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uiuo 2009-04-11 21:31

求教CHIEF RAY ANGLE在Zmax中如何可以看出来?

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? yK1@`3@?  
leslie1719 2011-12-26 09:48
我這邊有一個zpl可以直看出來~ |"j{!Ei  
如下: d`}t!]Gg  
!RIH: CHIEF RAY HEIGHT ON IMA Owe"x2D\  
ku8C#%.m3  
!CRA: CHIEF RAY ANGLE IN IMA SPACE 9L2]PU v  
b3'U }0Ug  
!和取最?視角度 IE^xk@  
mE|?0mRA %  
MAXFIELD = MAXF() .paKV"LJ  
F.]D\"0`  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 DW@|H  
]~YY#I":  
!獲曲面數 -a=RCzX]  
? Zhnb0/  
n = NSUR() 8)Z)pCN  
W 'w{}|  
!主光線錐激 \LN!k-c  
jDWmI% Y.  
0*=[1tdWY  
0~/'c0Ho  
RAYTRACE  0, 1, 0, 0, PWAV() |c<h& p  
[}mx4i  
8zI*<RX.Q  
43'!<[?x  
MAX_RIH = RAYY(n) X[e:fW[e)  
Iez`g<r  
4X}.aZO&b  
^MXW,xqb  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   SsY :gp_  
prk@uYCa =  
762c`aP_(  
|ee A>z"I  
PRINT   "MAX FIELD: " , maxfield, _HAtTW  
-eQ>3x&3r  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , VUneCt%  
j5Cf\*B4J  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH }!`_Bz:  
vWs#4JoG  
q*^m8  
+lhjz*0  
PRINT "FIELD ",   _k|k$qxE  
?niv}/'%O  
PRINT "CHIEF RAY ANGLE," )w_hbU_Pb&  
Hz >_tA"^T  
PRINT  "CHIEF RAY HEIGFHT ON IMA." k9*6`w  
"n, %Hh  
gj@>9  
[.Y]f.D  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for ,Qh9}I7;C  
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cHAq[Ebp2!  
For j, 0, 20, 1 INRP@Cp1  
Y(<(!TJ-  
FHY = j/20 ul&}'jBr  
W%-`  
RAYTRACE  0, FHY, 0, 0, PWAV() KlGmO;k  
c$n`=NI  
CRA = ACOS(RAYN(n-1))*180/3.1416 5L0w!q'W  
Njmb{L]Cps  
OLDX = CRA aInh?-  
<*@!>6mS  
OLDY = RAYY(n) Htm;N2$d  
f{w[H S,z  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY 3n)\D<f]#  
m:W+s4!E  
Ge=|RAw3  
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,ieew`  
\B Uno6  
NEXT @M)"  
W5(.Hub}  
!繪出該點數據 tL\L4>^7T  
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AkEt=vI  
Rebo.6rG  
GRAPHICS ;XI=Y"h{%  
bcUa'ZfN<  
Fvr$K*u  
 (2dkmn  
RAYTRACE 0, 1, 0, 0, PWAV() hr?0RPp}  
A,;[9J2\&  
MAX_RIH = RAYY(n) *Xk gwJq  
CP LsSv5  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 X_(n  
|o#pd\  
X_WIDE = XMAX() /1.6 *@fVogr^  
C4|H 5H  
Y_WIDE = YMAX() /1.6 ] ?k\ qS  
ZJOO*S  
SEGMENT = 40 O6b.oS '-  
.GiQC {@9w  
FOR j, 0, SEGMENT-1,1 *d}{7UMy#  
VX'G\Zz@h|  
y:VY8a 4  
"vo o!&<  
FHY = j/SEGMENT S20E}bS:>  
) B[S4K2  
RAYTRACE 0, FHY, 0, 0, PWAV() xeKfc}:&z  
<(x!P=NM-  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 ]Vd1fkXO0  
hEfFMi=a`  
RIH = RAYY(n) %!V=noo  
T%@qlEmf  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) nT%<!/}!  
f=Kt[|%'e  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) N3|aNQ=X0  
DX<xkS[P  
S !R:a>\  
Rqun}v}  
}EJ't io]  
~uweBp~O  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() Wq/0}W.  
&` weW  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 M%N_4j.  
`E5vO1Pl  
RIH = RAYY(n)       eS;W>d  
Wf9K+my  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) p&cJo<]=LE  
xi!R[xr1  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) ^ZG 3{>  
~MZ.988:<  
K&%YTA  
I#GsEhi  
LINE OLDX,OLDY,NEWX,NEWY hG>3y\!#  
|3uE"\nfA  
A$ = "0" _|KeB(W  
a+p_47 xa  
gtext OLDX,OLDY,0, A$ b`X"yg+  
Xd@x(T~'X  
NEXT `yWWX.`  
@P xX]e  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " S0-/9h  
etLA F  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" I,YP{H4  
GeCyq%dN  
x\!Uk!fM  
F ][QH\N  
GRAPHICS OFF 4I<U5@a  
G ~|Z (}H  
rcasiodu 2011-12-27 09:57
楼上的回答非常棒!谢谢分享这个宏! AHtLkfr(r  
还有一个简单的方法,利用Ray Trace观察主光线的ray angle以及imaging height,参见http://www.opticsky.cn/read-htm-tid-51156.html,此贴介绍的很详细。 F` gQ[  
paradism 2012-07-01 12:51
学习了!!!!!!!!!!!!!!!!!!!
wanglu079 2012-07-09 13:04
用宏指令看
qq41894351 2012-07-09 22:26
什么事宏指令
oxfocean 2019-05-14 17:10
这个宏厉害了
1014597 2019-05-15 06:04
这个宏厉害了
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