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uiuo 2009-04-11 21:31

求教CHIEF RAY ANGLE在Zmax中如何可以看出来?

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? Hh @q;0ni  
leslie1719 2011-12-26 09:48
我這邊有一個zpl可以直看出來~ 2&91C[da0  
如下: E [JXQ76  
!RIH: CHIEF RAY HEIGHT ON IMA Q0~5h?V'  
P8NKp O\  
!CRA: CHIEF RAY ANGLE IN IMA SPACE !8&,GT  
=/=x"q+X  
!和取最?視角度 GkMNV7"m  
J#Fe"  
MAXFIELD = MAXF()  iU^ 4a  
-Nmf}`_  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 w?ssV  
aKs!*uo0H  
!獲曲面數 )6)|PzMQ'  
G],+?E_,  
n = NSUR() \Ekez~k{`  
:NU-C!eT  
!主光線錐激 UwtOlV:G{  
V5rnI\:7  
(Br$(XJoK}  
nzy =0Ox[  
RAYTRACE  0, 1, 0, 0, PWAV() &n<jpMB  
j5z, l  
IcL3.(!]l  
,r5<v_  
MAX_RIH = RAYY(n) qt]QO1pAd  
iM2 EEC  
OdQ >h$ gZ  
EC1q#;:  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   )$q<"t\#P#  
xy mK|  
a2/r$Tgm  
s cR-|GuZ  
PRINT   "MAX FIELD: " , maxfield, }=A6Jv(j  
|U nTd$m  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , +azPpGZ=  
m?<8 ':  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH p8s2#+/  
2?t(%uf]  
XyS#6D  
`H$s -PX  
PRINT "FIELD ",   d\;M F  
rShi"Yw  
PRINT "CHIEF RAY ANGLE," ("/*k  
!P@u4FCs  
PRINT  "CHIEF RAY HEIGFHT ON IMA." "EEE09~l\  
 QN_5q5  
\(T; @r  
vCH>Fj"7  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for W}L =JJo},  
5B'-&.Aj+  
bDUGzezP<  
|<y[gj4`T/  
For j, 0, 20, 1 2IjqT L  
a]X6)6  
FHY = j/20 rA=F:N 2  
:NbD^h)R  
RAYTRACE  0, FHY, 0, 0, PWAV() eg(xN/D  
qgZ(o@\  
CRA = ACOS(RAYN(n-1))*180/3.1416 *\VQ%_wg  
e}[$ =  
OLDX = CRA t ?bq ~!X  
!&Q,]\j  
OLDY = RAYY(n) Ix:aHl  
g?=B{V  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY 8w2+t>?  
BOwkC;Q[  
FC]? T  
1pzU=!R?-O  
{g/\5Z\b  
Z?nMt  
NEXT )%^oR5W  
`n^jU92  
!繪出該點數據 a*SJHBB  
gEi" m5po  
[j93Mp  
@Wx_4LOhf  
GRAPHICS a S<JsB  
Z]SCIU @+  
$oxPmELtpe  
+!_^MBkk  
RAYTRACE 0, 1, 0, 0, PWAV() Mm6 (Q  
55$by.rf?  
MAX_RIH = RAYY(n) R o-Mex2  
x[(2}Qd  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 d9Q%GG0]  
l>=c]  
X_WIDE = XMAX() /1.6 ;OdUH   
4&y_+  
Y_WIDE = YMAX() /1.6 q1?2 U<  
JWn9&WK  
SEGMENT = 40 QT|mN  
QGshc  
FOR j, 0, SEGMENT-1,1 w:umr#  
_&dGo(B  
}(hE{((o  
o1n c.2/0J  
FHY = j/SEGMENT 5mFi)0={y  
D6ck1pxkx  
RAYTRACE 0, FHY, 0, 0, PWAV() .qVdo+M%F  
@{ nT4{  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 qA"?5j32  
G+%ZN  
RIH = RAYY(n) 5:s]z#8)  
Jx{,x-I  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) KX9ZwsC0  
|/<iydP  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) Wc]Fg9E  
\\/X+4|o'  
RMvlA' c  
1i>)@{P&BN  
S((8DSt*  
?&X6VNbU  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() pixI&iQ  
:JN3@NsK  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 Zv-6H*zM6  
{==Q6BG*  
RIH = RAYY(n)       _n_i*p '2  
qh&K{r*T  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) 5o72X k  
'PO1{&M  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) R -h7c!ko  
K^> qn,]H'  
}YSH8d  
L`Ic0}|lzy  
LINE OLDX,OLDY,NEWX,NEWY @e Myq1ZU  
e1IuobT  
A$ = "0" <y'ttxeS  
|aVv Lz  
gtext OLDX,OLDY,0, A$ UbYKiLDF)  
Ec[:6}  
NEXT xp &I~YPH  
xj~6,;83xR  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " qMUqd}=P  
w%ip"GT,  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" %kUJ:lg;d  
pE`( kD  
1";~"p2(  
$_ NaxV  
GRAPHICS OFF }.hBmhnZmI  
\vT8 )\  
rcasiodu 2011-12-27 09:57
楼上的回答非常棒!谢谢分享这个宏! #zQkQvAT9  
还有一个简单的方法,利用Ray Trace观察主光线的ray angle以及imaging height,参见http://www.opticsky.cn/read-htm-tid-51156.html,此贴介绍的很详细。 >2|#b  
paradism 2012-07-01 12:51
学习了!!!!!!!!!!!!!!!!!!!
wanglu079 2012-07-09 13:04
用宏指令看
qq41894351 2012-07-09 22:26
什么事宏指令
oxfocean 2019-05-14 17:10
这个宏厉害了
1014597 2019-05-15 06:04
这个宏厉害了
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