| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 #HV5M1m b
function sjr=nfdre(~) S`vt\g$ dN
ou-#+Sd d
%系统焦距及各镜间距输入，间距取负正负 GeJ}m yD O
85!]N F
f=input('f:'); =6U5^+|d
d1=input('d1:'); m}z6Bbis 0
d2=input('d2:'); jOT/ |k
d3=input('d3:'); U@q5`4-!8
CF>&mXg\
A=f^2/(d3*d2)-f/d1; Y/J~M$9P,
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); i[[.1MnS
C=d3/d2-f/d1; '!A}.wF0
}Hb0@
b_
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 #M~yt`R~
a2=d3/(a1*f);%α2 i!%WEHPe
b2=a1*(1-a2)*f/d2;%β2 }vh
<x6
b1=(1-a1)*f/(d1*b2);%β1 Y-bTKSn
hV~M!vFxA
8 XY xyOl
%曲率半径 ~qZ6I)?
- B Wf.
R1=2*f/(b1*b2) qR aPh:Q'
R2=2*a1*f/(b2*(1+b1)) >>$L
vQ
R3=2*a1*a2*f/(1+b2) PESvx>:
|Ogh-<|<
A1=b2^3*(a1-1)*(1+b1)^3; .tKBmq0xo"
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; j5D Cc,s
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; hY!ek;/Gc
: rM2G@{
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); FS 5iUH+5
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); rrz([2E2
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); U%pB
adu6`2 *$
CB=[C1 B1;C2 B2]; C&Qt*V#,
AB=[A1 B1;A2 B2]; D7nK"]HG;l
AC=[A1 C1;A2 C2]; f3Zf97i
tm/ >H
%非球面系数 d BB?A~
k2=-(det(CB)/det(AB)); y0Gblza
k3=-(det(AC)/det(AB)); 2H w 7V 3q
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 842v^ 2
k2=k2 4
. c 1
k3=k3 E} ]=<8V
]&H"EHC< $
end 7k, BE2]"
w0;4O)H$O
%有中间像，焦距输入为正数 Io*H}$Gf
*lA+ -gkK*
function sjr=yfdre(~) ##BbR
qpFx l
f=input('f:'); YvN]7tcb
d1=input('d1:'); e YP^. U)
d2=input('d2:'); st* sv}
d3=input('d3:'); I5E =Ujc_
i`e[Vwe2x@
A=f^2/(d3*d2)-f/d1; \"$P :Uv
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); ?;v\wx
C=d3/d2-f/d1; .'A1Eoo0d
5qH*"i+|s
a1=(-B-sqrt(B^2-4*A*C))/(2*A); _BA; H+M
a2=d3/(a1*f); l'q%bi=f
b2=a1*(1-a2)*f/d2; SF-E> s!XL
b1=(1-a1)*f/(d1*b2); yYGs] +
lCUYE"o
%曲率半径 LDEc}XXb
{H(l"KuL
R1=2*f/(b1*b2) (/<Nh7C1c
R2=2*a1*f/(b2*(1+b1)) sQA_ 6]`
R3=2*a1*a2*f/(1+b2) OnE%D|Tq=
nK03x YA
A1=b2^3*(a1-1)*(1+b1)^3; q/zU'7 %@
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; >U`G3(#7S
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; C{m%]jKH
9s_^?q
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); czIAx1 R9
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); &~+QPnI>Pm
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); `XH 0S`B
b
MD|
CB=[C1 B1;C2 B2]; "P#1=
AB=[A1 B1;A2 B2]; 8Yk*$RR9
AC=[A1 C1;A2 C2]; .B<Bqr@?8
]i(/T$?~
%二次系数 NW5OLa")J<
6 /YJA*
k2=-(det(CB)/det(AB)); >Y8\f :KQ
k3=-(det(AC)/det(AB)); fWq*Op.]c
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 MZ$uWm`/
k2=k2 u$^tRz9
k3=k3 ;$&\ :-6A#
-GFZFi
end
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