| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 u)~C;f)
function sjr=nfdre(~) )s%[T-uKi
HlH64w2^R
%系统焦距及各镜间距输入，间距取负正负 %y@Hh=
{qN 5MsY
f=input('f:'); ~1>.A(,=z
d1=input('d1:'); U15H@h
d2=input('d2:'); /!3@]xz*
d3=input('d3:'); w.\&9]P3~
D?NbW @]
A=f^2/(d3*d2)-f/d1; LILQ\I<<'
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); ,"HL ~2:~
C=d3/d2-f/d1; :(M(>4t
j 4^9 7
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 U
15H2-`
a2=d3/(a1*f);%α2 ;n&t>pBM
b2=a1*(1-a2)*f/d2;%β2 @
<
Q|5
b1=(1-a1)*f/(d1*b2);%β1 Vz= PiMO
0sfr d
~Hr} ]
%曲率半径 *U
P@9D
' <@3i[M
R1=2*f/(b1*b2) /(.mp<s 0
R2=2*a1*f/(b2*(1+b1)) /assq+H
R3=2*a1*a2*f/(1+b2) f)^ _|8
Yq%9M=#k
A1=b2^3*(a1-1)*(1+b1)^3; osX8eX]\
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; Y07ZB'K
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; G JoS #s
! q M=a3
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); kNobl
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); F!]lU`z)=
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); "O%gFye
JYW)uJ
CB=[C1 B1;C2 B2]; XYZ4TeW\1
AB=[A1 B1;A2 B2]; R]RZq+2 ^
AC=[A1 C1;A2 C2]; E: $P=%b
'lEA)&d
%非球面系数 r} mb Xvn
k2=-(det(CB)/det(AB)); J
/f
k3=-(det(AC)/det(AB)); z$?~Y(EY
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 "saUai4z
k2=k2 Na?!;1]_
k3=k3 8&)DE@W
L 8dc(Z%v
end l@\#Ywz
6y9t(m
%有中间像，焦距输入为正数 <c qbUL
4DL) rkO
function sjr=yfdre(~) er!DYv
>VN5`Zlw\C
f=input('f:'); \v.C]{Gzc
d1=input('d1:'); ! 3 f?:M
d2=input('d2:'); q@nP}Pv&5
d3=input('d3:'); JU^lyi!
_YLf L
A=f^2/(d3*d2)-f/d1; ZI 3Nq
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); 8(~K~q[Cr
C=d3/d2-f/d1;
ng_^
#p y[
a1=(-B-sqrt(B^2-4*A*C))/(2*A); /oR<A
a2=d3/(a1*f); ~1W x =
b2=a1*(1-a2)*f/d2; ~s]iy9i
b1=(1-a1)*f/(d1*b2); A .EbXo/
}L# _\
%曲率半径 jO1r)hw N>
I~Zh@d%
R1=2*f/(b1*b2) ;I}kQ!q
R2=2*a1*f/(b2*(1+b1)) y6[If cN
R3=2*a1*a2*f/(1+b2) * Of4o
bdF. qO9
A1=b2^3*(a1-1)*(1+b1)^3; 3
%|86:*
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; JQ6zVS2SSS
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; 9& ` 2V
7,lq}a8z
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); d [V;&U
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); NT+? #0I
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); H=Y{rq @
f v9V7
CB=[C1 B1;C2 B2]; bS"fkf9
AB=[A1 B1;A2 B2]; V I'hb'2
AC=[A1 C1;A2 C2]; '{ V0M<O
7[5.> h
%二次系数 O^^C;U@U<1
b7wvaRe.
k2=-(det(CB)/det(AB)); fH > NJK;
k3=-(det(AC)/det(AB)); \3S8 62B7
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 X .5aMm
k2=k2 C@L$~iG
k3=k3 _q{c##K f
jg\Z ;_!W
end
|
|