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uiuo 2009-04-11 21:31

求教CHIEF RAY ANGLE在Zmax中如何可以看出来?

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? gLV^Z6eE  
leslie1719 2011-12-26 09:48
我這邊有一個zpl可以直看出來~ |w4(rs-  
如下: n-W?Z'H{r  
!RIH: CHIEF RAY HEIGHT ON IMA !bieo'c  
 J(^ >?d'  
!CRA: CHIEF RAY ANGLE IN IMA SPACE Ir^BC!<2>  
}d@LSaM  
!和取最?視角度 {vjq y&?y  
UFos E|r:  
MAXFIELD = MAXF() -h=c=P  
LK{a9` h  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 (%.</|u  
ti+pUlVrM  
!獲曲面數 BJ"Ay@D*  
`TOX1cmw  
n = NSUR() |KTpK(6p  
ynxWQ%d(`  
!主光線錐激 1ZKz3)K  
> e;]mU`,  
w9'H.L q  
# .~.UHt  
RAYTRACE  0, 1, 0, 0, PWAV() '8L(f w{k  
f x%z| K  
HuK Aj  
|HNQ|r_5S  
MAX_RIH = RAYY(n) cj`#Tg.  
Gi;9 S  
<nf=SRZ  
ocq2  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   O~nBz):2  
.&Y,D-h}7|  
m)(SG  
{jrZ?e-q  
PRINT   "MAX FIELD: " , maxfield, ^Kb9@lz/  
neK*jdaP  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , x_]",2 W'  
kbD*=d}3{  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH -,[~~  
S.qk%NTTD  
,HQ1C8  
c9 gz!NE  
PRINT "FIELD ",   e=0l<Rj  
S83]O!w0  
PRINT "CHIEF RAY ANGLE," WNCM|VUl  
u XaL  
PRINT  "CHIEF RAY HEIGFHT ON IMA." fma tc#G  
/QV [N  
K]*g, s+  
*pDXcURw  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for H9.oVF^~  
C]aOgt/U  
;bUJ+6f:  
tn(f rccy  
For j, 0, 20, 1 BDarJY  
L3-<Kop  
FHY = j/20 e5]&1^+  
bjU 2UcI"<  
RAYTRACE  0, FHY, 0, 0, PWAV() hWl""66+5  
6GvhEulYR  
CRA = ACOS(RAYN(n-1))*180/3.1416 f hVbJU  
MoC*tImWR  
OLDX = CRA ?6_"nT*}  
Dwm@E\^ihm  
OLDY = RAYY(n) D}=/w+  
48R]\B<R{  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY <=B1"'\  
o06A=4I  
vHZX9LQU0+  
g~bf!  
kKFuTem_3  
Ek gZxT_&  
NEXT l}U~I 3}).  
1]a*Oer}  
!繪出該點數據 :)^# xE(  
0KWy?6 X  
;EE{ ~  
?NL&x  
GRAPHICS [Gh%nsH  
x= vE&9_u  
luP'JUq  
n1k$)S$iiy  
RAYTRACE 0, 1, 0, 0, PWAV() . }-@;:yh  
l^!0|/Vw  
MAX_RIH = RAYY(n) es*_Oo1  
e+d6R[`M  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 J pCZq #  
Z L6~Eut  
X_WIDE = XMAX() /1.6 pqGf@24c<  
pw(U< )  
Y_WIDE = YMAX() /1.6 :$X4#k<  
5 b#" G"  
SEGMENT = 40 sqMNon`5  
79<9}<T  
FOR j, 0, SEGMENT-1,1 |}]JWsuB  
g4.'T51  
.:|#9%5  
cLN[o8 ZU  
FHY = j/SEGMENT 7~%  
47(1V/r  
RAYTRACE 0, FHY, 0, 0, PWAV() Fw_bY/WN{  
h[[/p {z  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 /ut~jf`  
-x3tx7%  
RIH = RAYY(n) ECE{xoc  
/v|68x6  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) tnKpn-LPA  
l/y Kc8^<  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) J?qcRg`1E  
C[87f-g  
TGt1d  
i\DHIzGp[  
twJ|Jmd  
tc49Ty9$[  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() ^V0{Ew /x  
 t3yQ/  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 4Q`=t &u  
q!9v}R3(  
RIH = RAYY(n)       \4`saM /x  
JK^B+.  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) 0[$Mo3c+'  
9-Nq[i"  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) >w]k3MC  
YCLD!S/?  
hAxuZb7 ?  
w'zO(6 `  
LINE OLDX,OLDY,NEWX,NEWY Dry;$C}P  
Ymk4Cu.s  
A$ = "0" uYFcq  
CrwcYzrRWl  
gtext OLDX,OLDY,0, A$ J9$]]\52s.  
;o)`9<es!2  
NEXT n[cyK$"  
PE6u8ZAb"  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " V~uA(3\U  
luxKgcU  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" >-tH&X^  
U~B}vt  
uI:3$  
WNlSve)]ie  
GRAPHICS OFF @,>=X:7  
s2' :&5(  
rcasiodu 2011-12-27 09:57
楼上的回答非常棒!谢谢分享这个宏! V]S06>P  
还有一个简单的方法,利用Ray Trace观察主光线的ray angle以及imaging height,参见http://www.opticsky.cn/read-htm-tid-51156.html,此贴介绍的很详细。 >"$-VY6i  
paradism 2012-07-01 12:51
学习了!!!!!!!!!!!!!!!!!!!
wanglu079 2012-07-09 13:04
用宏指令看
qq41894351 2012-07-09 22:26
什么事宏指令
oxfocean 2019-05-14 17:10
这个宏厉害了
1014597 2019-05-15 06:04
这个宏厉害了
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