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uiuo 2009-04-11 21:31

求教CHIEF RAY ANGLE在Zmax中如何可以看出来?

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? J$Z=`=] t+  
leslie1719 2011-12-26 09:48
我這邊有一個zpl可以直看出來~ %Yj%0  
如下: `J1HQ!Z  
!RIH: CHIEF RAY HEIGHT ON IMA #8|LPfA  
?u|@,tQ[  
!CRA: CHIEF RAY ANGLE IN IMA SPACE ,$0-I@*V  
oQ 2$z8  
!和取最?視角度 _]-4d_&3(  
MfP)Pk5  
MAXFIELD = MAXF() ZUHRATT-  
)V\@N*L`ik  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 R|C 2O[r}  
+{1.kb Zq  
!獲曲面數 X/yq<_ g  
`&M,B=E  
n = NSUR() 27EK +$  
f#= c=e-A  
!主光線錐激 -}#HaL#'K  
j-":>}oW2.  
& 3BoK/y3  
.!x&d4;,q  
RAYTRACE  0, 1, 0, 0, PWAV() 83n%pS4x  
SVZocTt  
unLhI0XW  
Ix5&B6L8  
MAX_RIH = RAYY(n) X H-_tvB  
d ~Z\%4  
/8FmPCp}r  
r 3W3;L   
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   T#) )_aC  
d9K8[Q5^3  
{~3QBMx6  
'+`[)w  
PRINT   "MAX FIELD: " , maxfield, xG9Sk  
H$KO[mW}  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , vrkY7L3\  
FEaT}/h;  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH n t}7|h|  
9 r!zYZ`)  
Xw-[Sf]p  
# ]7Lieh[5  
PRINT "FIELD ",   BAf$ty h  
XBQt:7[<  
PRINT "CHIEF RAY ANGLE," _)M,p@!?=h  
=dmr ,WE  
PRINT  "CHIEF RAY HEIGFHT ON IMA." qCV<-o  
qqrjI.  
7?$?Yu  
\$ytmtf5  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for F5h/>  
4:`D3  
5 4gr'qvr  
fw%`[( hK  
For j, 0, 20, 1 Fx9-A8oIR  
, NSf  
FHY = j/20 ZK5nN9`  
@5Xo2}o-Q  
RAYTRACE  0, FHY, 0, 0, PWAV() \N,ox(f?gW  
l~c[}wv  
CRA = ACOS(RAYN(n-1))*180/3.1416 N3%X>*'  
'nmA!s  
OLDX = CRA szI7 I$Qb  
kZ40a\9 Ye  
OLDY = RAYY(n) $x0SWJ \G  
 {>]\<  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY jD: N)((  
%6UF%dbYH`  
:xd;=;q5  
y&/IJst&aq  
at: li  
d1b] +AG4  
NEXT c{z$^)A/  
 is'V%q  
!繪出該點數據 Cp8=8N(Xb  
[q <'ty  
JU 9GJ"  
Dw-d`8*  
GRAPHICS !wAT`0<94F  
j4.wd RK  
W(,j2pU  
)t6]F6!_  
RAYTRACE 0, 1, 0, 0, PWAV() 8>Cr6m   
zWHq4@K  
MAX_RIH = RAYY(n) R>< g\{G]  
}^ rxsx`  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 C|'DKT4M&  
Y'v[2s  
X_WIDE = XMAX() /1.6 z _!ut  
|Splbs k  
Y_WIDE = YMAX() /1.6 $ghZ<Y2}9  
U{U"%XdO  
SEGMENT = 40 S;|:ci<[=  
(3#PKfY+  
FOR j, 0, SEGMENT-1,1 ^h(wi`i  
!l:GrT8J  
D /eH~  
l$42MRi/  
FHY = j/SEGMENT Dl,QCZeM  
3EoCEPb#  
RAYTRACE 0, FHY, 0, 0, PWAV() 9T,/R1N8  
Dg&84,bv^  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 LQ+/|_(.  
`Q] N]mK  
RIH = RAYY(n) vOQ% f?%G\  
80xr zv  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) =L6#=7hcl  
Bo 35L:r|  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) Sg#XcTG  
)>volP  
b}e1JPk}!  
+y7z>Fwl  
)uPJ? 2S9  
Zk3Pv0c  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() 0[;2dc  
IqOg{#sm  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 2 $>DX\h  
ys_2?uv  
RIH = RAYY(n)       Y.:R-|W  
Xn7G2Yp  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) 7& M-^Ev  
\Mf>X\}  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20)  Fr%#  
q=1 N&#R G  
)rc!irac]  
y^. 66BH  
LINE OLDX,OLDY,NEWX,NEWY B#sCB&(  
mScv7S~/s  
A$ = "0" (In{GA7 ;  
z;OYPGvkw  
gtext OLDX,OLDY,0, A$ tgRj8 @  
U82a]i0  
NEXT B(Sy.n  
Fs+ tcr/\[  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " QX,$JM3  
G0FzXtu)q  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" % rBz A<  
e`*}?N4d  
[KDxB>R<{  
`L1,JE` q  
GRAPHICS OFF ;vn0%g  
 W!Tx%  
rcasiodu 2011-12-27 09:57
楼上的回答非常棒!谢谢分享这个宏! ggso9ZlLu+  
还有一个简单的方法,利用Ray Trace观察主光线的ray angle以及imaging height,参见http://www.opticsky.cn/read-htm-tid-51156.html,此贴介绍的很详细。 s%[F,hQRk  
paradism 2012-07-01 12:51
学习了!!!!!!!!!!!!!!!!!!!
wanglu079 2012-07-09 13:04
用宏指令看
qq41894351 2012-07-09 22:26
什么事宏指令
oxfocean 2019-05-14 17:10
这个宏厉害了
1014597 2019-05-15 06:04
这个宏厉害了
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