| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 K
Ha,6X
function sjr=nfdre(~) r~T!$Tb
K>.}>)0
%系统焦距及各镜间距输入，间距取负正负 QDY uJ&!h
v[uVAb fQ
f=input('f:'); H.l0kBeG
d1=input('d1:'); 5fk
A?Ecqq
d2=input('d2:'); IQ\!wWKmY
d3=input('d3:'); wry`2_c
_ -RqkRI
A=f^2/(d3*d2)-f/d1; 'Iw`+= iVz
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); ?@@$)2_*u
C=d3/d2-f/d1; &M@ .d$<C
Jm CHwyUK?
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 %52 e ^,//
a2=d3/(a1*f);%α2 $=\=80u/
b2=a1*(1-a2)*f/d2;%β2 0cB]:*W
b1=(1-a1)*f/(d1*b2);%β1
'v V t^h2
LI}e_= E
no-";{c
%曲率半径
'{c ND
U3Gg:onuE
R1=2*f/(b1*b2) _$T
!><)y
R2=2*a1*f/(b2*(1+b1)) 0);5cbV7i
R3=2*a1*a2*f/(1+b2) ?& :N|cltD
^n~ Kr1}nj
A1=b2^3*(a1-1)*(1+b1)^3; dl=)\mSFjF
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; k8IL o)
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; (^ B1Kt!<
r+%3Y:dZE
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); _"Y7 }A\9
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); ~H \P0G5GA
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); SPb`Q"
8 HLL3H0
CB=[C1 B1;C2 B2]; )2" g)9!
AB=[A1 B1;A2 B2]; m
%+'St|qr
AC=[A1 C1;A2 C2]; Oi|cTZ@A-
{nSgiqd"28
%非球面系数 WVQHb3Pe0
k2=-(det(CB)/det(AB)); |+8rYIms`
k3=-(det(AC)/det(AB)); 9-j-nx
@)
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 Nz{qu}dt
k2=k2 bhRa?wuoY
k3=k3 nl 2Lqu1
!Usmm8!K
end zhow\l2t}
a {7*um
%有中间像，焦距输入为正数 @)Vb?|3
hH>a{7V
function sjr=yfdre(~) `>KNa"b%$
A1B[5a*o!
f=input('f:'); Se[=$W
d1=input('d1:'); \`` w>Xy8
d2=input('d2:'); ^0_ >
d3=input('d3:'); ?7CdJgJp
Fi+ DG ?zu
A=f^2/(d3*d2)-f/d1; k:/Z6TLk3
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); (Q `Ps /
C=d3/d2-f/d1; &Pv$nMB$I
0*P -/)o x
a1=(-B-sqrt(B^2-4*A*C))/(2*A); s$f9?(,.Ay
a2=d3/(a1*f); JK{2 hr_a
b2=a1*(1-a2)*f/d2; #bGYH N
b1=(1-a1)*f/(d1*b2); ZiKO|U@/
hUi5~;Q5Fi
%曲率半径 Q!-"5P X
r!{i2I |
R1=2*f/(b1*b2) dXn$XGF%R
R2=2*a1*f/(b2*(1+b1)) v^/<2/E"?4
R3=2*a1*a2*f/(1+b2) 56c3tgVF
{1UU `d
A1=b2^3*(a1-1)*(1+b1)^3; 1A;,"8kBd
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; jl;N
Fk%
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; uUBUUr
; gaTSYVe
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); ]EN&EA"<
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); RigS1A\2l
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); _{LmJ?!
"{S4YA
CB=[C1 B1;C2 B2]; 'q/C: Yo
AB=[A1 B1;A2 B2]; b+Ax Te("
AC=[A1 C1;A2 C2]; *
kL>9
Lo[;{A$ u
%二次系数 8PeVHpZ
=RWY0| f
k2=-(det(CB)/det(AB)); # NK{]H$fd
k3=-(det(AC)/det(AB)); m=pH G
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 tg%<@U`7=
k2=k2 ]t17= Lr?
k3=k3 Ak`?,*L M
l) KN5V
end
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