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ruskie 2008-05-10 20:25

请教:Tracepro中照度图选项中选择归一化和不选择归一化选项有什么区别?

在Tracepro的照度图选项中有一项“Normalize to emitted flux”,选择和不选择的情况出来的照度图有什么区别?哪位能详细解答一下。 Gkuqe3  
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suezl9 2008-05-12 11:05
说明书:规范从所有发光源发出的所有出射通量给图的数据,这个选项允许你使通量和光照规范为总共的通量,如果这个框被选中后,TracePro在光照度图中使用出色通量来除以总通量。这对于在光学系统计算的系统透射率和照明系统中计算发光效率,会非常有用。 h6D4CT  
也就是说,比如你的总光源有10lm,得出的照度图在没有选择norm~选项的时候是显示正常的照度,在勾选了之后显示的照度值是原来的/总流明,可以认为是没流明所产生的照度值
ruskie 2008-05-13 10:26
谢谢版主的耐心解答,^_^
qiudonglai 2008-08-19 15:34
suezl9 ' 9f0UtT|[  
哈哈
norrin 2008-08-21 13:28
有中文说明书么?可以共享一下么?
lightgirl 2008-08-22 13:58
Normalize c<|y/n  
Normalize the map data to the total emitted flux from all sources. 0QZT<Zs  
This option allows you to have the flux and irradiance normalized to the total rt*x[5<  
emitted flux. When this box is checked, TracePro divides the values in the 0 (-4"u>?  
irradiance map and the total flux by the emitted flux. This is especially useful for b=lJ`|  
calculating system transmittance for an optical system, or lighting efficiency for a .|[{$&B  
lighting calculation. bfz7t!A)A  
Example 1: System Transmittance rq3f/_#L!O  
Suppose you need to calculate the system transmittance of an optical system. ^>l <)$s  
You would probably use the grid raytrace option, and the emitted flux is equal to t7-]OY7%w_  
the sum of the flux in all the emitted rays. When you display an irradiance map, *G.vY#h  
the system transmittance is equal to the total flux, displayed at the bottom of the k^%=\c  
irradiance map window, divided by the emitted flux. To get the system 8S8qj"s  
transmittance, check the Normalize to emitted flux box and press the Apply e1W9"&4>G{  
button. The map will be redisplayed, and the Normalized Flux value will be equal _rYW|*cIF  
to the system transmittance. $}W T"K  
Example 2: Lighting Efficiency J;_4 3eS  
Suppose you need to calculate the lighting efficiency of a luminaire in illuminating -yqgs>R(d  
a plane. You would probably choose the Surface Source raytrace option, and the O ixqou  
emitted flux is equal to the flux you specified when you defined the sources. When EX_j|/&tZ  
you display an irradiance map, the total flux incident on the observation plane is $4g {4-)  
displayed at the bottom of the window. The lighting efficiency is equal to the total DK?aFSf\  
flux divided by the emitted flux. To get the lighting efficiency directly, check the j<(E %KN3  
Normalize to emitted flux box and press the Apply button. The map will be =8 @DYz'  
redisplayed, and the Normalized Flux value will be equal to the lighting efficiency } KyoMs  
of the luminaire.
kaoyanming 2015-06-02 09:31
可以看成均匀性吗?
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