| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 M4m90C;dq
function sjr=nfdre(~) WPz q?yK
98^o9i
%系统焦距及各镜间距输入，间距取负正负 KsMC+:`F
;zc,vs
f=input('f:'); 39zwPoN>
d1=input('d1:'); BvA09lK
d2=input('d2:'); @3@oaa/v
d3=input('d3:'); 3vK,vu q
IU*w 'a
A=f^2/(d3*d2)-f/d1; n'-?C MH`
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); $7bl ,~Z
C=d3/d2-f/d1; j( SBpM
"2~%-;c
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 [O52Bn
a2=d3/(a1*f);%α2 {~RS$ |
b2=a1*(1-a2)*f/d2;%β2 !^EdB}@yS
b1=(1-a1)*f/(d1*b2);%β1
mtQlm5l
C0b OPn
"\l O1D
%曲率半径 *He%%pk
0Zq jq0O#
R1=2*f/(b1*b2) *tD`X( K
R2=2*a1*f/(b2*(1+b1)) D) *OQLHW
R3=2*a1*a2*f/(1+b2) >Tq Mb8e_
8w|-7$ v
A1=b2^3*(a1-1)*(1+b1)^3; [c=T)]E1
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; YLEa;M R
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; u{_jweZ
n,E =eNc
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); e<;^P( g`E
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); H ^< LnYZ
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); P b(XR+
#~Z55 D_
CB=[C1 B1;C2 B2]; N3`EJY_|V
AB=[A1 B1;A2 B2]; ^bj aa
AC=[A1 C1;A2 C2]; q0l=S+0
,GH;jw)P
%非球面系数 |dxcEjcY_
k2=-(det(CB)/det(AB)); j$z<wR7j0
k3=-(det(AC)/det(AB)); Fu%%:3_
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 \~#$$Q-qtU
k2=k2 U0Y;*_>4
k3=k3 DG!H8^
! 9U
end RrPo89o
A"`^A brm
%有中间像，焦距输入为正数 Zs s `##
2unaK<1s
function sjr=yfdre(~) Qmk}smvH
_ `RCY^t
f=input('f:');
69o,T`B
d1=input('d1:'); O&Ws*k
d2=input('d2:'); }95; qyQ$
d3=input('d3:'); tL;!!vg#V
keBf^NY
A=f^2/(d3*d2)-f/d1; H*Tc.Ie
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); p? dXs^ c
C=d3/d2-f/d1; D_HE! fl
9EE},D
a1=(-B-sqrt(B^2-4*A*C))/(2*A); h5:>o
a2=d3/(a1*f); @4' bI)
b2=a1*(1-a2)*f/d2; x'.OLXx>
b1=(1-a1)*f/(d1*b2); *r &q;ER
kYVn4Wq
%曲率半径 Wx i|(}
9<9 c^2
R1=2*f/(b1*b2) |Mm9QF;iA
R2=2*a1*f/(b2*(1+b1)) n8!qz:z/
R3=2*a1*a2*f/(1+b2) kbxy^4" X
F>0[v|LG
A1=b2^3*(a1-1)*(1+b1)^3; bvuoo/
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; t#Q" ;e
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; nJvDk h#h1
`o.DuvQ
E
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); e+!+(D
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); AV%?8-
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); sUfYEVjr
FuiEy=+
CB=[C1 B1;C2 B2]; |7K[+aK
AB=[A1 B1;A2 B2]; !F |mCEU
AC=[A1 C1;A2 C2]; 8+L,a_q-
}w#Ek=,s#o
%二次系数 $ON4 nx
[F^qa/vJ10
k2=-(det(CB)/det(AB)); C;T:'Uws
k3=-(det(AC)/det(AB)); Xy74D/ocui
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 }SdI _sLe
k2=k2 f?ImQYqP
k3=k3 FAS+*G Fz
-7^A_!.
end
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