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uiuo 2009-04-11 21:31

求教CHIEF RAY ANGLE在Zmax中如何可以看出来?

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? 9y8&9<#  
leslie1719 2011-12-26 09:48
我這邊有一個zpl可以直看出來~ \*y-g@-{W$  
如下: nH'e?>x~e  
!RIH: CHIEF RAY HEIGHT ON IMA S_4?K)n #  
Ugt/rf5n  
!CRA: CHIEF RAY ANGLE IN IMA SPACE VUGmi]qd  
_|\~q[ep  
!和取最?視角度 \?ZB]*Fu  
Q&ptc>{bH6  
MAXFIELD = MAXF() wn, KY$/  
l^-];|Y  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 D~iz+{Q4  
]e^&aR5f"  
!獲曲面數 ]BZA:dd.G  
8oseYH  
n = NSUR() rjAn@!|:+  
9C9oUtS  
!主光線錐激 {n.PF8A5X  
k[YS8g-Q  
"1*:JVG  
|?xN\O^#}  
RAYTRACE  0, 1, 0, 0, PWAV() ?V.cOR`6  
$am$ EU?s  
^Za-`8#`L  
EhvX)s  
MAX_RIH = RAYY(n) e@ 07  
{.|CdqwY  
glxsa8  
JPUW6e07o  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   P%VSAh\|n  
RFcv^Xf  
(Q!}9K3  
cn3\kT*  
PRINT   "MAX FIELD: " , maxfield, v^NIx q}U  
\fd v]f  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , EU;9 *W<  
, WYPU  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH LEf^cM=>  
!zpRrx_  
0<@KG8@hI;  
q`a'gJx#y  
PRINT "FIELD ",   H;LViP2K*  
?4&e;83_#y  
PRINT "CHIEF RAY ANGLE," [5b--O  
xml7Uarc  
PRINT  "CHIEF RAY HEIGFHT ON IMA." ,Vm < rK  
]^7@}Ce_  
rfg'G&A(  
!hy-L_wL]  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for MrFQ5:=  
}C?'BRX  
7U"g3 a)=  
mdDOvm:&  
For j, 0, 20, 1 _8J.fT$${  
((;!<5-`s  
FHY = j/20 -f^tE,-  
q~o<*W   
RAYTRACE  0, FHY, 0, 0, PWAV() $( kF#  
q3N jky1w  
CRA = ACOS(RAYN(n-1))*180/3.1416 P|E| $)m  
hWLA<wdb  
OLDX = CRA +GN(Ug'R  
/-'}q=M  
OLDY = RAYY(n) 5Ln,{vsv  
'GWN~5  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY [ l??A3G  
B dfwa  
MJO-q $)c  
ltSU fI  
4k1xy##  
pYEMmZ?L  
NEXT /Cr%{'Pzk  
AV]2 euyn  
!繪出該點數據 1R%.p7@5QU  
ec;o\erPG  
WE#^a6  
pah'>dAL  
GRAPHICS {}n^cq  
'JE`(xD  
/36:ms A  
Wvh#:Z  
RAYTRACE 0, 1, 0, 0, PWAV() LonxT&"!D  
Ll't>)  
MAX_RIH = RAYY(n) ; DR$iH-F  
 8dA~\a  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 $%d*@ 'c  
oZgjQM$YP  
X_WIDE = XMAX() /1.6 H%td hu\e  
PFjL1=7I  
Y_WIDE = YMAX() /1.6 'H>^2C iM  
C{rcs'  
SEGMENT = 40 ? OM!+O  
.p[ux vp  
FOR j, 0, SEGMENT-1,1 9cF[seE"0  
(ZZ8L-s  
IEi^kJflU  
_TZRVa_  
FHY = j/SEGMENT .`eN8Dl1  
\}b%E'+_T  
RAYTRACE 0, FHY, 0, 0, PWAV() dZ@63a>>@  
YD6'#(  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 FW4<5~'  
qEOhwrh  
RIH = RAYY(n) M6j y\<a  
C&%_a~  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) [z{1*Xc  
tyFzSrfc  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) ;)*eo_tQ  
rb.N~  
!F$6-0%  
x 9fip-  
1Pu~X \sO  
d#FQc18v}k  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() a1lh-2x X  
d$!RZHo10V  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 NXrlk  
rEW b"  
RIH = RAYY(n)       )ez9"# MH'  
a`>B Ly5o  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) h2R::/2.  
8l`*]1.W<  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) :$c |  
 qX{+oy5  
VI86KJu  
sO@Tf\d  
LINE OLDX,OLDY,NEWX,NEWY g($2Dk_F2  
"chDg(jMZ  
A$ = "0" ~9@UjQ^)F  
?e 4/p  
gtext OLDX,OLDY,0, A$ t{{QE:/  
 \4fQMG  
NEXT 5.GR1kl6  
3!]rmZ-W  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " $!t4r  
' `Hr}  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" VOLj>w  
NzvXN1_%  
tR$NRMZ.  
lThB2/tV\  
GRAPHICS OFF (4nq>;$3  
Q$"D]!G  
rcasiodu 2011-12-27 09:57
楼上的回答非常棒!谢谢分享这个宏! +N U G  
还有一个简单的方法,利用Ray Trace观察主光线的ray angle以及imaging height,参见http://www.opticsky.cn/read-htm-tid-51156.html,此贴介绍的很详细。 p`qgrI`  
paradism 2012-07-01 12:51
学习了!!!!!!!!!!!!!!!!!!!
wanglu079 2012-07-09 13:04
用宏指令看
qq41894351 2012-07-09 22:26
什么事宏指令
oxfocean 2019-05-14 17:10
这个宏厉害了
1014597 2019-05-15 06:04
这个宏厉害了
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