| qlmi |
2006-08-10 13:34 |
关于Effective focal length的问题
ZEMAX中priscription data会给出系统的许多有用的数据，其中包括effective focal length的数据和主平面位置的数据。但是我发现直接给出的effective focal length数据和根据其定义结合主平面的数据算出来的结果不一致，这时怎么回事？ K Er?&e
一下是我的Prescription Data数据： klj.\wg/p{
GENERAL LENS DATA: 1` n
ZK$
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Surfaces : 3 'V Y\ut
Stop : 1 4_Rv}Y d
System Aperture : Object Space NA = 0.12 W!Rr_'yFe)
Glass Catalogs : Schott L\kT9wWK|
Ray Aiming : Paraxial Reference, Cache On OoAZ t
X Pupil shift : 0 mZ
t:
Y Pupil shift : 0 j(= zc6m
Z Pupil shift : 0 2HvzMo-4
Apodization : Gaussian, factor = 1.00000E+000 ]G2%VKkr
************************************************************* 9!6yo
Effective Focal Length : 1.639158 (in air at system temperature and pressure) /B9 jmvj`
Effective Focal Length : 1.639158 (in image space) }=."X8zOI8
************************************************************* }\\6"90g*
Back Focal Length : -1.061568 \~q cYp
Total Track : 4.318 ?{6[6T
Image Space F/# : 3.417255 qS+I lg
Paraxial Working F/# : 2.950535 'r?OzFtxh
Working F/# : 2.961912 ZZl4|
Image Space NA : 0.1670788 (wsvj61
Object Space NA : 0.12 gbRdng7(}
Stop Radius : 0.2398355 t]%! vXo
Paraxial Image Height : 0 Aonq;} V e
Paraxial Magnification : 0 -?<L"u
Entrance Pupil Diameter : 0.4796709 84d ej<
Entrance Pupil Position : 0 k-vxKrjZ/
Exit Pupil Diameter : 2.511155 0H{0aQQ
Exit Pupil Position : 7.420935 YPq`su7m9
Field Type : Angle in degrees ;w}5:3+
Maximum Field : 0 Jid :$T>
Primary Wave : 1.31 5Gsj;
Lens Units : Millimeters Iq[,)$
Angular Magnification : 0 #8d$%F))
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Fields : 1 /`Lki>"
Field Type: Angle in degrees DP_ b B(
# X-Value Y-Value Weight
0- +`{j
1 0.000000 0.000000 1.000000 | "Oazll
2={ g 'k(
Vignetting Factors Kn9 ,N@bU_
# VDX VDY VCX VCY VAN %rRpUrnm
1 0.000000 0.000000 0.000000 0.000000 0.000000 I1H:h
h(G(U_V-Od
Wavelengths : 1 v +=_
Units: Microns O_PC/=m1@
# Value Weight n1W}h@>8
1 1.310000 1.000000 v u.f B4
~ +$l9~`{
CARDINAL POINTS: U-s6h;^ O
2h6F j&
Object space positions are measured with respect to surface 1. hK$-R 1O
Image space positions are measured with respect to the image surface. \r f1#Em
The index in both the object space and image space is considered. a~~ "2LE`
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Object Space Image Space qwaw\vOA
W = 1.310000 (Primary) {ersXQ:
************************************************************ ZdH WSfO)O
Focal Length : -1.639015 1.639015 "v3u$-xN1
************************************************************ I$wP`gQh
Focal Planes : 0.313078 -1.159568 Phgn|
Principal Planes : 1.952094 -2.798584 r/O(EW#=8
Anti-Principal Planes : -1.325937 0.479447 O!]w J
Nodal Planes : 1.952094 -2.798584 3P6!j
Anti-Nodal Planes : -1.325937 0.479447 &:jE+l
\aUbBa%!
我用*号，标出了需要注意的地方，请高手指教！
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