[求助]用ZEMAX计算光纤的耦合效率 [复制链接]

我用ZEMAX计算光纤的耦合效率，可是我发现当接收光纤的数值孔径增大时耦合效率反而降低了，这是怎么回事呢？

模场分布约接近，耦合效率越高，跟NA无关

我也想知道，同问

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谢谢  学学

能否请问五楼的大侠怎么做到的，谢谢啊~~335797507@qq.com

            

System Efficiency              :      0.999138 @^# 9N!Fj]  
W?N+7_%'  
Receiver Efficiency            :      0.945327 sVnq|[ /  
]A+t@/k  
Coupling Efficiency            :      0.944512 (-0.2479 dB) lA6{TH.x  
vy7?]}MvV  
Maximum Efficiency              :      0.995227 Xrc{wDn  
bz,"TG[  
The system efficiency is the fraction of the energy in the source vUL@i'0&o  
beam that exits the optical system. This value is determined by hp7ni1V  
the input na, entrance pupil size and position, apodization, gC%$)4-:  
transmission of the optics, and vignetting. 23+JuXC6>  
tmeg=U7  
The receiver efficiency is the fraction of the transmitted energy !6#.%"{-  
that couples from the exit pupil to the receiving fiber. This 9Ns%<FRO@  
value is determined by aberrations and the na of the receiving fiber. zT!.5qd  
?}uvpB1}  
The coupling efficiency is the fraction of energy radiated *y+K{ fM1  
by the source that couples into the receiver. This is the ^4[QX -_2  
product of the system and receiver efficiencies. E=bZ4 /  
z>=;Xe8P8n  
The maximum efficiency is the coupling efficiency if there U`{
M1@$  
were no aberrations. *uxKI:rB:  
<P*7u\9&  
数值孔径不是越大越好呀,当耦合光学系统的模式与你光线的模式完全匹配时,耦合效率最大. Ir
- 1@_1Q  
耦合效率的计算有一个积分过程,还是比较复杂的.

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有没有这方面的书籍？