0.479447 \\XvVi:B Nodal Planes : 1.952094 -2.798584 Yo3my>N&g Anti-Nodal Planes : -1.325937 0.479447 P:vAU8d> M eo(|U 我用*号,标出了需要注意的地方,请高手指教!
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