| qlmi |
2006-08-10 13:34 |
关于Effective focal length的问题
ZEMAX中priscription data会给出系统的许多有用的数据，其中包括effective focal length的数据和主平面位置的数据。但是我发现直接给出的effective focal length数据和根据其定义结合主平面的数据算出来的结果不一致，这时怎么回事？ @@}A\wA-
一下是我的Prescription Data数据： Z3 &8(vw
GENERAL LENS DATA: ]kc]YO7i%R
J0^p \mG
Surfaces : 3 D4_D{\xhO
Stop : 1 #~nI^
ggW
System Aperture : Object Space NA = 0.12 "x&H*"
Glass Catalogs : Schott
RtK/bUa
Ray Aiming : Paraxial Reference, Cache On rY88xh^
X Pupil shift : 0 +STT(b Mn
Y Pupil shift : 0 61CNEzQ
Z Pupil shift : 0 :'#B U:
Apodization : Gaussian, factor = 1.00000E+000 Xo }w$q5
************************************************************* LTG/gif[u
Effective Focal Length : 1.639158 (in air at system temperature and pressure) ePB=aCZ
Effective Focal Length : 1.639158 (in image space) 2L ~U^
************************************************************* ;z!~-ByzL
Back Focal Length : -1.061568 p}N'>+@=
Total Track : 4.318 W>'R<IY4#N
Image Space F/# : 3.417255 7J##IH+z35
Paraxial Working F/# : 2.950535 .GLotc
Working F/# : 2.961912 K@%. T#
Image Space NA : 0.1670788 cYW F)WAog
Object Space NA : 0.12 C'kd>LAGu
Stop Radius : 0.2398355 dEns|r
Paraxial Image Height : 0 a!4'}gHR
Paraxial Magnification : 0 QfRt3\^`
Entrance Pupil Diameter : 0.4796709 *T*MLD]Q
Entrance Pupil Position : 0 PJ9JRG7j
Exit Pupil Diameter : 2.511155 YgrBIul
Exit Pupil Position : 7.420935 Wv$e/ N`l
Field Type : Angle in degrees dAohj
QH:
Maximum Field : 0 %;9wToyK>
Primary Wave : 1.31 %q(n'^#Z.y
Lens Units : Millimeters %F1 Ce/
Angular Magnification : 0 w9l)=[s=
w IL5-k,
Fields : 1 ( T!Q
Field Type: Angle in degrees '9H]S Ew
# X-Value Y-Value Weight =@&]PYv
1 0.000000 0.000000 1.000000 &\`=} hB
&Pgb Fy
Vignetting Factors FtT+Q$q=
# VDX VDY VCX VCY VAN v6TH-
1 0.000000 0.000000 0.000000 0.000000 0.000000 Jc:*X4-'
VI[ikNpX
Wavelengths : 1 mp%i(Y"vp
Units: Microns 4: 5 CnK
# Value Weight :W 8DgL>l
1 1.310000 1.000000 |Zncr9b
sR
~1J4
CARDINAL POINTS: s 3Y
\,9\
&-s!ko4z
Object space positions are measured with respect to surface 1. }=az6cLE2
Image space positions are measured with respect to the image surface. D 0\
The index in both the object space and image space is considered. k g0Z(T:&8
p 8Ts5n
Object Space Image Space q?e97 a
W = 1.310000 (Primary) f LxFF
************************************************************ d* 7 Tjs{\
Focal Length : -1.639015 1.639015 \{P(s :
************************************************************ 7Oru{BQ">
Focal Planes : 0.313078 -1.159568 6ZR'1_i6i=
Principal Planes : 1.952094 -2.798584 r8}GiP0|
Anti-Principal Planes : -1.325937 0.479447 LezM=om.
Nodal Planes : 1.952094 -2.798584 ^t?P32GJ
Anti-Nodal Planes : -1.325937 0.479447 } | (KI
% 7z
我用*号，标出了需要注意的地方，请高手指教！
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