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sansummer 2011-06-27 11:39

如何分析Ghost focus generator的结果

例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html E.U0qK],  
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其中使用Ghost focus generator后的结果为: )MMhlcNC  
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Ghost Trace Data y 2cL2c$BT  
File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx lbG}noqb  
Title: A SIMPLE COOKE TRIPLET. 0\ZaMu #  
Units are Millimeters. hQP6@KIe)  
Wavelength: 0.550000 μm QQSH +  
Type: Double Bounces >9(7h&[Y  
The '****' denotes a possible internal focus 3[,wMy"  
RMS is the RMS spot radius on axis at the primary wavelength. 3a/[."W u  
RMS values of 0.00 indicate that an accurate RMS c-ttds  
could not be computed, usually due to ray errors. dp33z"<3  
This analysis may be inaccurate if the system is EI%M Azj}  
non-rotationally symmetric or uses non-standard surfaces. ?L8&(&1@VD  
Ghost reflection off surface 2 then 1. (GH002001.ZMX) ;!^ +N  
Surf     Marginal          F/#          RMS 91U^o8y  
   1  5.0000E+000     5.737068  3.5355E+000 Vx}Yl&*D  
   2  4.7160E+000     4.595701  3.3570E+000 CL EpB2_  
   1  4.3614E+000     0.990012  3.1277E+000 zZ<ns+h  
   2  2.7155E+000     0.607262  1.9876E+000 ?'TA!MR  
   3 -2.2309E+000     0.916280  2.6065E+000  W{L  
   4 -2.7766E+000     0.514753  0.0000E+000 b1eK(F  
   5 -7.3909E+000     0.888038  0.0000E+000 'E@2I9Kj  
   6 -9.0530E+000     0.823473  0.0000E+000 >~.Zr3P6kC  
   7 -3.4681E+001     0.823473  0.0000E+000 (QA-"9v#i,  
Marginal ray height    :       -34.6809 B#| Z`mZ  
Chief ray height       :       -24.8107 ],H1  
Distance to ghost pupil:       -50.9613 r.Y*{!t  
Distance to ghost focus:       -57.1176 uDpf2(>s  
Effective focal length :         8.2347
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请问这个结果怎么看? `WraOsoY  
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其中:Ghost reflection off surface 2 then 1,什么意思? k, $I59  
最后的光线高度能用来分析什么?? *4r s  
Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 L`<T'3G  
Effective focal length : 8.2347 *(@L+D0N  
这有代表什么,求高手啊
sansummer 2011-06-27 13:58
我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? ;"d?_{>7  
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Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦
superyu2009 2011-11-22 19:48
用CODE V分析更好
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