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sansummer 2011-06-27 11:39

如何分析Ghost focus generator的结果

例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html aWLA6A+C&  
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其中使用Ghost focus generator后的结果为: QL2 LIs  
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Ghost Trace Data g3%x"SlIU  
File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx 8<Yv:8%B6  
Title: A SIMPLE COOKE TRIPLET. :(3'"^_NA  
Units are Millimeters. ~fcC+"7q/  
Wavelength: 0.550000 μm TBF{@{.d  
Type: Double Bounces " ? V;C  
The '****' denotes a possible internal focus gr.G']9lNq  
RMS is the RMS spot radius on axis at the primary wavelength. :l Z\=2D  
RMS values of 0.00 indicate that an accurate RMS @RoU   
could not be computed, usually due to ray errors. -{d(~XIo  
This analysis may be inaccurate if the system is B"*PBJuOA  
non-rotationally symmetric or uses non-standard surfaces. #zSNDv`  
Ghost reflection off surface 2 then 1. (GH002001.ZMX) _x!/40^G  
Surf     Marginal          F/#          RMS K@osD7-  
   1  5.0000E+000     5.737068  3.5355E+000 vt(n: Xk  
   2  4.7160E+000     4.595701  3.3570E+000 o ?.VW/"  
   1  4.3614E+000     0.990012  3.1277E+000 Z.aeE*Hs$  
   2  2.7155E+000     0.607262  1.9876E+000 v6x jLP;O  
   3 -2.2309E+000     0.916280  2.6065E+000 NP~3!b  
   4 -2.7766E+000     0.514753  0.0000E+000 ,L>{(Q)  
   5 -7.3909E+000     0.888038  0.0000E+000 yC|odX#  
   6 -9.0530E+000     0.823473  0.0000E+000 SwrzW'%A  
   7 -3.4681E+001     0.823473  0.0000E+000 * "?,.  
Marginal ray height    :       -34.6809 Xo.3OER  
Chief ray height       :       -24.8107 SST@   
Distance to ghost pupil:       -50.9613 f|s,%AU"i  
Distance to ghost focus:       -57.1176 76c:* bZ  
Effective focal length :         8.2347
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请问这个结果怎么看? B&*`A&^y  
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其中:Ghost reflection off surface 2 then 1,什么意思? '=K~M  
最后的光线高度能用来分析什么?? ~1,$  
Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 "zFTPL"  
Effective focal length : 8.2347 oVfRp.a  
这有代表什么,求高手啊
sansummer 2011-06-27 13:58
我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? 4!'4 l=jO  
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Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦
superyu2009 2011-11-22 19:48
用CODE V分析更好
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